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COVALENT BONDING: ORBITALS

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COVALENT BONDING: ORBITALS HYBRIDIZATION (9.1) HYBRIDIZATION Consider methane,CH4 C has 4 valence electrons 1s2 2s2 2p2 This suggests that there might be two kinds of ... – PowerPoint PPT presentation

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Title: COVALENT BONDING: ORBITALS


1
COVALENT BONDING ORBITALS
  • HYBRIDIZATION (9.1)

2
HYBRIDIZATION
  • Consider methane,CH4
  • C has 4 valence electrons 1s2 2s2 2p2
  • This suggests that there might be two kinds of
    C-H bonds one involving a 2s e- on carbon
    pairing with the 1s on H and the other involving
    a 2p e- on carbon pairing with the 1s on H.
  • Expt evidence confirms that the four C-H bonds in
    CH4 are identical and that CH4is tetrahedral.

3
Figure 9.1 a b a) The Lewis Structure of the
Methane Molecule b) The Tetrahedral Molecular
Geometry of the Methane Molecule
4
HYBRIDIZATION (2)
  • To resolve this conflict, promote a 2s electron
    to the empty 2p orbital, then mix or hybridize
    the 2s (1) and 2p (3) orbitals to form four
    identical hybrid AOs named sp3
  • These hybrid atomic orbitals overlap with the 1s
    orbital on hydrogen to form the covalent C-H bond
    (sp3 1s).
  • Why do hybrids form? To minimize total energy.

5
HYBRIDIZATION (3)
  • Using the VSEPR rules, C has four covalent bonds
    and has tetrahedral molecular geometry. The
    H-C-H bond angle 109.5o. This agrees with
    exptal measurements (4 identical C-H bonds).
  • Hybridization integrates electron configurations
    with expt measurements.
  • Other hybrids sp2 (3 e pairs), sp (2), dsp3
    (5), d2sp3 (6)

6
Figure 9.24 Relationship of the Number of
Effective Pairs, Their Spatial Arrangement, and
the Hybrid Orbital Set Required
7
Figure 9.8 The Hybridization of the s, px, and
py Atomic Orbitals Results in the Formation of
Three sp2 Orbtitals Centered in the xy Plane
8
Figure 9.9 An Orbital Energy-Level Diagram for
sp2 Hybridization
9
Figure 9.11 The Sigma Bonds in Ethylene
10
Figure 9.13 (a)The Orbitals Used to Form the
Bonds in Ethylene (b) The Lewis Structure for
Ethylene
11
Figure 9.16 The Orbital Energy-Level Diagram for
the Formation of sp Hybrid Orbitals on Carbon
12
Figure 9.20 a-d (a) The sp hybridized N atom (b)
The ? bonds in the N2 molecule (c) The two pi
bonds in N2 are formed when electron pairs are
shared between two sets of parallel p orbitals
(d) The total bonding picture of N2
13
Figure 9.21 A Set of dsp3 Hybrid Orbitals on
Phosphorus Atom
14
Figure 9.23 An Octahedral Set of d2sp3 Orbitals
on Sulfur Atom
15
Figure 9.24 Relationship of the Number of
Effective Pairs, Their Spatial Arrangement, and
the Hybrid Orbital Set Required
16
HYBRIDS AND MOLECULAR STRUCTURE
  • Write Lewis structure and use VSEPR method to
    predict e pair geometry
  • Select hybridization scheme this is consistent
    with VSEPR prediction (Fig 9.24)
  • Identify orbital overlap
  • Form multiple bonds if needed
  • Determine molecular geometry

17
HYBRIDS AND MULTIPLE BONDS (1)
  • Use Valence Bond method to determine
    3-dimensional structure of hydrocarbons with
    double and triple bonds (planar)
  • Sigma (?) or end-to-end orbital overlap bond
  • Pi (?) or side-by-side orbital overlap bond
  • Geometric isomers (2-butene)
  • Benzene and other aromatic compounds

18
HYBRIDS AND MULTIPLE BONDS (2)
  • A single bond has one sigma bond.
  • A double bond has one sigma bond and one pi bond.
  • A triple bond has one sigma bond and two pi
    bonds.

19
Problems
  • 16, 18, 22, 24, 28, 32, 33
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