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Organic Chemistry

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Title: Organic Chemistry


1
Organic Chemistry
William H. Brown Christopher S. Foote
2
  • Aromatics I
  • Chapter 20

3
Benzene - Kekulé
  • The first structure for benzene was proposed by
    August Kekulé in 1872
  • This structure, however, did not account for the
    unusual chemical reactivity of benzene

4
Benzene - MO Model
  • The concepts of hybridization of atomic orbitals
    and the theory of resonance, developed in the
    1930s, provided the first adequate description of
    benzenes structure
  • the carbon skeleton is a regular hexagon, with
    all C-C-C and H-C-C bond angles 120

5
Benzene - MO Model
6
Benzene - MO Model
  • Combination of six 2p atomic orbitals gives six
    molecular orbitals
  • three bonding MOs and
  • three antibonding MOs
  • In the ground state, the six pi electrons of
    benzene occupy the three bonding MOs

7
Benzene MO Model
  • the stability of benzene results from the fact
    that these three bonding MOs are much lower in
    energy than the six uncombined 2p atomic orbitals

8
Benzene - Resonance
  • We often represent benzene as a hybrid of two
    equivalent Kekulé structures
  • each makes an equal contribution to the hybrid
    and thus the C-C bonds are neither double nor
    single, but something in between

9
Benzene - Resonance
  • Resonance energy the difference in energy
    between a resonance hybrid and the most stable of
    its hypothetical contributing structures in which
    electrons are localized on particular atoms and
    in particular bonds
  • One way to estimate the resonance energy of
    benzene is to compare the heats of hydrogenation
    of benzene and cyclohexene

10
Benzene
11
Concept of Aromaticity
  • The underlying criteria for aromaticity were
    recognized in the early 1930s by Erich Hückel,
    based on MO calculations
  • To be aromatic, a compound must
  • be cyclic
  • have one p orbital on each atom of the ring
  • be planar or nearly planar so that there is
    continuous or nearly continuous overlap of all p
    orbitals of the ring
  • have a closed loop of (4n 2) pi electrons in
    the cyclic arrangement of p orbitals

12
Frost Circles
  • Inscribe a polygon of the same number of sides as
    the ring to be examined such that one of the
    vertices is at the bottom of the ring
  • The relative energies of the MOs in the ring are
    given by where the vertices touch the circle
  • Those MOs
  • below the horizontal line through the center of
    the ring are bonding MOs
  • on the horizontal line are nonbonding MOs
  • above the horizontal line are antibonding MOs

13
Frost Circles
  • Following are Frost circles describing the MOs
    for monocyclic, planar, fully conjugated four-,
    five-, and six-membered rings

14
Aromatic Hydrocarbons
  • Annulene a cyclic hydrocarbon with a continuous
    alternation of single and double bonds
  • 10Annulene according to Hückels criteria,
    this unsaturated hydrocarbon should be aromatic
  • it is cyclic
  • it has one 2p orbital on each carbon of the ring,
  • it has 4(2) 2 10 pi electrons
  • It is not aromatic, however, because it is not
    planar

15
10Annulene
  • nonbonded interactions between the two hydrogens
    that point inward toward the center of the ring
    force the ring into a nonplanar conformation in
    which overlap of the ten 2p orbitals is no longer
    continuous

16
14Annulene
  • this unsaturated hydrocarbon meets the Hückel
    criteria and is aromatic

17
18Annulene
  • This unsaturated hydrocarbon is also aromatic

18
Antiaromatic Hydrocbn
  • Antiaromatic hydrocarbon a monocyclic, planar,
    fully conjugated hydrocarbon with 4n pi electrons
    (4, 8, 12, 16, 20...)
  • an antiaromatic hydrocarbon is especially
    unstable relative to an open-chain fully
    conjugated hydrocarbon of the same number of
    carbon atoms
  • Cyclobutadiene is antiaromatic. In the
    ground-state electron configuration of this
    molecule,
  • two electrons fill the ?1 bonding MO
  • the remaining two electrons lie in the ?2 and ?3
    nonbonding MOs

19
Cyclobutadiene
  • planar cyclobutadiene has two unpaired electrons,
    which make it highly unstable and reactive

20
Cyclobutadiene
  • cyclobutadiene is trapped within the cage of a
    larger molecule called a hemicarcerand (to rotate
    this molecule, see the accompanying CD)

21
Cyclooctatetraene
  • Planar cyclooctatetraene, if it existed, would be
    antiaromatic it would have two unpaired
    electrons in ?4 and ?5 nonbonding MOs

22
Heterocyclic Aromatics
  • Heterocyclic compound a compound that contains
    more than one kind of atom in a ring
  • in organic chemistry, the term refers to a ring
    with one or more atoms are other than carbon
  • Pyridine and pyrimidine are heterocyclic analogs
    of benzene each is aromatic.

23
Pyridine
  • the nitrogen atom of pyridine is sp2 hybridized
  • the unshared pair of electrons lies in an sp2
    hybrid orbital and is not a part of the six pi
    electrons of the aromatic system
  • pyridine has a resonance energy of 134 kJ (32
    kcal)/mol, slightly less than that of benzene

24
Furan
  • the oxygen atom of furan is sp2 hybridized
  • one unshared pairs of electrons on oxygen lies in
    an unhybridized 2p orbital and is a part of the
    aromatic sextet
  • the other unshared pair lies in an sp2 hybrid
    orbital and is not a part of the aromatic system
  • the resonance energy of furan is 67 kJ (16
    kcal)/mol

25
Other Heterocyclics
26
Aromatic Hydrcbn Ions
  • Any neutral, monocyclic unsaturated hydrocarbon
    with an odd number of carbons must have at least
    one CH2 group and, therefore, cannot be aromatic
  • cyclopropene, for example, has the correct number
    of pi electrons to be aromatic, 4(0) 2 2, but
    does not have a closed loop of 2p orbitals

27
Cyclopropenyl Cation
  • if, however, the CH2 group of cyclopropene is
    transformed into a CH group in which carbon is
    sp2 hybridized and has a vacant 2p orbital, the
    overlap of orbitals is continuous and the cation
    is aromatic

28
Cyclopropenyl Cation
  • When 3-chlorocyclopropene is treated with SbCl5,
    it forms a stable salt
  • this chemical behavior is to be contrasted with
    that of 5-chloro-1,3-cyclopentadiene, which
    cannot be made to form a stable salt

29
Cyclopentadienyl C
  • if planar cyclopentadienyl cation existed, it
    would have 4 pi electrons and be antiaromatic
  • note that we can draw five equivalent
    contributing structures for the cyclopentadienyl
    cation. Yet this cation is not aromatic because
    it has only 4 pi electrons.

30
Cyclopentadienyl Anion
  • To convert cyclopentadiene to an aromatic ion, it
    is necessary to convert the CH2 group to a CH-
    group in which carbon becomes sp2 hybridized and
    has 2 electrons in its unhybridized 2p orbital

31
Cyclopentadienyl Anion
  • The pKa of cyclopentadiene is 16
  • in aqueous NaOH, it is in equilibrium with its
    sodium salt
  • it is converted completely to its anion by very
    strong bases such as NaNH2 , NaH, and LDA

32
Cycloheptatrienyl C
  • Cycloheptatriene forms an aromatic cation by
    conversion of its CH2 group to a CH group with
    its sp2 carbon having a vacant 2p orbital

33
Nomenclature
  • Monosubstituted alkylbenzenes are named as
    derivatives of benzene
  • many common names are retained

34
Nomenclature
  • Benzyl and phenyl groups

35
Disubstituted Benzenes
  • Locate the two groups by numbers or by the
    locators ortho (1,2-), meta (1,3-), and para
    (1,4-)
  • where one group imparts a special name, name the
    compound as a derivative of that molecule

36
Disubstituted Benzenes
  • where neither group imparts a special name,
    locate the groups and list them in alphabetical
    order

37
Polysubstituted Derivs
  • if one group imparts a special name, name the
    molecule as a derivative of that compound
  • if no group imparts a special name, list them in
    alphabetical order, giving them the lowest set of
    numbers

38
NMR Spectroscopy
  • Hydrogens bonded to a benzene ring appear in the
    region ? 6.5 to 8.5
  • Aryl hydrogens absorb further downfield than
    vinylic hydrogens, which is accounted for by an
    induced ring current
  • the induced ring current has an associated
    magnetic field which opposes the applied field in
    the middle of the ring but reinforces it on the
    outside of the ring
  • thus, hydrogens on the benzene ring come into
    resonance at a lower applied field that is, at a
    larger chemical shift than vinylic hydrogens

39
NMR Spectroscopy
  • There are, of course, no hydrogens on the inside
    of a benzene ring. But there are in larger
    annulenes, for example 18annulene

40
Phenols
  • The functional group of a phenol is an -OH group
    bonded to a benzene ring

41
Phenols
  • hexylresorcinol is a mild antiseptic and
    disinfectant
  • eugenol is used as a dental antiseptic and
    analgesic
  • urushiol is the main component of the oil of
    poison ivy

42
Acidity of Phenols
  • Phenols are significantly more acidic than
    alcohols, compounds that also contain the -OH
    group

43
Acidity of Phenols
  • the greater acidity of phenols compared with
    alcohols is due to the greater stability of the
    phenoxide ion relative to an alkoxide ion

44
Acidity of Phenols
  • Alkyl and halogen substituents effect acidities
    by inductive effects
  • alkyl groups are electron-releasing
  • halogens are electron-withdrawing

45
Acidities of Phenols
  • nitro groups increase the acidity of phenols by
    both an electron-withdrawing inductive effect and
    a resonance effect

46
Acidities of Phenols
  • part of the acid-strengthening effect of -NO2 is
    due to its electron-withdrawing inductive effect
  • in addition, -NO2 substituents in the ortho and
    para positions help to delocalize the negative
    charge

47
Acidity of Phenols
  • Phenols are weak acids and react with strong
    bases to form water-soluble salts
  • water-insoluble phenols dissolve in NaOH(aq)

48
Acidity of Phenols
  • most phenols do not react with weak bases such as
    NaHCO3 they do not dissolve in aqueous NaHCO3

49
Alkyl-Aryl Ethers
  • Alkyl-aryl ethers can be prepared by the
    Williamson ether synthesis
  • but only using phenoxide salts and alkyl halides
  • aryl halides are unreactive to SN2 reactions
  • The following two examples illustrate
  • the use of a phase-transfer catalyst
  • the use of dimethyl sulfate as a methylating agent

50
Alkyl-Aryl Ethers
51
Kolbe Carboxylation
  • Phenoxide ions react with carbon dioxide to give
    a carboxylic salt

52
Kolbe Carboxylation
  • the mechanism begins by nucleophilic addition of
    the phenoxide ion to a carbonyl group of CO2

53
Oxidation to Quinones
  • Because of the presence of the electron-donating
    -OH group, phenols are susceptible to oxidation
    by a variety of strong oxidizing agents

54
Oxidation of Phenols
55
Quinones
  • Perhaps the most important chemical property of
    quinones is that they are readily reduced to
    hydroquinones

56
Vitamin K
  • both natural and synthetic vitamin K (menadione)
    are 1,4-naphthoquinones

57
Benzylic Oxidation
  • Benzene is unaffected by strong oxidizing agents
    such as H2CrO4 and KMnO4
  • halogen and nitro substituents are also
    unaffected by these reagents
  • an alkyl group with at least one hydrogen on its
    benzylic carbon is oxidized to a carboxyl group

58
Benzylic Oxidation
  • if there is more than one alkyl group on the
    benzene ring, each is oxidized to a -COOH group

59
Benzylic Chlorination
  • Chlorination (and bromination) is by a radical
    mechanism

60
Benzylic Reactions
  • Benzylic radicals (and cations too) are easily
    formed because of the resonance stabilization of
    these intermediates
  • the benzyl radical is a hybrid of five
    contributing structures

61
Benzylic Halogenation
  • Benzylic bromination is highly regioselective

62
Benzylic Halogenation
  • Benzylic chlorination is also regioselective, but
    less so than benzylic bromination
  • The order of regioselectivity is
  • which parallels BDEs for the formation of radicals

63
Hydrogenolysis
  • Hydrogenolysis cleavage of a single bond by H2
  • among ethers, benzylic ethers are unique in that
    they are cleaved under conditions of catalytic
    hydrogenation

64
Benzyl Ethers
  • The particular value of benzyl ethers is that
    they can serve as protecting groups for the OH
    groups of alcohols and phenols
  • to carry out hydroboration/oxidation of this
    alkene, the phenolic -OH must first be protected
    it is acidic enough to react with BH3 and destroy
    the reagent

65
Benzyl Ethers
  • protect the phenolic -OH, carry out the
    hydroboration/oxidation, and then remove the
    benzyl protecting group by hydrogenolysis

66
Prob 20.15
  • State the number of p orbital electrons in each.

67
Prob 20.23
  • From this spectral data, write a structural
    formula for compound F, C12H16O.

68
Prob 20.24
  • From this spectral data, write a structural
    formula for compound G, C10H10O.

69
Prob 20.29
  • Compound K, C10H12O2, is insoluble in water, 10
    NaOH and 10 HCl. Given this information and the
    following spectral data, propose a structural
    formula for compound K.

70
Prob 20.30
  • Propose a structural formula for each compound.

71
Prob 20.31
  • Each compound shows strong, sharp absorption
    between 1700 and 1720 cm-1, and strong, broad
    absorption over the region 2500-3500 cm-1.

72
Prob 20.35
  • Arrange the entries in each set in order of
    increasing acidity.

73
Prob 20.36
  • Explain the trends in acidity of phenol and the
    monofluoro derivatives of phenol.

74
Prob 20.38
  • From each pair, select the stronger base.

75
Prob 20.39
  • Describe a chemical procedure to separate a
    mixture of these compounds and recover each in
    pure form.

76
Prob 20.46
  • Account for the following order of reactivity
    under SN1 conditions.

77
Prob 20.47
  • Propose a mechanism for this rearrangement.
    Account for the fact that the product is
    2-phenylpropanal rather than its constitutional
    isomer, 1-phenyl-1-propanone.

78
Prob 20.49
  • Synthesize these compounds from ethylbenzene.

79
Prob 20.50
  • Show how to convert 1-phenylpropane to the
    following compounds.

80
Prob 20.51
  • Given this retrosynthetic analysis, propose a
    synthesis for cabinoxamide. Note that aryl
    bromides form Grignard reagents much more readily
    than aryl chlorides.

81
Prob 20.52
  • Propose (1) a mechanism for formation of I, (2)
    a structure for II and a mechanism for its
    formation, and (3) a mechanism for the formation
    of cromolyn sodium.

82
Prob 20.53
  • Describe the chemistry of each step.

83
Prob 20.53 (contd)
  • describe the chemistry of each step

84
  • Aromatics I

End of Chapter 20
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