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ME 201 Engineering Mechanics: Statics

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Thus far we've been working with loads that are concentrated at a point: ... W=60x2 N/m. 2 m. Example Problem Solution. Given: trapezoid. Find: FR, W=60x2 N/m. 2 m ... – PowerPoint PPT presentation

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Title: ME 201 Engineering Mechanics: Statics


1
ME 201Engineering Mechanics Statics
  • Chapter 4 Part D
  • 4.10 Distributed Loading

2
Distributed Loads
  • Thus far weve been working with loads that are
    concentrated at a point
  • Many times in engineering we need to be concerned
    with another type of loading referred to as
    distributed loading

3
Distributed Loads
  • To compute the resultant, FR, of a distributed
    load, consider the following
  • To find FR, we need to sum an infinite number of
    small forces

4
Distributed Loads
  • Consider a small differential element, dF, with a
    width of dx and a height of w(x)
  • The area of the element is
  • Since infinite number of forces, need to integrate

5
Distributed Loads
  • Where does FR act?
  • Can be determined by equating the moments of the
    force resultant and the force distribution

This is also the centroid of the area
6
Centroids
  • For simple shapes, centroid can be found in a
    table (see back cover of textbook)
  • Where is the centroid for these common shapes?

7
Example Problem
  • Given
  • w400 lb/ft
  • Find
  • FR,

w lb/ft
A
B
10 ft
8
Example Problem Solution
w lb/ft
  • Given
  • w400 lb/ft
  • Find
  • FR,

A
B
10 ft
9
Example Problem
  • Given
  • w100x N/m
  • Find
  • FR,

600 N/m
A
B
6 m
10
Example Problem Solution
600 N/m
  • Given
  • w100x N/m
  • Find
  • FR,

A
B
6 m
11
Example Problem
100 lb/ft
  • Given
  • trapezoid
  • Find
  • FR,

50 lb/ft
A
B
9 ft
12
Example Problem Solution
100 lb/ft
  • Given
  • trapezoid
  • Find
  • FR,

50 lb/ft
A
B
9 ft
13
Example Problem
  • Given
  • trapezoid
  • Find
  • FR,

W60x2 N/m
2 m
14
Example Problem Solution
  • Given
  • trapezoid
  • Find
  • FR,
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