Is this quarter fair? - PowerPoint PPT Presentation

About This Presentation
Title:

Is this quarter fair?

Description:

Is this quarter fair? – PowerPoint PPT presentation

Number of Views:28
Avg rating:3.0/5.0
Slides: 125
Provided by: EndU7
Category:
Tags: fair | mmpi | quarter

less

Transcript and Presenter's Notes

Title: Is this quarter fair?


1
(No Transcript)
2
Example
  • You give 100 random students a questionnaire
    designed to measure attitudes toward living in
    dormitories
  • Scores range from 1 to 7
  • (1 unfavorable 4 neutral 7 favorable)
  • You wonder if the mean score of the population is
    different then 4

3
Hypothesis
  • Alternative hypothesis
  • H1 ?sample 4
  • In other words, the population mean will be
    different than 4

4
Hypothesis
  • Alternative hypothesis
  • H1 ?sample 4
  • Null hypothesis
  • H0 ?sample 4
  • In other words, the population mean will not be
    different than 4

5
Results
  • N 100
  • X 4.51
  • s 1.94
  • Notice, your sample mean is consistent with H1,
    but you must determine if this difference is
    simply due to chance

6
Results
  • N 100
  • X 4.51
  • s 1.94
  • To determine if this difference is due to chance
    you must calculate an observed t value

7
Observed t-value
  • tobs (X - ?) / Sx

8
Observed t-value
  • tobs (X - ?) / Sx
  • This will test if the null hypothesis H0 ?
    sample 4 is true
  • The bigger the tobs the more likely that H1 ?
    sample 4 is true

9
Observed t-value
  • tobs (X - ?) / Sx

Sx S / N
10
Observed t-value
  • tobs (X - ?) / .194

.194 1.94/ 100
11
Observed t-value
  • tobs (4.51 4.0) / .194

12
Observed t-value
  • 2.63 (4.51 4.0) / .194

13
t distribution
14
t distribution
tobs 2.63
15
t distribution
tobs 2.63
Next, must determine if this t value happened due
to chance or if represent a real difference in
means. Usually, we want to be 95 certain.
16
t critical
  • To find out how big the tobs must be to be
    significantly different than 0 you find a tcrit
    value.
  • Calculate df N - 1
  • Page 747
  • First Column are df
  • Look at an alpha of .05 with two-tails

17
t distribution
tobs 2.63
18
t distribution
tcrit -1.98
tcrit 1.98
tobs 2.63
19
t distribution
tcrit -1.98
tcrit 1.98
tobs 2.63
20
t distribution
tcrit -1.98
tcrit 1.98
tobs 2.63
If tobs fall in critical area reject the null
hypothesis Reject H0 ? sample 4
21
t distribution
tcrit -1.98
tcrit 1.98
tobs 2.63
If tobs does not fall in critical area do not
reject the null hypothesis Do not reject H0 ?
sample 4
22
Decision
  • Since tobs falls in the critical region we reject
    Ho and accept H1
  • It is statistically significant, students tend to
    think favorably about living in the dorms.
  • p lt .05

23
Example
  • You wonder if the average IQ score of students at
    Villanova significantly different (at alpha
    .05)than the average IQ of the population (which
    is 100). You sample the students in this room.
  • N 54
  • X 130
  • s 18.4

24
The Steps
  • Try to always follow these steps!

25
Step 1 Write out Hypotheses
  • Alternative hypothesis
  • H1 ?sample 100
  • Null hypothesis
  • H0 ?sample 100

26
Step 2 Calculate the Critical t
  • N 54
  • df 53
  • ? .05
  • tcrit 2.0

27
Step 3 Draw Critical Region
tcrit 2.00
tcrit -2.00
28
Step 4 Calculate t observed
  • tobs (X - ?) / Sx

29
Step 4 Calculate t observed
  • tobs (X - ?) / Sx

Sx S / N
30
Step 4 Calculate t observed
  • tobs (X - ?) / Sx

2.5 18.4 / 54
31
Step 4 Calculate t observed
  • tobs (X - ?) / Sx
  • 12 (130 - 100) / 2.5

2.5 18.4 / 54
32
Step 5 See if tobs falls in the critical region
tcrit 2.00
tcrit -2.00
33
Step 5 See if tobs falls in the critical region
tcrit 2.00
tcrit -2.00
tobs 12
34
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

35
Step 7 Put answer into words
  • We reject H0 and accept H1.
  • The average IQ of students at Villanova is
    statistically different (? .05) than the
    average IQ of the population.

36
Practice
  • You recently finished giving 5 of your friends
    the MMPI paranoia measure. Is your friends
    average average paranoia score significantly (?
    .10) different than the average paranoia of the
    population (? 56.1)?

37
Scores
38
Step 1 Write out Hypotheses
  • Alternative hypothesis
  • H1 ?sample 56.1
  • Null hypothesis
  • H0 ?sample 56.1

39
Step 2 Calculate the Critical t
  • N 5
  • df 4
  • ? .10
  • tcrit 2.132

40
Step 3 Draw Critical Region
tcrit 2.132
tcrit -2.132
41
Step 4 Calculate t observed
  • tobs (X - ?) / Sx
  • -.48 (55.2 - 56.1) / 1.88

1.88 4.21/ 5
42
Step 5 See if tobs falls in the critical region
tcrit 2.132
tcrit -2.132
tobs -.48
43
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

44
Step 7 Put answer into words
  • We fail to reject H0
  • The average paranoia of your friends is not
    statistically different (? .10) than the
    average paranoia of the population.

45
SPSS
46
(No Transcript)
47
One-tailed test
  • In the examples given so far we have only
    examined if a sample mean is different than some
    value
  • What if we want to see if the sample mean is
    higher or lower than some value
  • This is called a one-tailed test

48
Remember
  • You recently finished giving 5 of your friends
    the MMPI paranoia measure. Is your friends
    average paranoia score significantly (? .10)
    different than the average paranoia of the
    population (? 56.1)?

49
Hypotheses
  • Alternative hypothesis
  • H1 ?sample 56.1
  • Null hypothesis
  • H0 ?sample 56.1

50
What if. . .
  • You recently finished giving 5 of your friends
    the MMPI paranoia measure. Is your friends
    average paranoia score significantly (? .10)
    lower than the average paranoia of the population
    (? 56.1)?

51
Hypotheses
  • Alternative hypothesis
  • H1 ?sample lt 56.1
  • Null hypothesis
  • H0 ?sample or gt 56.1

52
Step 2 Calculate the Critical t
  • N 5
  • df 4
  • ? .10
  • Since this is a one-tail test use the
    one-tailed column
  • Note one-tail directional test
  • tcrit -1.533
  • If H1 is lt then tcrit negative
  • If H1 is gt then tcrit positive

53
Step 3 Draw Critical Region
tcrit -1.533
54
Step 4 Calculate t observed
  • tobs (X - ?) / Sx

55
Step 4 Calculate t observed
  • tobs (X - ?) / Sx
  • -.48 (55.2 - 56.1) / 1.88

1.88 4.21/ 5
56
Step 5 See if tobs falls in the critical region
tcrit -1.533
57
Step 5 See if tobs falls in the critical region
tcrit -1.533
tobs -.48
58
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

59
Step 7 Put answer into words
  • We fail to reject H0
  • The average paranoia of your friends is not
    statistically less then (? .10) the average
    paranoia of the population.

60
Practice
  • You just created a Smart Pill and you gave it
    to 150 subjects. Below are the results you
    found. Did your Smart Pill significantly (?
    .05) increase the average IQ scores over the
    average IQ of the population (? 100)?
  • X 103
  • s 14.4

61
Step 1 Write out Hypotheses
  • Alternative hypothesis
  • H1 ?sample gt 100
  • Null hypothesis
  • H0 ?sample lt or 100

62
Step 2 Calculate the Critical t
  • N 150
  • df 149
  • ? .05
  • tcrit 1.645

63
Step 3 Draw Critical Region
tcrit 1.645
64
Step 4 Calculate t observed
  • tobs (X - ?) / Sx
  • 2.54 (103 - 100) / 1.18

1.1814.4 / 150
65
Step 5 See if tobs falls in the critical region
tcrit 1.645
tobs 2.54
66
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

67
Step 7 Put answer into words
  • We reject H0 and accept H1.
  • The average IQ of the people who took your Smart
    Pill is statistically greater (? .05) than the
    average IQ of the population.

68
(No Transcript)
69
So far. . .
  • We have been doing hypothesis testing with a
    single sample
  • We find the mean of a sample and determine if it
    is statistically different than the mean of a
    population

70
Basic logic of research
71
Start with two equivalent groups of subjects
72
Treat them alike except for one thing
73
See if both groups are different at the end
74
Notice
  • This means that we need to see if two samples are
    statistically different from each other
  • We can use the same logic we learned earlier with
    single sample hypothesis testing

75
Example
  • You just invented a magic math pill that will
    increase test scores.
  • You give the pill to 4 subjects and another 4
    subjects get no pill
  • You then examine their final exam grades

76
HypothesisTwo-tailed
  • Alternative hypothesis
  • H1 ?pill ?nopill
  • In other words, the means of the two groups will
    be significantly different
  • Null hypothesis
  • H0 ?pill ?nopill
  • In other words, the means of the two groups will
    not be significantly different

77
HypothesisOne-tailed
  • Alternative hypothesis
  • H1 ?pill gt ?nopill
  • In other words, the pill group will score higher
    than the no pill group
  • Null hypothesis
  • H0 ?pill lt or ?nopill
  • In other words, the pill group will be lower or
    equal to the no pill group

78
For current example, lets just see if there is a
difference
  • Alternative hypothesis
  • H1 ?pill ?nopill
  • In other words, the means of the two groups will
    be significantly different
  • Null hypothesis
  • H0 ?pill ?nopill
  • In other words, the means of the two groups will
    not be significantly different

79
Results
  • Pill Group
  • 5
  • 3
  • 4
  • 3
  • No Pill Group
  • 1
  • 2
  • 4
  • 3

80
Remember before. . . Step 2 Calculate the
Critical t
  • df N -1

81
NowStep 2 Calculate the Critical t
  • df N1 N2 - 2
  • df 4 4 - 2 6
  • ? .05
  • t critical 2.447

82
Step 3 Draw Critical Region
tcrit 2.447
tcrit -2.447
83
Remember before. . .Step 4 Calculate t observed
  • tobs (X - ?) / Sx

84
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2

85
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2

86
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2
  • X1 3.75
  • X2 2.50

87
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2

88
Standard Error of a Difference
  • Sx1 - x2
  • When the N of both samples are equal
  • If N1 N2
  • Sx1 - x2 Sx12 Sx22

89
Results
  • Pill Group
  • 5
  • 3
  • 4
  • 3
  • No Pill Group
  • 1
  • 2
  • 4
  • 3

90
Standard Deviation
S
-1
91
Standard Deviation
  • Pill Group
  • 5
  • 3
  • 4
  • 3
  • No Pill Group
  • 1
  • 2
  • 4
  • 3

??X2 10 ??X22 30
??X1 15 ??X12 59
92
Standard Deviation
  • Pill Group
  • 5
  • 3
  • 4
  • 3
  • No Pill Group
  • 1
  • 2
  • 4
  • 3

??X2 10 ??X22 30
??X1 15 ??X12 59
S .96
S 1.29
93
Standard Deviation
  • Pill Group
  • 5
  • 3
  • 4
  • 3
  • No Pill Group
  • 1
  • 2
  • 4
  • 3

??X2 10 ??X22 30
??X1 15 ??X12 59
S .96
S 1.29
Sx .48
Sx . 645
94
Standard Error of a Difference
  • Sx1 - x2
  • When the N of both samples are equal
  • If N1 N2
  • Sx1 - x2 Sx12 Sx22

95
Standard Error of a Difference
  • Sx1 - x2
  • When the N of both samples are equal
  • If N1 N2
  • Sx1 - x2 (.48)2 (.645)2

96
Standard Error of a Difference
  • Sx1 - x2
  • When the N of both samples are equal
  • If N1 N2
  • Sx1 - x2 (.48)2 (.645)2

.80
97
Standard Error of a Difference Raw Score Formula
  • When the N of both samples are equal
  • If N1 N2
  • Sx1 - x2

98
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4
  • Sx1 - x2

99
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4
  • Sx1 - x2

10
15
100
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4
  • Sx1 - x2

10
15
59
30
101
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4
  • Sx1 - x2

10
15
59
30
4
4
4 (4 - 1)
102
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4
  • Sx1 - x2

10
15
59
30
56.25
25
4
4
12
103
??X1 15 ??X12 59 N1 4
??X2 10 ??X22 30 N2 4

10
15
.80
59
30
56.25
25
7.75
4
4
12
104
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2

Sx1 - x2 .80 X1 3.75 X2 2.50
105
NowStep 4 Calculate t observed
  • tobs (3.75 - 2.50) / .80

Sx1 - x2 .80 X1 3.75 X2 2.50
106
NowStep 4 Calculate t observed
  • 1.56 (3.75 - 2.50) / .80

Sx1 - x2 .80 X1 3.75 X2 2.50
107
Step 5 See if tobs falls in the critical region
tcrit 2.447
tcrit -2.447
108
Step 5 See if tobs falls in the critical region
tcrit 2.447
tcrit -2.447
tobs 1.56
109
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

110
Step 7 Put answer into words
  • We fail to reject H0.
  • The final exam grades of the pill group were
    not statistically different (? .05) than the
    final exam grades of the no pill group.

111
SPSS
112
Practice
  • You wonder if psychology majors have higher IQs
    than sociology majors (? .05)
  • You give an IQ test to 4 psychology majors and 4
    sociology majors

113
Results
  • Psychology
  • 110
  • 150
  • 140
  • 135
  • Sociology
  • 90
  • 95
  • 80
  • 98

114
Step 1 Hypotheses
  • Alternative hypothesis
  • H1 ?psychology gt ?sociology
  • Null hypothesis
  • H0 ?psychology or lt ?sociology

115
Step 2 Calculate the Critical t
  • df N1 N2 - 2
  • df 4 4 - 2 6
  • ? .05
  • One-tailed
  • t critical 1.943

116
Step 3 Draw Critical Region
tcrit 1.943
117
NowStep 4 Calculate t observed
  • tobs (X1 - X2) / Sx1 - x2

118
??X1 535 ??X12 72425 N1 4 X1 133.75
??X2 363 ??X22 33129 N2 4 X2 90.75
  • 9.38

363
535
72425
33129
4
4
4 (4 - 1)
119
Step 4 Calculate t observed
  • 4.58 (133.75 - 90.75) / 9.38

Sx1 - x2 9.38 X1 133.75 X2 90.75
120
Step 5 See if tobs falls in the critical region
tcrit 1.943
tobs 4.58
121
Step 6 Decision
  • If tobs falls in the critical region
  • Reject H0, and accept H1
  • If tobs does not fall in the critical region
  • Fail to reject H0

122
Step 7 Put answer into words
  • We Reject H0, and accept H1
  • Psychology majors have significantly (? .05)
    higher IQs than sociology majors.

123
Practice
124
SPSS Problem 2
  • 7.37
  • 7.11
Write a Comment
User Comments (0)
About PowerShow.com