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Methods of Proof

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Title: Methods of Proof


1
Methods of Proof
  • Proof techniques in this handout
  • Direct proof
  • Division into cases
  • Proof by contradiction
  • In this handout, the proof techniques will be
    used to prove properties in number theory.

2
Even and Odd Integers
  • Definition An integer n
  • ? is even iff
  • ? an integer k such that n2k
  • ? is odd iff
  • ? an integer k such that n2k1.
  • Ex If x and y are integers,
  • is even or odd?

3
Method of Direct Proof
  • To prove a statement ?x?D if P(x) then Q(x).
  • Suppose x is a particular but arbitrarily
    chosen element of D
  • for which P(x) is true
  • Show the conclusion Q(x) is true by using
  • ? definitions
  • ? previously established results
  • ? rules of logical inference.

4
Method of Direct Proof (Ex.)
  • Show ?x?Z if x is odd
  • then 3x9 is even.
  • Proof Suppose x is an arbitrarily chosen odd
    integer.
  • Then x2k1 for some integer k. (by
    definition)
  • So 3x9 3(2k1)9 (by substitution)
  • 6k39 (by distributive law)
  • 2(3k6) (by factoring out a 2)
    ()
  • 3k6 is an integer. ()
  • Hence 3x9 is even
  • based on (), () and definition of even
    integers.
  • (this is what we needed to show)

5
Directions for writing proofs
  • Write the theorem to be proved.
  • Clearly mark the beginning of your proof
  • with the word Proof.
  • 3) Make your proof self-contained.
  • (Identify all variables used in the proof
  • state the sources of outside facts).
  • 4) Write proofs in complete English
    sentences.

6
Common mistakes in proofs
  • Arguing from examples
  • Using same letter
  • to mean two different things
  • Jumping to a conclusion
  • (without adequate reasons)

7
Types of Mathematical Statements
  • Theorems Very important statements that
  • have many and varied consequences.
  • Propositions Less important and
    consequential.
  • Corollaries The truth can be deduced
    almost immediately
  • from other statements.
  • Lemmas Dont have much intrinsic interest but
    help to prove other theorems.

8
Divisibility
  • Definition For n,d ?Z and d?0 we say that n
    is divisible by d
  • iff ndk for some k ?Z .
  • Alternative ways to say
  • n is a multiple of d , d is a factor of n ,
  • d is a divisor of n , d divides n .
  • Notation d n .
  • Examples 648, 55, -48, 70, 19 .

9
Properties of Divisibility
  • For ?x?Z, 1x .
  • For ?x?Z s.t. x?0, x0 .
  • For ?a,b,c?Z, if ab and ac then a(bc) .
  • Transitivity For ?a,b,c?Z,
  • if ab and bc then ac .

10
Quotient-Remainder Theorem
  • Theorem For ? n?Z and d?Z
  • ?! q,r?Z such that
  • ndqr and 0rltd.
  • q is called quotient r is called remainder.
  • Notation q n div d r n mod d.
  • Examples 1) 53 865. Hence
  • 53 div 8 6 53 mod 8 5.
  • 2) -29 7(-5)6. Hence
  • -29 div 7 -5 -29 mod 7 6.

11
Example of using div and mod
  • Last year Halloween was on Thursday.
  • Q. What day is Halloween this year?
  • Solution There are 365 days between
  • 10/31/13 and 10/31/14.
  • 365 mod 7 1.
  • Thus, if 10/31/13 was Thursday
  • then 10/31/14 is Friday.

12
Proof Technique Division into Cases
  • Suppose at some stage of a proof
  • ? we know that
  • A1 or A2 or A3 or or An is true
  • ? want to deduce a conclusion C.
  • Use division into cases
  • Show A1?C, A2?C, , An?C.
  • Conclude that C is true.

13
Division into Cases Example
  • Proposition If n?Z such that
  • neither of 2 or 3 divide n, (1)
  • then n2 mod 12 1. (2)
  • Proof Suppose n?Z s.t. neither of 2 or 3 divide
    n.
  • By quotient-remainder theorem,
  • exactly one of the following is true
  • a) n6k, b) n6k1, c) n6k2, d) n6k3,
  • e) n6k4, f) n6k5 for some integer
    k. (3)
  • n cant be 6k, 6k2 or 6k4 because
  • in that case 2 n (which contradicts (1) ).
    (4)
  • n cant be 6k3 because in that case 3 n
  • (which contradicts (1) ). (5)

14
Division into Cases Example(cont.)
  • Proof(cont.) Based on (3), (4) and (5),
  • either n6k1 or n6k5.
  • Lets show (2) for each of these two cases.
  • Case 1 Suppose n6k1.
  • Then n2 (6k1)236k212k1 (by basic
    algebra)
  • 12(3k2k)1 (6)
  • Let p3k2k. Then p is an integer.
  • n2 12p1 . ( by substitution in (6) )
  • Hence n2 mod 12 1 by quotient-remainder
    th-m.
  • Case 2 Suppose n6k5. (exercise)

15
Method of Proof by Contradiction
  • Suppose the statement to be proved is false.
  • Show that this supposition logically leads to a
    contradiction.
  • Conclude that the statement to be proved is true.
  • Example of proof by contradiction.
  • Theorem There is no greatest integer.
  • The proof on the board.
  • We will see several contradiction proofs in graph
    theory.
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