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Physics Chapter 8 Fluid Mechanics

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Title: Chapter 9 Author: Dan Cote Last modified by: Dan Created Date: 12/15/2005 1:45:18 PM Document presentation format: On-screen Show (4:3) Other titles – PowerPoint PPT presentation

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Title: Physics Chapter 8 Fluid Mechanics


1
PhysicsChapter 8Fluid Mechanics
2
Density
  • ? M
  • V
  • Therefore ?V M

3
Density
Chapter 8
4
Fig. T9.3, p. 262 Slide 13
5
Archimedess Principle
  • Any object completely or partially submerged
    in a fluid is buoyed up by a force whose
    magnitude is equal to the weight of the fluid
    displaced by the object.

6
Buoyant Force
  • The upward force is called the buoyant force
  • The physical cause of the buoyant force is the
    pressure difference between the top and the
    bottom of the object

7
Buoyant Force, cont.
  • The magnitude of the buoyant force always equals
    the weight of the displaced fluid
  • The buoyant force is dependent on the volume of
    the object and the density of the fluid it is
    submerged in.
  • For a floating object, the buoyancy force must
    equal the weight of the object.
  • BW
  • Some objects may float high or low

8
Example A balloon having a volume of 1.5 cubic
meters is filled with ethyl alcohol and is
tethered to the bottom of a swimming pool.
Calculate the tension in the cord tethering it to
the bottom of the swimming pool.
  • Fy B T W 0
  • Therefore, T B W
  • T ?waterVg ?alcoholVg
  • T (?water ?alcohol )Vg
  • T (1000kg/m3 806kg/m3) (1.5m3)(9.8m/s2)
  • T 2851.8 N

B
FBD
T
W
9
11.6 Archimedes Principle
Example 9 A Swimming Raft The raft is made of
solid square pinewood. Determine whether the
raft floats in water and if so, how much of the
raft is beneath the surface.
10
11.6 Archimedes Principle
11
11.6 Archimedes Principle
The raft floats!
12
11.6 Archimedes Principle
If the raft is floating
13
Pressure
  • P F N
  • A m2
  • Pascals Principal
  • Pressure applied to a fluid in a closed
    container is transmitted equally to every point
    of the fluid and to the walls of the container.

14
Hydraulic Lift
P1 P2 Therefore F1 F2
A1 A2
F2, A2
F1, A1
15
Pressure at a Depth
  • P F mg ?Vg ?Ahg ?hg
  • A A A A

Find the pressure on the bottom of the submarine
due to the water above it. Find the pressure
on the bottom of the submarine due to the
water And air above it.
330 m
16
Equation of Continuity
  • A1v1 A2v2
  • The product of the cross-sectional area of a pipe
    and the fluid speed is a constant
  • Speed is high where the pipe is narrow and speed
    is low where the pipe has a large diameter
  • Av is called the flow rate

17
How Airplanes Wings Work
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