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Comment reconstruire le graphe de visibilit

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Comment reconstruire le graphe de visibilit d un polygone? (Reconstructing visibility graphs of polygons) J r mie Chalopin, Shantanu Das LIF, Aix-Marseille ... – PowerPoint PPT presentation

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Title: Comment reconstruire le graphe de visibilit


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Visibility Graph of Polygons
  • Gvis(P)
  • Vertices of Gvis ltgt vertices of P
  • Edge (u,v) in Gvis iff
  • u and v can see each-other.
  • (if the line u to v is inside P)
  • Objective
  • Construct Gvis
  • (up to isomorphism)

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Polygons vs. Graphs
  • Exploration of Polygons Exploration of
    edge-labeled graphs

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Polygons vs. Graphs II
  • Exploration of Polygons Exploration of
    edge-labeled graphs

Property YK 1996 A robot exploring an
edge-labeled graph of known size n, can not
always reconstruct the graph.
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Polygons vs. Graphs III
  • Exploration of Polygons Exploration of
    edge-labeled graphs

Property YK 1996 A robot exploring an
edge-labeled graph of known size n, can not
always reconstruct the graph.
Theorem A robot exploring a polygon can always
reconstruct the visibility graph of the polygon
if it knows an upper bound on n.
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Graph Exploration
  • The view of an exploring robot

Minimum-base
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Graph Exploration II
  • The minimum-base of a graph G
  • The smallest graph B such that G covers B

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Property YK 1996 A robot exploring an
edge-labeled graph can construct the minimum-base
if it knows an upper bound on n.
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Exploring visibility graphs
  • If C1,C2,,Cp are the classes of vertices in Gvis
  • Ci q n/p
  • Classes repeat periodically on the boundary.
  • How to find the internal edges (chords)?

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Properties of Polygons
  • Every polygon has an ear!
  • ( If a,b,c appear in this order on the boundary
    b is an ear iff a sees c.)
  • Removing an ear of a simple polygon leaves a
    smaller polygon.
  • (visibility relationships are maintained)
  • Every sub-polygon of four or more vertices has a
    chord.

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Properties of Polygons II
  • It is easy to recognize an ear!
  • Check for the paths
  • (1, -1) (-2, 2) (1, -1)
  • (-1, 1) (2, -2) (-1, 1)

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-2
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Lemma If v is an ear, every vertex in the
class of v is an ear.
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Deconstructing Polygons
  • Choose a class Ci of ears.
  • Remove all Ci vertices from P
  • (i.e. remove a vertex from B)

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Deconstructing Polygons-II
  • Choose a class Ci of ears.
  • Remove all Ci vertices from P
  • (i.e. remove a vertex from B)

Repeat until a single class remains!
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Deconstructing Polygons III
  • Choose a class Ci of ears.
  • Remove all Ci vertices from P
  • (i.e. remove a vertex from B)

Repeat until a single class remains!
Remaining vertices form a clique!
Lemma There is a unique class C which forms a
clique.
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Using class C
Lemma There is a unique class C which forms a
clique.
  • C corresponds to a vertex with q-1 self loops in
    the minimum-base.
  • gt
  • Robot can compute n pq

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Solving Rendezvous
Rendezvous Position the robots s.t. they are
mutually visible to each other.
  • Solving rendezvous is easy!
  • 1. Compute minimum-base.
  • 2. Identify C
  • 3. Go to any vertex of C

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Constructing Gvis
  • Edges incident to C
  • Can be identified easily.
  • Clique edges partitions P
  • Each class appears once in each part
  • Same holds for any other class that forms a clique

How to identify the remaining edges?
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Identifying Adjacencies
  • Identify edges (vi,vik) of increasing distances
    k 2, 3, ..., n/2.
  • Is the next unidentified vertex
  • vj vik or not?
  • Easy, if in different classes.
  • Let y be the number of dist. (k-1) backward-edges
    of vik
  • Go to vj and look back (LB)

We can show that vj vik ltgt LB -(y1)
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Complexity of the Algorithm
  • The complexity is dominated by cost of
    constructing minimum-base
  • Walk along the boundary and identify the
    neighbors of each vertex.
  • Use distinguishing paths to identify classes (n-1
    paths of length n)
  • Iteratively obtain distinguishing paths for k 1
    to n
  • Cost O(n3m) moves.
  • (Additional cost O(n2) moves)

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Summary
  • A robot moving in a polygon P that
  • knows an UB on n (vertices of P)
  • and can look back
  • Is able to
  • compute the value of n
  • construct the visibility graph
  • solve rendezvous
  • Why visibility graphs?
  • It is not possible to determine the exact shape
    of the polygon.
  • Visibility graphs provide sufficient topological
    information.

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Related Results
  • With angle measurements at each vertex
  • A robot moving only on the boundary and knowing
    n, can reconstruct the polygon. Disser et al.
    2010
  • Convexity Detection Look-back
  • A robot knowing n can construct the visibility
    graph Bilo et al. 2009
  • Only Convexity Detection
  • A robot can knowing n construct the visibility
    graph (in exponential time) (unpublished)
  • Impossibility
  • A robot moving on the boundary can not construct
    visibility graph even if it knows n Bilo et al.
    2009
  • Distance Measurements to visible vertices
  • Can the robot construct the visibility graph?

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Merci de votre attention!
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