Lesson 4-10b - PowerPoint PPT Presentation

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Lesson 4-10b

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... the concept of an antiderivative Understand the geometry of the antiderivative and that of slope fields Work rectilinear motion ... 12 Motion Problems ... – PowerPoint PPT presentation

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Title: Lesson 4-10b


1
Lesson 4-10b
  • Anti-Differentiation

2
Quiz
  • Estimate the area under the graph of f(x) x²
    1 from x -1 to x 2 . Improve your estimate
    by using six right endpoint rectangles.

3
Objectives
  • Understand the concept of an antiderivative
  • Understand the geometry of the antiderivative and
    that of slope fields
  • Work rectilinear motion problems with
    antiderivatives

4
Vocabulary
  • Antiderivative the opposite of the derivative,
    if f(x) F(x) then F(x) is the antiderivative
    of f(x)
  • Integrand what is being taken the integral of
    F(x)
  • Variable of integration what variable we are
    taking the integral with respect to
  • Constant of integration a constant (derivative
    of which would be zero) that represents the
    family of functions that could have the same
    derivative

5
Two other Anti-derivative Forms
  • Form
  • Form

Remember derivative of ex is just ex
Remember derivative of ln x is (1/x)
6
Practice Problems
2ex x C
-5 lnx C
ex ?x3 - x C
x ln x C
7
How to Find C
  • In order to find the specific value of the
    constant of integration, we need to have an
    initial condition to evaluate the function at (to
    solve for C)!
  • Example find
    such that F(1) 4.

F(x) x² 3x C
F(1) 4 (1)² 3(1) C 4
C 0 C (boring
answer!)
8
Acceleration, Velocity, Position
  • Remember the following equation from
    Physicss(t) s0 v0t ½ at² where s0 is
    the initial offset distance (when t0)
    v0 is the initial velocity (when t0) and
    a is the acceleration constant (due to gravity)
  • We can solve problems given either s(t) or a(t)
    (and some initial conditions) basically solving
    the problem from either direction!

9
Motion Problems
  • Find the velocity function v(t) and position
    function s(t) corresponding to the acceleration
    function a(t) 4t 4 given v(0) 8 and s(0)
    12.

2t² 4t 8
v(0) 8 2(0)² 4(0) v0 8 v0
s(0) 12 ?(0)³ 2(0)² 8(0) s0
12 s0
s(t) ?t³ 2t² 8t 12
10
Motion Problems
  • A ball is dropped from a window hits the ground
    in 5 seconds. How high is the window (in feet)?

a(t) - 32 ft/s²
v(0) 0 -32(0) v0
(ball was dropped) 0 v0
s(5) 0 -16(5)² s0 s0 400 feet
window was 400 feet up
11
Slope Fields
  • A slope field is the slope of the tangent to F(x)
    (f(x) in an anti-differentiation problem) plotted
    at each value of x and y in field.
  • Since the constant of integration is unknown, we
    get a family of curves.
  • An initial condition allows us to plot the
    function F(x) based on the slope field.

12
Slope Field Example
f(0) -2
13
Summary Homework
  • Summary
  • Anti-differentiation is the reverse of the
    derivative
  • It introduces the integral
  • One of its main applications is area under the
    curve
  • Homework
  • pg 358-360 Day 1 1-3, 12, 13, 16
    Day 2 25, 26, 53, 61, 74
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