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200809 NSERC Undergraduate Student Research Awards USRA

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Calculate the mole fraction of O2 present in the output gas stream. ... assuming that the mole fraction of A equals xA at quilibrium, then xB = 1.0 xA, ... – PowerPoint PPT presentation

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Title: 200809 NSERC Undergraduate Student Research Awards USRA


1
  • 2008-09 NSERC Undergraduate Student Research
    Awards (USRA)
  • Department deadline is Friday, February 1, 2008
  • In addition to the research experience, you will
    earn 4500.00 for 16 weeks at least 1,125.00
    from your professor.
  • Students must have obtained a cumulative GPA of
    at least 8.0 or B- up to the time of application

2
59-241 Labs
  • Find your lab partner within the next few days.
  • TAs will be in the classroom next Tuesday to sign
    you up and may also tell you which experiment you
    will start with
  • Tutorial time is now posted on the website.

3
Expressions of the equilibrium constant K
  • The equilibrium constant, K, (a dimensionless
    quantity) can be expressed in terms of fugacities
    for gas phase reactions or activities for aqueous
    phase reactions.
  • Fugacity ( a dimensionless quantity) is equal to
    the numerical value of partial pressure, i.e.
    pj/p? where p? 1 bar).
  • The activity, a, is equal to the numerical value
    of the molality, i.e. bj/b? where b? 1 mol kg-1.

4
For reactions occurring in electrolyte solutions
  • Effects of the interactions of ions on the
    reaction process should be considered.
  • Such a factor can be expressed with the activity
    coefficient, ?, which denotes distance from the
    ideal system where there is no ion-interaction.
  • The activity shall now be calculated as aj
    ?jbj/b?
  • For a reaction A B ? C D
  • K

5
The activities of solids are equal to 1
  • a(solid) 1 (!!!)
  • Illustration Express the equilibrium constant
    for the heterogeneous reaction
  • NH4Cl(s) ? NH3(g) HCl(g)
  • Solution
  • In term of fugacity (i.e. partial
    pressure) Kp
  • In term of molar fraction Kx

6
Estimate reaction compositions at equilibrium
  • Example 1 Given the standard Gibbs energy of
    reaction H2O(g) ? H2(g) 1/2O2(g) at 2000K is
    135.2 kJ mol-1, suppose that steam at 200k pa is
    passed through a furnace tube at that
    temperature. Calculate the mole fraction of O2
    present in the output gas stream.
  • Solution (details will be discussed in class)
  • lnK - (135.2 x 103 J
    mol-1)/(8.3145 JK-1mol-1 x 2000K)
  • - 8.13037
  • K 2.9446x10-4
  • K
  • Ptotal 200Kpa
  • assuming the mole fraction of
    O2 equals x
  • PO2 x Ptotal,
  • PH2 2(xPtotal)
  • PH2O Ptotal PO2 PH2
    (1-3x)Ptotal

7
Equilibria in biological systems
  • Biological standard state pH 7.
  • For a reaction A vH(aq) ? P
  • ?rG ?rG? RT
  • ?rG? RT
  • the first two terms of the above eq. form ?rG
  • ?rG ?rG? 7vRTln10

8
Example For a particular reaction of the form A
? B 2H in aqueous solution, it was found
that ?rG? 20kJ mol-1 at 28oC. Estimate the
value of ?rG.
  • Solution ?rG ?rG? 7vRTln10
  • here v - 2 !!!
  • ?rG 20 kJ mol-1 7(-2)(8.3145x10-3 kJ
    K-1mol-1)
  • x(273 28K)ln10
  • 20 kJ mol-1 80.676 kJ mol-1
  • -61 kJ mol-1
  • (Note that when measured with the biological
    standard, the standard reaction Gibbs energy
    becomes negative!)

9
Molecular Interpretation of equilibrium
10
The response of equilibria to reaction conditions
  • Equilibria respond to changes in pressure,
    temperature, and concentrations of reactants and
    products.
  • The equilibrium constant is not affected by the
    presence of a catalyst.

11
How equilibria respond to pressure
  • Equilibrium constant K is a function of the
    standard reaction Gibbs energy, ?rG? .
  • Standard reaction Gibbs energy ?rG? is defined at
    a single standard pressure and thus is
    independent of pressure.
  • The equilibrium constant is therefore independent
    of pressure

12
  • K is independent of pressure does NOT mean that
    the equilibrium composition is independent of the
    pressure!!!
  • consider the reaction 2A(g) ? B(g)
  • assuming that the mole fraction of A
    equals xA at quilibrium, then xB 1.0 xA,
  • K
  • because K does not change, xA must
    change in response to any variation in Ptotal!!!

13
Le Chateliers Principle
  • A system at equilibrium, when subject to a
    disturbance, responds in a way that tends to
    minimize the effect of the disturbance.

14
Example Predict the effect of an increase in
pressure on the Haber reaction, 3H2(g) N2(g)
? 2NH3(g).
  • Solution
  • According to Le Chateliers
    Principle, an increase in pressure will favor the
    product.
  • prove K
  • Therefore, to keep K unchanged, the
    equilibrium mole fractions Kx will change by a
    factor of 4 if doubling the pressure ptotal.

15
The response of equilibria to temperature
  • According to Le Chateliers Principle
  • Exothermic reactions increased
    temperature favors the reactants.
  • Endothermic reactions increased
    temperature favors the products.
  • The vant Hoff equation
  • (a)
    (7.23a)
  • (b)
    (7.23b)

16
Derivation of the vant Hoff equation
  • Differentiate lnK with respect to temperature
  • Using Gibbs-Helmholtz equation (eqn 3.53 8th
    edition)
  • thus
  • Because d(1/T)/dT -1/T2

17
  • For an exothermic reaction, ?rH? lt 0, thus
    , suggesting that increasing the
    reaction temperature will reduce the equilibrium
    constant.
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