Title: Lecture 05 Analysis (I)
1Lecture 05 Analysis (I) Time Response and State
Transition Matrix
5.1 State Transition Matrix 5.2 Modal
decomposition --Diagonalization 5.3
Cayley-Hamilton Theorem
2The behavior of x(t) et y(t)
- Homogeneous solution of x(t)
- Non-homogeneous solution of x(t)
3Homogeneous solution
State transition matrix
4Properties
5Non-homogeneous solution
Convolution
Homogeneous
6Zero-input response
Zero-state response
7Example 1
Ans
8Using Maisons gain formula
9Methode 1
Methode 2
Methode 3 Cayley-Hamilton Theorem
10Methode 1
11Method 2 Diagonalization
Example 4.5
diagonal matrix
12Diagonalization via Coordinate Transformation
Plant
Eigenvalue of A
Assume that all the eigenvalues of A are
distinct, i.e.
Then eigenvectors,
are independent.
Coordinate transformation matrix
13where
14New coordinate
(4.1)
Solution of (4.1)
The above expansion of x(t) is called modal
decomposition.
Hence, system asy. stable ? all the eigenvales of
A lie in LHP
15Example
Find eigenvector
16(4.2)
Solution of (4.1)
17In the case of A matrix is phase-variable form
and
Vandermonde matrix for phase-variable form
18Example
depend
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20Case 3
Jordan form
Generalized eigenvectors
21Example
22Cayley-Hamilton Theorem
Method 3
Theorem Every square matrix satisfies its char.
equation.
Given a square matrix A, . Let
f(?) be the char. polynomial of A.
Char. Equation
By Caley-Hamilton Theorem
23any
24Example
25Example
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32Example
33Example