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Physics%20207:%20Lecture%202%20Notes

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Goals Employ conservation of momentum in 1 D & 2D Introduce Momentum and Impulse Compare Force vs time to Force vs distance Introduce Center-of-Mass – PowerPoint PPT presentation

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Title: Physics%20207:%20Lecture%202%20Notes


1
Lecture 15
  • Goals
  • Employ conservation of momentum in 1 D 2D
  • Introduce Momentum and Impulse
  • Compare Force vs time to Force vs distance
  • Introduce Center-of-Mass
  • Note 2nd Exam, Monday, March 19th, 715 to 845
    PM

2
Comments on Momentum Conservation
  • More general than conservation of mechanical
    energy
  • Momentum Conservation occurs in systems with no
    net external forces (as a vector quantity)

3
Explosions A collision in reverse
  • A two piece assembly is hanging vertically at
    rest at the end of a 20 m long massless string.
    The mass of the two pieces are 60 and 20 kg
    respectively. Suddenly you observe that the 20
    kg is ejected horizontally at 30 m/s. The time
    of the explosion is short compared to the swing
    of the string.
  • Does the tension in the string increase or
    decrease after the explosion?
  • If the time of the explosion is short then
    momentum is conserved in the x-direction because
    there is no net x force. This is not true of the
    y-direction but this is what we are interested in.

After
Before
4
Explosions A collision in reverse
  • A two piece assembly is hanging vertically at
    rest at the end of a 20 m long massless string.
    The mass of the two pieces are 60 and 20 kg
    respectively. Suddenly you observe that the 20
    kg mass is ejected horizontally at 30 m/s.
  • Decipher the physics
  • 1. The green ball recoils in the x direction
    (3rd Law) and, because there is no net external
    force in the x-direction the x-momentum is
    conserved.
  • 2. The motion of the green ball is constrained
    to a circular paththere must be centripetal
    (i.e., radial acceleration)

After
Before
5
Explosions A collision in reverse
  • A two piece assembly is hanging vertically at
    rest at the end of a 20 m long massless string.
    The mass of the two pieces are 60 20 kg
    respectively. Suddenly you observe that the 20
    kg mass is suddenly ejected horizontally at 30
    m/s.
  • Cons. of x-momentum
  • px before px after 0 - M V m v
  • V m v / M 2030/ 60 10 m/s
  • Tbefore Weight (6020) x 10 N 800 N
  • SFy m acy M V2/r T Mg
  • T Mg MV2 /r 600 N 60x(10)2/20 N 900 N

After
6
Exercise Momentum is a Vector (!) quantity
  • A block slides down a frictionless ramp and then
    falls and lands in a cart which then rolls
    horizontally without friction
  • In regards to the block landing in the cart is
    momentum conserved?
  1. Yes
  2. No
  3. Yes No
  4. Too little information given

7
Exercise Momentum is a Vector (!) quantity
  • x-direction No net force so Px is conserved.
  • y-direction Net force, interaction with the
    ground so
  • depending on the system (i.e., do you include the
    Earth?)
  • py is not conserved (system is block and cart
    only)

2 kg
5.0 m
30
10 kg
  • Let a 2 kg block start at rest on a 30 incline
    and slide vertically a distance 5.0 m and fall a
    distance 7.5 m into the 10 kg cart
  • What is the final velocity of the cart?

7.5 m
8
Exercise Momentum is a Vector (!) quantity
1) ai g sin 30 5 m/s2 2) d 5 m
/ sin 30 ½ ai Dt2 10 m 2.5 m/s2
Dt2 2s Dt v ai Dt 10 m/s vx v
cos 30 8.7 m/s
  • x-direction No net force so Px is conserved
  • y-direction vy of the cart block will be zero
    and we can ignore vy of the block when it lands
    in the cart.

N
5.0 m
mg
30
30
  • Initial Final
  • Px MVx mvx (Mm) Vx
  • M 0 mvx (Mm) Vx
  • Vx m vx / (M m)
  • 2 (8.7)/ 12 m/s
  • Vx 1.4 m/s

7.5 m
y
x
9
Impulse (A variable external force applied for a
given time)
  • Collisions often involve a varying force
  • F(t) 0 ? maximum ? 0
  • We can plot force vs time for a typical
    collision. The impulse, I, of the force is a
    vector defined as the integral of the force
    during the time of the collision.
  • The impulse measures momentum transfer

10
Force and Impulse (A variable force applied for
a given time)
  • J a vector that reflects momentum transfer

F
Impulse I area under this curve ! (Transfer of
momentum !)
Impulse has units of Newton-seconds
11
Force and Impulse
  • Two different collisions can have the same
    impulse since I depends only on the momentum
    transfer, NOT the nature of the collision.

same area
F
t
?t
?t
?t big, F small
?t small, F big
12
Average Force and Impulse
Fav
F
Fav
t
?t
?t
?t big, Fav small
?t small, Fav big
13
Exercise Force Impulse
  • Two boxes, one heavier than the other, are
    initially at rest on a horizontal frictionless
    surface. The same constant force F acts on each
    one for exactly 1 second.
  • Which box has the most momentum after the force
    acts ?
  1. heavier
  2. lighter
  3. same
  4. cant tell

14
Discussion Exercise
  • The only force acting on a 2.0 kg object moving
    along the x-axis. Notice that the plot is force
    vs time.
  • If the velocity vx is 2.0 m/s at 0 sec, what is
    vx at 4.0 s ?
  • Dp m Dv Impulse
  • m Dv I0,1 I1,2 I2,4
  • m Dv (-8)1 N s
  • ½ (-8)1 N s ½ 16(2) N s
  • m Dv 4 N s
  • Dv 2 m/s
  • vx 2 2 m/s 4 m/s

15
A perfectly inelastic collision in 2-D
  • Consider a collision in 2-D (cars crashing at a
    slippery intersection...no friction).

V
v1
q
m1 m2
m1
m2
v2
before
after
  • If no external force momentum is conserved.
  • Momentum is a vector so px, py and pz

16
A perfectly inelastic collision in 2-D
  • If no external force momentum is conserved.
  • Momentum is a vector so px, py and pz are
    conseved

V
v1
m1 m2
q
m1
m2
v2
before
after
  • x-dir px m1 v1 (m1 m2 ) V cos q
  • y-dir py m2 v2 (m1 m2 ) V sin q

17
2D Elastic Collisions
  • Perfectly elastic means that the objects do not
    stick and, by stipulation, mechanical energy is
    conservsed.
  • There are many more possible outcomes but, if no
    external force, then momentum will always be
    conserved

18
Billiards
  • Consider the case where one ball is initially at
    rest.

after
before
pa q
pb
vcm
Pa f
F
The final direction of the red ball will depend
on where the balls hit.
19
Billiards Without external forces, conservation
of both momentum mech. energy
  • Conservation of Momentum
  • x-dir Px m vbefore m vafter cos q m Vafter
    cos f
  • y-dir Py 0 m vafter sin q m
    Vafter sin f

If the masses of the two balls are equal then
there will always be a 90 angle between the
paths of the outgoing balls
20
Center of Mass
  • Most objects are not point-like but have a mass
    density and are often deformable.
  • So how does one account for this complexity in a
    straightforward way?
  • Example
  • In football coaches often tell players attempting
    to tackle the ball carrier to look at their
    navel.
  • So why is this so?

21
System of Particles Center of Mass (CM)
  • If an object is not held then it will rotate
    about the center of mass.
  • Center of mass Where the system is balanced !
  • Building a mobile is an exercise in finding
  • centers of mass.

mobile
22
System of Particles Center of Mass
  • How do we describe the position of a system
    made up of many parts ?
  • Define the Center of Mass (average position)
  • For a collection of N individual point-like
    particles whose masses and positions we know

(In this case, N 2)
23
Momentum of the center-of-mass is just the total
momentum
  • Notice
  • Impulse and momentum conservation applies to the
    center-of-mass

24
Sample calculation
  • Consider the following mass distribution

XCM (m x 0 2m x 12 m x 24 )/4m meters YCM
(m x 0 2m x 12 m x 0 )/4m meters XCM 12
meters YCM 6 meters
25
A classic example
  • There is a disc of uniform mass and radius r.
    However there is a hole of radius a a distance b
    (along the x-axis) away from the center.
  • Where is the center of mass for this object?

26
System of Particles Center of Mass
  • For a continuous solid, convert sums to an
    integral.

dm
where dm is an infinitesimal mass element (see
text for an example).
r
y
x
27
Recap
  • Thursday, Review for exam
  • For Tuesday, Read Chapter 10.1-10.5
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