Political Science 5: Example of ChiSquared Test - PowerPoint PPT Presentation

1 / 14
About This Presentation
Title:

Political Science 5: Example of ChiSquared Test

Description:

... there is no relationship between race/ethnicity and admissions. Chi-Square ... Race ... Race and Admissions. Let's examine the bivariate correlation between ... – PowerPoint PPT presentation

Number of Views:44
Avg rating:3.0/5.0
Slides: 15
Provided by: thadko4
Category:

less

Transcript and Presenter's Notes

Title: Political Science 5: Example of ChiSquared Test


1
Political Science 5Example of Chi-Squared Test
2
How Sure is Sure? Quantifying Uncertainty in
Tables
  • Using Two-Way Tables
  • SAT scores and UC admissions
  • Null hypothesis there is no relationship between
    race/ethnicity and admissions
  • Chi-Square Test
  • The formula
  • Interpreting your results
  • Using a Chi-Square test to hold constant a
    confound or another independent variable

3
Race and Admissions
  • A recent study of UC admissions over the past two
    years showed that thousands of students with SATs
    under 1000 have been admitted.
  • Even flagships like UCSD, UCLA and Berkeley
    admitted hundreds.
  • Many observers offered this hypothesis to explain
    the trend Minority students with low SATs are
    more likely to be admitted.

4
Race and Admissions
  • Lets examine the bivariate correlation between
    ethnicity and admittance.

Data on UC applicants who scored lower than 1000
on the SAT, taken from the Los Angeles Times,
November 3, 2003.
5
Race and Admissions
  • If the ethnicity of a student with sub-1000 SAT
    scores makes him more likely to be admitted to
    the UC, admission rates in that table will differ
    by race.
  • 62.9 for underrepresented minorities
  • 63.4 for whites and Asian-Americans
  • Opposite of what the hypothesis predicted!

6
Test of Statistical Significance
  • We still want to see if this small difference in
    our sample is statistically significant at the
    95 confidence level.
  • We could do a difference in proportions test.
  • We will do a Chi-Square test, a nice option when
    we have more than two groups.
  • The null hypothesis is that there is no
    association between ethnicity and UC admission
    rates for these students.

7
Chi-Square Test
  • Under the null hypothesis, you would expect to
    see table entries that indicate the same
    admission rates for each ethnicity.
  • To calculate the expected count in any cell of a
    two-way table when the null hypothesis is true

8
Chi-Square Test
  • For the Row 1, Column 1 entry in our UC
    admission table, which gives the number of
    underrepresented minorities who are admitted,
    this expected count is

9
Chi-Square Test
  • To conduct a Chi-Square test, first fill in a
    tables worth of expected counts

10
Chi-Square Test
  • Then use this formula to get a single Chi-Square
    statistic, which is a measure of how much the
    observed counts differ from the expected counts,
    for your table

11
Chi-Square Test
  • So for each entry
  • Step 1. Subtract the expected count from the
    observed count.
  • Step 2. Square that difference.
  • Step 3. Divide that square by the expected count
    to get a quotient.
  • Then add up your quotients for all of the cells.

12
Chi-Square Test
  • When the null hypothesis is true, the resulting
    Chi-Square statistic has a sampling distribution
    called the chi-square distribution,
    characterized by its degrees of freedom, which
    equals
  • df ( of rows - 1) ( of columns - 1)
  • Our UC admissions table has 1 degree of freedom
  • (2-1) (2-1) 1 1 1

13
Chi-Square Test
  • We can reject the null hypothesis at the 95
    confidence level if our Chi-Square statistic is
    greater than the values given by this table for
    each number of degrees of freedom.
  • Chi-Square is 0.76 in UC example, so cannot reject

14
Chi-Square Test
  • If you have a confound, like Did the students
    parent attend UC?, you can use the Chi-Square
    test to see if there is a relationship between
    ethnicity and admission, holding confound
    constant
  • Build one 2X2 table for students who parents
    attended a UC, and another 2X2 table for students
    with no legacy
  • Conduct two separate Chi-Square tests to examine
    bivariate relationship for each group.
Write a Comment
User Comments (0)
About PowerShow.com