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Chapter 5 The Simplex Method

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How do we represent a feasible extreme point algebraically? Optimality Test: ... Transform the LP problem given in a standard form into a canonical form. ... – PowerPoint PPT presentation

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Title: Chapter 5 The Simplex Method


1
Chapter 5The Simplex Method
The most popular method for solving Linear
Programming Problems We shall present it as an
Algorithm
2
General Structure of Algorithms
Initialise
Check for desired results
Yes
Stop
Iterate
No
Perform a sequence of repetitive steps
3
Construct a feasible extreme point
Is this point optimal ?
Yes
Stop
Iterate
No
Move along an edge to a better extreme point
4
Missing Details
  • Initialisation
  • How do we represent a feasible extreme point
    algebraically?
  • Optimality Test
  • How do we determine whether a given extreme point
    is optimal?
  • Iteration
  • How do we move a long an edge to a better
    adjacent extreme point?

5
5.1 initialisation
  • Transform the LP problem given in a standard form
    into a canonical form.
  • This involves the introduction of slack
    variables, one for each functional constraint.
  • Thus if we start with n variables and m
    functional constraints, we end up with nm
    variables and m functional equality constraints.

6
Standard Form
  • optmax
  • ???
  • bi 0 , for all i.

7
Canonical Form
8
Observation
  • The i-th slack variable measure the distance of
    the point x(x1,...,xn) from the hyperplane
    defining the i-th constraint (This is not a
    Euclidean distance).
  • Thus, if the i-th slack variable is equal to zero
    the point x (x1,...,xn) is on the i-th
    hyperplane. Otherwise it is not.
  • The original variables measure the distance to
    the hyperplanes defining the respective
    non-negativity constraints.

9
Example
x3,x4,x5 are slack variables
10
Why do we do this?
  • If we use the slack variables as a basis, we
    obtain a feasible extreme point !!!

11
5.5.1 Definition
  • A basic feasible solution is a basic solution
    that satisfies the non-negativity constraint.
  • Observation
  • A basic feasible solution is an extreme point of
    the feasible region.
  • Thus
  • Initialisation involves constructing a basic
    feasible solution using the slack varaibles.

12
Example
x3,x4,x5 are slack variables
  • Initial basic feasible solution x
    (0,0,40,30,15), namely
  • x1 0 x2 0 x3 40 x4 30 x5 15

13
Summary of the Initialisation Step
  • Select the slack variables as basic
  • Comments
  • Simple
  • Not necessarily good selection the first basic
    feasible solution can be (very) far from the
    optimal solution.
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