Angular Momentum - PowerPoint PPT Presentation

1 / 41
About This Presentation
Title:

Angular Momentum

Description:

Chapter 11 Angular Momentum The Vector Product There are instances where the product of two vectors is another vector Earlier we saw where the product of two vectors ... – PowerPoint PPT presentation

Number of Views:230
Avg rating:3.0/5.0
Slides: 42
Provided by: Marily347
Category:

less

Transcript and Presenter's Notes

Title: Angular Momentum


1
Chapter 11
  • Angular Momentum

2
The Vector Product
  • There are instances where the product of two
    vectors is another vector
  • Earlier we saw where the product of two vectors
    was a scalar
  • This was called the dot product
  • The vector product of two vectors is also called
    the cross product

3
The Vector Product and Torque
  • The torque vector lies in a direction
    perpendicular to the plane formed by the position
    vector and the force vector
  • t r x F
  • The torque is the vector (or cross) product of
    the position vector and the force vector

4
The Vector Product Defined
  • Given two vectors, A and B
  • The vector (cross) product of A and B is defined
    as a third vector, C
  • C is read as A cross B
  • The magnitude of C is AB sin q
  • q is the angle between A and B

5
More About the Vector Product
  • The quantity AB sin q is equal to the area of the
    parallelogram formed by A and B
  • The direction of C is perpendicular to the plane
    formed by A and B
  • The best way to determine this direction is to
    use the right-hand rule

6
Properties of the Vector Product
  • The vector product is not commutative. The order
    in which the vectors are multiplied is important
  • To account for order, remember
  • A x B - B x A
  • If A is parallel to B (q 0o or 180o), then A x
    B 0
  • Therefore A x A 0

7
More Properties of the Vector Product
  • If A is perpendicular to B, then A x B AB
  • The vector product obeys the distributive law
  • A x (B C) A x B A x C

8
Final Properties of the Vector Product
  • The derivative of the cross product with respect
    to some variable such as t is
  • where it is important to preserve the
    multiplicative order of A and B

9
Vector Products of Unit Vectors
10
Vector Products of Unit Vectors, cont
  • Signs are interchangeable in cross products
  • A x (-B) - A x B

11
Using Determinants
  • The cross product can be expressed as
  • Expanding the determinants gives

12
Torque Vector Example
  • Given the force
  • t ?

13
Angular Momentum
  • Consider a particle of mass m located at the
    vector position r and moving with linear momentum
    p

14
Angular Momentum, cont
  • The instantaneous angular momentum L of a
    particle relative to the origin O is defined as
    the cross product of the particles instantaneous
    position vector r and its instantaneous linear
    momentum p
  • L r x p

15
Torque and Angular Momentum
  • The torque is related to the angular momentum
  • Similar to the way force is related to linear
    momentum
  • This is the rotational analog of Newtons Second
    Law
  • St and L must be measured about the same origin
  • This is valid for any origin fixed in an inertial
    frame

16
More About Angular Momentum
  • The SI units of angular momentum are (kg.m2)/ s
  • Both the magnitude and direction of L depend on
    the choice of origin
  • The magnitude of L mvr sin f
  • f is the angle between p and r
  • The direction of L is perpendicular to the plane
    formed by r and p

17
Angular Momentum of a Particle, Example
  • The vector L r x p is pointed out of the
    diagram
  • The magnitude is
  • L mvr sin 90o mvr
  • sin 90o is used since v is perpendicular to r
  • A particle in uniform circular motion has a
    constant angular momentum about an axis through
    the center of its path

18
Angular Momentum of a System of Particles
  • The total angular momentum of a system of
    particles is defined as the vector sum of the
    angular momenta of the individual particles
  • Ltot L1 L2 Ln SLi
  • Differentiating with respect to time

19
Angular Momentum of a System of Particles, cont
  • Any torques associated with the internal forces
    acting in a system of particles are zero
  • Therefore,
  • The net external torque acting on a system about
    some axis passing through an origin in an
    inertial frame equals the time rate of change of
    the total angular momentum of the system about
    that origin

20
Angular Momentum of a System of Particles, final
  • The resultant torque acting on a system about an
    axis through the center of mass equals the time
    rate of change of angular momentum of the system
    regardless of the motion of the center of mass
  • This applies even if the center of mass is
    accelerating, provided t and L are evaluated
    relative to the center of mass

21
Angular Momentum of a Rotating Rigid Object
  • Each particle of the object rotates in the xy
    plane about the z axis with an angular speed of w
  • The angular momentum of an individual particle is
    Li mi ri2 w
  • L and w are directed along the z axis

22
Angular Momentum of a Rotating Rigid Object, cont
  • To find the angular momentum of the entire
    object, add the angular momenta of all the
    individual particles
  • This also gives the rotational form of Newtons
    Second Law

23
Angular Momentum of a Rotating Rigid Object, final
  • The rotational form of Newtons Second Law is
    also valid for a rigid object rotating about a
    moving axis provided the moving axis
  • (1) passes through the center of mass
  • (2) is a symmetry axis
  • If a symmetrical object rotates about a fixed
    axis passing through its center of mass, the
    vector form holds L Iw
  • where L is the total angular momentum measured
    with respect to the axis of rotation

24
Angular Momentum of a Bowling Ball
  • The momentum of inertia of the ball is 2/5MR 2
  • The angular momentum of the ball is Lz Iw
  • The direction of the angular momentum is in the
    positive z direction

25
Conservation of Angular Momentum
  • The total angular momentum of a system is
    constant in both magnitude and direction if the
    resultant external torque acting on the system is
    zero
  • Net torque 0 -gt means that the system is
    isolated
  • Ltot constant or Li Lf
  • For a system of particles, Ltot SLn constant

26
Conservation of Angular Momentum, cont
  • If the mass of an isolated system undergoes
    redistribution, the moment of inertia changes
  • The conservation of angular momentum requires a
    compensating change in the angular velocity
  • Ii wi If wf
  • This holds for rotation about a fixed axis and
    for rotation about an axis through the center of
    mass of a moving system
  • The net torque must be zero in any case

27
Conservation Law Summary
  • For an isolated system -
  • (1) Conservation of Energy
  • Ei Ef
  • (2) Conservation of Linear Momentum
  • pi pf
  • (3) Conservation of Angular Momentum
  • Li Lf

28
Conservation of Angular MomentumThe
Merry-Go-Round
  • The moment of inertia of the system is the moment
    of inertia of the platform plus the moment of
    inertia of the person
  • Assume the person can be treated as a particle
  • As the person moves toward the center of the
    rotating platform, the angular speed will
    increase
  • To keep L constant

29
Motion of a Top
  • The only external forces acting on the top are
    the normal force n and the gravitational force M
    g
  • The direction of the angular momentum L is along
    the axis of symmetry
  • The right-hand rule indicates that ? r ? F r
    ? M g is in the xy plane

30
Motion of a Top, cont
  • The direction of d L is parallel to that of ? in
    part. The fact that Lf d L Li indicates that
    the top precesses about the z axis.
  • The precessional motion is the motion of the
    symmetry axis about the vertical
  • The precession is usually slow relative to the
    spinning motion of the top

31
Gyroscope
  • A gyroscope can be used to illustrate
    precessional motion
  • The gravitational force Mg produces a torque
    about the pivot, and this torque is perpendicular
    to the axle
  • The normal force produces no torque

32
Gyroscope, cont
  • The torque results in a change in angular
    momentum d L in a direction perpendicular to the
    axle. The axle sweeps out an angle df in a time
    interval dt.
  • The direction, not the magnitude, of L is
    changing
  • The gyroscope experiences precessional motion

33
Gyroscope, final
  • To simplify, assume the angular momentum due to
    the motion of the center of mass about the pivot
    is zero
  • Therefore, the total angular momentum is L Iw
    due to its spin
  • This is a good approximation when w is large

34
Precessional Frequency
  • Analyzing the previous vector triangle, the rate
    at which the axle rotates about the vertical axis
    can be found
  • wp is the precessional frequency

35
Gyroscope in a Spacecraft
  • The angular momentum of the spacecraft about its
    center of mass is zero
  • A gyroscope is set into rotation, giving it a
    nonzero angular momentum
  • The spacecraft rotates in the direction opposite
    to that of the gyroscope
  • So the total momentum of the system remains zero

36
Angular Momentum as a Fundamental Quantity
  • The concept of angular momentum is also valid on
    a submicroscopic scale
  • Angular momentum has been used in the development
    of modern theories of atomic, molecular and
    nuclear physics
  • In these systems, the angular momentum has been
    found to be a fundamental quantity
  • Fundamental here means that it is an intrinsic
    property of these objects
  • It is a part of their nature

37
Fundamental Angular Momentum
  • Angular momentum has discrete values
  • These discrete values are multiples of a
    fundamental unit of angular momentum
  • The fundamental unit of angular momentum is h-bar
  • Where h is called Plancks constant

38
Angular Momentum of a Molecule
  • Consider the molecule as a rigid rotor, with the
    two atoms separated by a fixed distance
  • The rotation occurs about the center of mass in
    the plane of the page with a speed of

39
Classical Ideas in Subatomic Systems
  • Certain classical concepts and models are useful
    in describing some features of atomic and
    molecular systems
  • Proper modifications must be made
  • A wide variety of subatomic phenomena can be
    explained by assuming discrete values of the
    angular momentum associated with a particular
    type of motion

40
Niels Bohr
  • Niels Bohr was a Danish physicist
  • He adopted the (then radical) idea of discrete
    angular momentum values in developing his theory
    of the hydrogen atom
  • Classical models were unsuccessful in describing
    many aspects of the atom

41
Bohrs Hydrogen Atom
  • The electron could occupy only those circular
    orbits for which the orbital angular momentum was
    equal to n
  • where n is an integer
  • This means that orbital angular momentum is
    quantized
Write a Comment
User Comments (0)
About PowerShow.com