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5-2 Medians and Altitudes of Triangles

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5-2 Medians and Altitudes of Triangles You identified and used perpendicular and angle bisectors in triangles. Identify and use medians in triangles. – PowerPoint PPT presentation

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Title: 5-2 Medians and Altitudes of Triangles


1
5-2 Medians and Altitudes of Triangles
You identified and used perpendicular and angle
bisectors in triangles.
  • Identify and use medians in triangles.
  • Identify and use altitudes in triangles.

2
Median
  • A median of a triangle is a segment whose
    endpoints are a vertex and the midpoint of the
    opposite side.
  • (Goes from vertex to opposite side)

Median
3
  • Every triangle has three medians that are
    concurrent.
  • The point of concurrency of the medians of a
    triangle is called the centroid and is always
    inside the triangle.

Page 335
4
Balancing Act
  • Balance your triangle on the eraser end of your
    pencil. Mark the point. This is the centroid of
    the triangle.
  • Fold your triangle to find the midpoint of each
    side of your triangle Connect each vertex to the
    midpoint of the opposite side.
  • Do all three line segments meet at one point?

5
Centroid
  • The point of concurrency of the medians of any
    triangle is called the centroid.
  • The centroid is the center of balance (or center
    of gravity) of the triangle.

Centroid
6
In ?XYZ, P is the centroid and YV 12. Find YP
and PV.
Centroid Theorem
YV 12
Simplify.
YP PV YV Segment Addition 8 PV 12 YP
8 PV 4 Subtract 8 from each side.
Answer YP 8 PV 4
 
7
In ?LNP, R is the centroid and LO 30. Find LR
and RO.
A. LR 15 RO 15 B. LR 20 RO 10 C. LR
17 RO 13 D. LR 18 RO 12
8
In ?JLN, JP 16. Find PM.
A. 4 B. 6 C. 16 D. 8
 
9
Altitude (height)
  • An altitude of a triangle is a perpendicular
    segment drawn from a vertex to the line that
    contains the opposite side.
  • (Vertex to opposite side at a right angle.)

Altitude
10
  • Every triangle has three altitudes. If extended,
    the latitudes of a triangle intersect in a common
    point called the orthocenter.

Page 337
11
COORDINATE GEOMETRY The vertices of ?HIJ are
H(1, 2), I(3, 3), and J(5, 1). Find the
coordinates of the orthocenter of ?HIJ.
Point-slope form
Distributive Property
Add 1 to each side.
12
Point-slope form
Distributive Property
Subtract 3 from each side.
13
Then, solve a system of equations to find the
point of intersection of the altitudes.
Equation of altitude from J
Multiply each side by 5.
Add 105 to each side.
Add 4x to each side.
Divide each side by 26.
14
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16
5-2 Assignment
  • Page 340, 5-11, 16-19, 27-30
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