Equilibrium and Radioactivity - PowerPoint PPT Presentation

1 / 90
About This Presentation
Title:

Equilibrium and Radioactivity

Description:

Equilibrium and Radioactivity From there to here, from here to there, funny things are everywhere--TSG 1957 – PowerPoint PPT presentation

Number of Views:127
Avg rating:3.0/5.0
Slides: 91
Provided by: Nicho122
Category:

less

Transcript and Presenter's Notes

Title: Equilibrium and Radioactivity


1
Equilibrium and Radioactivity
  • From there to here, from here to there, funny
    things are everywhere
  • --TSG 1957

2
The rate of a reaction
  • Expressed in mol/sec or M/s

3
N2 3H2?2NH3
  • If 2.40 moles of NH3 are produced each second,
    what is the rate of use of N2 and H2?

4
N2 3H2?2NH3
  • If 2.40 moles of NH3 are produced each second,
    what is the rate of use of N2 and H2?
  • 2.40 mol NH3/s x 1 N2/2 NH3
  • 1.20 mol N2/s
  • 2.40 mol NH3/s x 3 H2/2 NH3
  • 3.60 mol H2/s

5
How can you speed up a reaction?
6
How can you speed up a reaction?
  • --Heat it up.
  • --Crush, grind or powder a solid reactant.
  • --Increase pressure of a gaseous reactant
  • --Increase concentrations of aqueous reactants
  • --Add a catalyst (if known)
  • (Stir or shake to bring reactants together.)

7
How would you speed up
  • Hydrochloric acid acts on tin metal to form
    hydrogen gas and aqueous tin (II) chloride

8
How would you speed up
  • Hydrochloric acid acts on tin metal to form
    hydrogen gas and aqueous tin (II) chloride
  • Increase concentration of HCl
  • Powder the tin
  • Heat the reactants
  • Stir or shake
  • (I dont know of a catalystits pretty fast
    already)

9
Reversible reactions.
  • AKA all reactions
  • All reactions work in reverse, at least a little
    bit.

should be written as
10
Write the reverse reaction
  • 2NaHCO3 (s) ?Na2CO3 (s) H2O (g)
  • CaCO3 (s) ?CaO (s) CO2 (g)
  • H2 (g) Cl2 (g) ?2HCl (g)
  • N2 (g) 3H2 (g) ?2NH3 (g)

11
H2 I2 2HI
1 mole H2 and 1 mole I2 (1L)
If you start with 1 mole H2 and 1 mole I2 in a 1L
flask
12
H2 I2 2HI
1 mole H2 and 1 mole I2 (1L)
.8 mole H2 .8 mole I2 and .4 mole HI (1L)
it will proceed forwards. Some of the reactants
will form products.
13
H2 I2 2HI
2 mole HI (1L)
If you start with 2 moles HI in a 1L flask
14
H2 I2 2HI
2 mole HI (1L)
.8 mole H2 .8 mole I2 and .4 mole HI (1L)
it will proceed in reverse. Some of the
products will form reactants
15
H2 I2 2HI
1 mole H2 and 1 mole I2 (1L)
2 mole HI (1L)
.8 mole H2 .8 mole I2 and .4 mole HI (1L)
Did you notice?
16
H2 I2 2HI
1 mole H2 and 1 mole I2 (1L)
2 mole HI (1L)
.8 mole H2 .8 mole I2 and .4 mole HI (1L)
You get the same final concentrations
17
Starting with reactants
Rate of reaction (mol/s)
Time (s)
The forward reaction starts out fast, then slows
as reactants are used up
18
Starting with reactants
Rate of reaction (mol/s)
Time (s)
The reverse reaction starts out at 0 mol/s, then
speeds up as products are produced
19
Starting with reactants
Rate of reaction (mol/s)
Time (s)
Did you notice?
20
Starting with reactants
Rate of reaction (mol/s)
Time (s)
The forward and reverse reactions reach the same
rate. Concentrations will stabilize
21
Eventually
  • reactants make products just as fast as products
    make reactants.

22
Eventually
  • reactants make products just as fast as products
    make reactants.
  • Its inevitable.

23
Eventually
  • reactants make products just as fast as products
    make reactants.
  • Its inevitable.
  • Its dynamic equilibrium

24
That's EQUILIBRIUM!
25
Try it.
  • N2 3H2 2NH3
  • Describe the rate of the forward reaction if you
    start with nitrogen and hydrogen.
  • What is the rate of the reverse reaction?
  • What happens to each rate?
  • Why?
  • Eventually

26
The equilibrium constant expression
  • For aA bB?? cC dD
  • (if all substances are gasses or aqueous)
  • The expression
  • Cc Dd
  • Aa Bb is a constant (K) at a given
    temperature

27
Please note
  • Products on top
  • Coefficients become exponents
  • Brackets mean molarity
  • Concentrations are multiplied
  • Solid and liquid substances are not included
  • then this ratio is a constant!

28
For example
  • For H2(g) I2 (g)??2HI (g)
  • The equilibrium constant expression is
  • K HI2 (.4M)2 .25
  • H2I2 (.8M)(.8M)

29
Write the equilibrium constant expression for
  1. 4NH3(g)5O2(g)??4NO(g)6H2O(g)
  2. CO (g) 2H2 (g) ??CH3OH (g)
  3. NH3(g)H2O (l) ?? NH4 (aq) OH-(aq)

30
Rookie mistakes
  • --putting reactants on top
  • --using coefficients inside the brackets
  • --adding instead of multiplying concentrations
  • --multiplying by coefficients, instead of raising
    to the power
  • --including liquids and solids.
  • Avoid these errors!

31
What is the value of K?
  • 4NH3(g)5O2(g)??4NO(g)6H2O(g)
  • .050 M .30 M .20 M .40 M
  • 2) CO (g) 2H2 (g) ??CH3OH (g)
  • .20 M .20 M .030 M
  • 3) NH3(g)H2O (l) ?? NH4 (aq) OH-(aq)
  • .10 M 55.5 M .0013 M .0013 M

32
What is the unknown concentration?
  • 4NH3(g)5O2(g)??4NO(g)6H2O(g)
  • .060 M .40 M .15 M ? M
  • 2) CO (g) 2H2 (g) ??CH3OH (g)
  • ? M .25 M .070 M
  • 3) NH3(g)H2O (l) ?? NH4 (aq) OH-(aq)
  • ? M 55.5 M .0019 M .00030M

33
Le Chateliers Principle
  • If a system in equilibrium is subjected to a
    stress, the system will shift in the direction
    that will relieve that stress

34
Application of LeChateliers principle
  • Shift right
  • --forward reaction is faster,
  • --more of all products are formed
  • --all reactants are used
  • Shift left
  • --reverse reaction is faster,
  • --more of all reactants are formed
  • --all products are used

35
Application of LeChateliers principle
  • An aqueous or gas substance in the reaction
    addedshift away to use it up
  • Increasing pressureshift toward side with fewer
    moles of gas to relieve pressure
  • Increasing temperatureshift in the endothermic
    direction to absorb heat

36
N2(g) 3H2(g) 2NH3(g) D Which way would
the equilibrium shift if you
  1. Add N2(g)
  2. Add H2(g)
  3. Add NH3(g)
  4. Increase P (compress)
  5. Increase T
  6. Add a catalyst
  7. Remove N2(g)
  • 7. Remove H2(g)
  • 8. Remove NH3(g)
  • 9. Decrease P (allow to expand)
  • 10. Decrease T
  • 11. Increase pressure by adding He (g)

37
N2(g) 3H2(g) 2NH3(g) D Which way would
the equilibrium shift if you
  1. Add N2(g)
  2. Add H2(g)
  3. Add NH3(g)
  4. Increase P (compress)
  5. Increase T
  6. Add a catalyst
  7. Remove N2(g)
  • 7. Remove H2(g)
  • 8. Remove NH3(g)
  • 9. Decrease P (allow to expand)
  • 10. Decrease T
  • 11. Increase pressure by adding He (g)

38
N2(g) 3H2(g) 2NH3(g) D Why?
Forward reaction speeds up
  1. Add N2(g)
  2. Add H2(g)
  3. Add NH3(g)
  4. Increase P (compress)
  5. Increase T
  6. Add a catalyst
  7. Remove N2(g)
  • 7. Remove H2(g)
  • 8. Remove NH3(g)
  • 9. Decrease P (allow to expand)
  • 10. Decrease T
  • 11. Increase pressure by adding He (g)

Reverse reaction slows down
39
How would you shift this reaction to the left?
  • HCOOH (aq) D??HCOO- (aq) H (aq)
  • (formic (heat) (formate (hydrogen
  • acid) ion)
    ion)

40
Why do reactions proceed at all?
41
Why do reactions proceed at all?
  • To go to a more stable, lower energy state.
  • 1) If DH is (-), reaction gives off heat. (DHlt0)
  • OR
  • 2) an advantage in gaining entropy, S. (DSgt0)
  • OR BOTH!

42
Enthalpy and Entropy
  • DH
  • Endo- or exothermic
  • Energy is stored in/released from chemical bonds
  • Measured in kJ/mol
  • DS
  • Gains or loses entropy
  • A system becomes more or less disordered
    (sltlltaqltltg)
  • Measured in J/ mol k

43
2H2 O2?2H2O
44
2H2 O2?2H2O
  • DH is very negativeit gives up a lot of heat.
  • 2H2 O2?2H2O D

Releasing heat is an advantage for a reaction
45
2H2 O2?2H2O
  • DS is also negativeit loses entropy as 3 moles
    of gasses form only 2 moles.
  • This is a disadvantage, its worse at higher
    temperatures. Over 5000oC, hydrogen gas wont
    even burn.

The advantage for entropy depends on temperature
46
What is DH, DS and DG?
  • D CaCO3 (s) ?CaO (s) CO2 (g)
  • H2 (g) Cl2 (g) ?2HCl (g) D
  • N2 (g) 3H2 (g) ?2NH3 (g) D

47
  • What happens at a higher temperature?

48
at a higher temperature
  • 1) Particles move faster.
  • 2) There are more collisions.
  • 3) Those collisions have more energy.

49
To react, reactants must collide with enough
energy, the activation energy.
50
Cool, medium, warm
51
Notice
  1. The bell-shaped distributions
  2. The average speed is higher at higher To
  3. The speeds spread out more at higher To

52
What is fast enough to react?
  • More collisions will have enough energy to react
    at higher temperatures

53
What if this is fast enough?
54
What if this is fast enough?
55
To react, reactants must collide with enough
energy, the activation energy.
56
Catalysis
  • A catalyst speeds up a reaction
  • This is done by lowering the energy barrier, Ea
  • When the barrier is lower, more collisions are
    fast enough

57
(No Transcript)
58
Nuclear Chemistry--
--as opposed the the unclear chemistry you have
studied
59
Nuclear Chemistry
  • --breaks the rules that one atom cannot be
    converted to another.
  • Chemistry the dance of the electrons
  • nuclear reactions change the nuclei of atoms
  • --charge and mass are still conserved.

60
Nuclide Notation
  • A nuclide is a nucleus or atom of a specific
    isotope of an element

K
39
19
  • Potassium-39.
  • -- has 19 protons (atomic number 19), making it
    potassium, and 20 neutrons (making a mass number
    of 39)

61
How many p, n, e- in each?What is the mass
number and atomic number?
Cl-
36
I-
131
H
3
17
53
1
Sr2
90
Th
228
Fe3
59
38
90
26
62
How many p, n, e- in each?What is the mass
number and atomic number?
undergoes a b decay
Cl-
36
I-
131
H
3
17
53
1
Sr2
90
Th
228
Fe3
59
38
90
26
undergoes an a decay
63
Natural decays
  • athe loss of a particle from a nuclide
  • --The a particle is composed of 2p and 2n, the
    4He nucleus
  • --decreases the mass by 4 and the atomic number
    by 2
  • bemission of an electron (b particle) from the
    nucleus by the conversion of a n ? p e-
  • --the electron is the b particle
  • --increases the atomic number by 1, does not
    affect mass

64
Write the reaction
  • Argon-39 undergoes a b decay
  • Thorium-228 undergoes an a decay
  • An a decay forms lead-204
  • A b decay forms nitrogen-14
  • A natural decay forms Sc-45 from Ca-45
  • A natural decay forms Ac-227 from Pa-231

65
Stable?
66
Nuclear reactions
  • Many nuclear reactions involve colliding nuclei
    or smaller particles at some significant fraction
    of the speed of light,
  • --find the missing particle by balancing mass and
    charge.

67
Fission vs Fusion
  • Fissionbreaking up large nuclei
  • --natural radioactive decay of large atoms
  • --used for nuclear power
  • Fusioncombining small nuclei
  • --occurs naturally in stars
  • --prospects for nuclear energyno radioactive
    byproducts
  • Both are transmutationsone nuclide is converted
    into another

68
Consider the relationships
  • Half life
  • Original amount
  • Final amount
  • Time elapsed

69
Consider the relationships
  • AA0(1/2)
  • A is the amount of the sample remaining
  • A0 is the original amount in the sample
  • t is the time that has passed, and
  • t 1/2 is the half-life of the nuclide

t/t1/2
70
Please notice
  • AA0(1/2)
  • A / A0 the fraction remaining and
  • t / t 1/2the number of half-lifes that have
    passed

t/t1/2
71
Try it.
  • Hydrogen-3 has a half life of 12.3 years. If you
    start with a 20 g sample of H-3
  • --how much is left after 12.3 years?
  • --how much is left after 24.6 years?
  • --how much is left after 30.2 years?

72
Try it.
  • Br-82 has a half life of 35.3 hours. If you
    start with a 6.5 mg sample of Br-82
  • --how much is left after 4 days?
  • --how long will it take to reach .75 mg?

73
Try it.
  • Br-82 has a half life of 35.3 hours. If you
    start with a 6.5 mg sample of Br-82
  • --how much is left after 4 days?
  • --how long will it take to reach .75 mg?

How do you solve for an exponent?
74
Use a log function
  • log (A/A0) log(1/2)
  • log (A/A0) log(1/2)
  • log (A/A0)
  • log(1/2)

t/t1/2
t/t1/2
t/t1/2
75
Try it.
  • Br-82 has a half life of 35.3 hours. If you
    start with a 6.5 mg sample of Br-82
  • --how much is left after 4 days?
  • --how long will it take to reach .75 mg?

76
Try it.
  • If you start with 1.38 mg of U-234 and t1/22.44
    x 105 yrs for its decay
  • --how much is left after 20,000 years?
  • --how long will it take to reach 0.40 mg?

77
Try it.
  • A .350 mg sample of K-42 decays to only .066 mg
    in 29.7 hours.
  • --what is the half life?
  • --how much was left after 20.0 hours?
  • --how long will it take to reach .010 mg?

78
The uses of radioactivity
79
The uses of radioactivity
  • Medicinetracers, radiation therapy
  • History/geologyradioisotope dating
  • Nuclear energy
  • Nuclear weapons

80
The uses of radioactivity
  • Medicine
  • Tracers
  • I-131, S-35, F-18, P-32
  • Radiation therapy
  • I-131, Lu-177, Y-90, Sr-89

81
The uses of radioactivity
  • History/geologyradioisotope dating
  • C-14, U-238, Sm-147, K-40

82
The uses of radioactivity
  • Nuclear Energy
  • Nuclear reactions give off a large amount of
    energy
  • This energy is often converted to electricity
  • A nuclear reactor contains the reactants so the
    by-products (usually neutrons) carry out the
    chain reaction

83
Pressurized water reactor
84
Boiling water reactor
85
Heavy water reactor
86
Gas-cooled reactor
87
Hydride salt reactor
88
Pebble bed modular reactor
89
(No Transcript)
90
NERVA
Write a Comment
User Comments (0)
About PowerShow.com