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Chapter 23. Gauss

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Chapter 23. Gauss Law 23.1. What is Physics? 23.2. Flux 23.3. Flux of an Electric Field 23.4. Gauss' Law 23.5. – PowerPoint PPT presentation

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Title: Chapter 23. Gauss


1
Chapter 23. Gauss Law
  • 23.1. What is Physics?      
  • 23.2. Flux      
  • 23.3. Flux of an Electric Field      
  • 23.4. Gauss' Law      
  • 23.5. Gauss' Law and Coulomb's Law      
  • 23.6. A Charged Isolated Conductor     
  • 23.7. Applying Gauss' Law Cylindrical
    Symmetry      
  • 23.8. Applying Gauss' Law Planar Symmetry     
  • 23.9. Applying Gauss' Law Spherical Symmetry

2
What is Physics?
  • Gaussian surface is a hypothetical (any imaginary
    shape) closed surface enclosing the charge
    distribution.
  • Gauss' law relates the electric fields at points
    on a (closed) Gaussian surface to the net charge
    enclosed by that surface.



                                                                                                
3
Gaussian surface
  • Let us divide the surface into small squares
    of area ?A, each square being small enough to
    permit us to neglect any curvature and to
    consider the individual square to be flat. We
    represent each such element of area with an area
    vector
  • Magnitude is the area ?A.
  • Direstion is perpendicular to the Gaussian
    surface and directed away from the interior of
    the surface.



                                                                                                              
4
Flux
  • The rate of volume flow through the loop is

5
Flux of an Electric Field
  • The electric field for a surface is
  • The electric field for a gaussian surface is

The electric flux F through a Gaussian surface is
proportional to the net number of electric field
lines passing through that surface.
SI Unit of Electric Flux Nm2/C
6
Problem 1
  • The drawing shows an edge-on view of two planar
    surfaces that intersect and are mutually
    perpendicular. Surface 1 has an area of 1.7 m2,
    while surface 2 has an area of 3.2 m2. The
    electric field E in the drawing is uniform and
    has a magnitude of 250 N/C. Find the electric
    flux through (a) surface 1 and (b) surface 2.

7
Sample Problem 2
  • Figure 23-4 shows a Gaussian surface in the
    form of a cylinder of radius R immersed in a
    uniform electric field E , with the cylinder axis
    parallel to the field. What is the flux F of the
    electric field through this closed surface?

                                                                                                                                            

8
Sample Problem 3
  • A nonuniform electric field given by
    pierces the Gaussian cube shown in Fig. (E
    is in newtons per coulomb and x is in meters.)
    What is the electric flux through the right face,
    the left face, the top face, and the Gaussian
    surface?

                                                                                                                              

9
Gauss Law
  • For a point charge

10
Gauss Law
  • For charge distribution Q

The electric flux through a Gaussian surface
times by e0 ( the permittivity of free space) is
equal to the net charge Q enclosed
  • The net charge qenc    is the algebraic sum of
    all the enclosed charges.
  • Charge outside the surface, no matter how large
    or how close it may be, is not included in the
    term qenc.

11
Check Your Understanding
  • The drawing shows an arrangement of three
    charges. In parts (a) and (b) different Gaussian
    surfaces are shown. Through which surface, if
    either, does the greater electric flux pass?

12
Sample Problem
  • Figure 23-7 shows five charged lumps of
    plastic and an electrically neutral coin. The
    cross section of a Gaussian surface S is
    indicated. What is the net electric flux through
    the surface if q1q43.1 nC, q2q5-5.9 nC, and
    q3-3.1 nC?

                                                                                                           

13
A Charged Isolated Conductor
  • If an excess charge is placed on an isolated
    conductor, that amount of charge will move
    entirely to the surface of the conductor. None of
    the excess charge will be found within the body
    of the conductor.
  • For an Isolated Conductor with a Cavity, There is
    no net charge on the cavity walls all the excess
    charge remains on the outer surface of the
    conductor





                                                                                  
14
The External Electric Field of a Conductor
If s is the charge per unit area,
                                                                                          
  • according to Gauss' law,

15
Sample Problem
  • Figure 23-11a shows a cross section of a
    spherical metal shell of inner radius R. A point
    charge of q is located at a distance R/2 from
    the center of the shell. If the shell is
    electrically neutral, what are the (induced)
    charges on its inner and outer surfaces? Are
    those charges uniformly distributed? What is the
    field pattern inside and outside the shell?

                                                                                                                                                                          

16
Applying Gauss' Law Cylindrical Symmetry
Figure 23-12 shows a section of an infinitely
long cylindrical plastic rod with a uniform
positive linear charge density ?.


                                                                                      

17
Applying Gauss' Law Planar Symmetry
  • Figure 23-15 shows a portion of a thin,
    infinite, nonconducting sheet with a uniform
    (positive) surface charge density s

18
Applying Gauss' Law Spherical Symmetry
  • A shell of uniform charge attracts or repels a
    charged particle that is outside the shell as if
    all the shell's charge were concentrated at the
    center of the shell.
  • If a charged particle is located inside a shell
    of uniform charge, there is no electrostatic
    force on the particle from the shell.

                                                                                          

19
  • Any spherically symmetric charge distribution
    with the volume charge density ?
  • For rgtR, the charge produces an electric field on
    the Gaussian surface as if the charge were a
    point charge located at the center,
  • For rltR, the electric field is

20
Checkpoint
  • The figure shows two large, parallel,
    nonconducting sheets with identical (positive)
    uniform surface charge densities, and a sphere
    with a uniform (positive) volume charge density.
    Rank the four numbered points according to the
    magnitude of the net electric field there,
    greatest first.

    
                                                                                                                                                      

21
Conceptual Questions
  1. Two charges, q and q, are inside a Gaussian
    surface. Since the net charge inside the Gaussian
    surface is zero, Gauss law states that the
    electric flux through the surface is also zero
    that is F0. Does the fact that F 0 imply that
    the electric field E at any point on the Gaussian
    surface is also zero? Justify your answer.
  2. The drawing shows three charges, labeled q1, q2,
    and q3. A Gaussian surface is drawn around q1 and
    q2. (a) Which charges determine the electric flux
    through the Gaussian surface? (b) Which charges
    produce the electric field at the point P?
    Justify your answers.

22
  • (3) A charge q is placed inside a spherical
    Gaussian surface. The charge is not located at
    the center of the sphere. (a) Can Gauss law tell
    us exactly where the charge is located inside the
    sphere? Justify your answer. (b) Can Gauss law
    tell us about the magnitude of the electric flux
    through the Gaussian surface? Why?
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