Title: Fundamentals of Electromagnetics for Teaching and Learning: A Two-Week Intensive Course for Faculty in Electrical-, Electronics-, Communication-, and Computer- Related Engineering Departments in Engineering Colleges in India
1Fundamentals of Electromagneticsfor Teaching and
LearningA Two-Week Intensive Course for Faculty
inElectrical-, Electronics-, Communication-, and
Computer- Related Engineering Departments in
Engineering Colleges in India
- by
- Nannapaneni Narayana Rao
- Edward C. Jordan Professor Emeritus
- of Electrical and Computer Engineering
- University of Illinois at Urbana-Champaign, USA
- Distinguished Amrita Professor of Engineering
- Amrita Vishwa Vidyapeetham, India
2Program for Hyderabad Area and Andhra Pradesh
FacultySponsored by IEEE Hyderabad Section, IETE
Hyderabad Center, and Vasavi College of
EngineeringIETE Conference Hall, Osmania
University CampusHyderabad, Andhra PradeshJune
3 June 11, 2009 Workshop for Master Trainer
Faculty Sponsored byIUCEE (Indo-US Coalition for
Engineering Education)Infosys Campus, Mysore,
KarnatakaJune 22 July 3, 2009
3- Module 2
- Maxwells Equations
- in Integral Form
- 2.1 The line integral
- 2.2 The surface integral
- 2.3 Faradays law
- 2.4 Amperes circuital law
- 2.5 Gauss Laws
- 2.6 The Law of Conservation of Charge
- 2.7 Application to static fields
4Instructional Objectives
- 8. Evaluate line and surface integrals
- 9. Apply Faraday's law in integral form to find
the - electromotive force induced around a closed
loop, fixed or - revolving, for a given magnetic field
distribution - 10. Make use of the uniqueness of the
magnetomotive force - around a closed path to find the
displacement current - emanating from a closed surface for a given
current - distribution
- 11. Apply Gauss law for the electric field in
integral form to - find the displacement flux emanating from a
closed - surface bounding the volume for a specified
charge - distribution within the volume
- 12. Apply Gauss law for the magnetic field in
integral form - to simplify the problem of finding the
magnetic flux - crossing a surface
-
5Instructional Objectives (Continued)
- 13. Apply Gauss' law for the electric field in
integral form, - Ampere's circuital law in integral form,
the law of - conservation of charge, and symmetry
considerations, to - find the line integral of the magnetic
field intensity - around a closed path, given an arrangement
of point - charges connected by wires carrying
currents - 14. Apply Gauss law for the electric field in
integral form to - find the electric fields for symmetrical
charge - distributions
- 15. Apply Amperes circuital law in integral
form, without - the displacement current term, to find the
magnetic fields - for symmetrical current distributions
6- 2.1 The Line Integral
- (EEE, Sec. 2.1 FEME, Sec. 2.1)
7- The Line Integral
- Work done in carrying a charge from A to B in an
electric field
8(Voltage between A and B)
9 Line integral of E from A to B.
Line integral of E around the closed path C.
102-9
If then
is independent of the path from A to
B (conservative field)
112-10
2-10
along the straight line paths,
from (0, 0, 0) to (1, 0, 0), from (1, 0, 0) to
(1, 2, 0) and then from (1, 2, 0) to (1, 2, 3).
122-11
- From (0, 0, 0) to (1, 0, 0),
- From (1, 0, 0) to (1, 2, 0),
13- From (1, 2, 0) to (1, 2, 3),
-
14 15Review Questions
- 2.1. How do you find the work done in moving a
test charge - by an infinitesimal distance in an
electric field? - 2.2. What is the amount of work involved in
moving a test - charge normal to the electric field?
- 2.3. What is the physical interpretation of the
line integral of - E between two points A and B?
- 2.4. How do you find the approximate value of the
line - integral of a vector field along a given
path? How do you - find the exact value of the line integral?
- 2.5. Discuss conservative versus nonconservative
fields, - giving examples.
16Problem S2.1. Evaluation of line integral around
a closed path in Cartesian coordinates
17Problem S2.2. Evaluation of line integral around
a closed path in spherical coordinates
18 2.2 The Surface Integral (EEE, Sec. 2.2 FEME,
Sec. 2.2)
192-18
The Surface Integral Flux of a vector crossing a
surface
Flux (B)(DS)
Flux 0
202-19
Surface integral of B over S.
212-20
Surface integral of B over the closed surface
S.
D2.4 (a)
22(b)
23(c)
24 25Review Questions
- 2.6. How do you find the magnetic flux crossing
an - infinitesimal surface?
- 2.7. What is the magnetic flux crossing an
infinitesimal - surface oriented parallel to the
magnetic flux density - vector?
- 2.8. For what orientation of an infinitesimal
surface relative - to the magnetic flux density vector is
the magnetic flux - crossing the surface a maximum?
- 2.9. How do you find the approximate value of
the surface - integral of a vector field over a given
surface? How do - you find the exact value of the surface
integral? - 2.10. Provide physical interpretation for the
closed surface - integrals of any two vectors of your
choice., -
26Problem S2.3. Evaluation of surface integral over
a closed surface in Cartesian coordinates
27- 2.3 Faradays Law
- (EEE, Sec. 2.3 FEME, Sec. 2.3)
28 29Voltage around C, also known as electromotive
force (emf) around C (but not really a force),
Magnetic flux crossing S,
Time rate of decrease of magnetic flux crossing
S,
30Important Considerations (1) Right-hand screw
(R.H.S.) Rule The magnetic flux crossing the
surface S is to be evaluated toward that
side of S a right-hand screw advances as it is
turned in the sense of C.
31- (2) Any surface S bounded by C
- The surface S can be any surface bounded by C.
For example -
- This means that, for a given C, the values of
magnetic flux crossing all possible surfaces
bounded by it is the same, or the magnetic flux
bounded by C is unique.
32- (3) Imaginary contour C versus loop of wire
- There is an emf induced around C in either
case by the setting up of an electric field. A
loop of wire will result in a current flowing
in the wire. - (4) Lenzs Law
- States that the sense of the induced emf is
such that any current it produces, if the
closed path were a loop of wire, tends to oppose
the change in the magnetic flux that produces
it.
33- Thus the magnetic flux produced by the
induced current and that is bounded by C must
be such that it opposes the change in the
magnetic flux producing the induced emf. - (5) N-turn coil
- For an N-turn coil, the induced emf is N times
that induced in one turn, since the surface
bounded by one turn is bounded N times by the
N-turn coil. Thus
34where ? is the magnetic flux linked by one turn.
35D2.5
(a)
362-35
Lenzs law is verified.
372-36
2-36
(b)
382-37
2-37
(c)
39E2.2 Motional emf concept
conducting rails
conducting bar
40This can be interpreted as due to an electric
field induced in the moving bar, as viewed by
an observer moving with the bar, since
41- where
- is the magnetic force on a charge Q in the bar.
Hence, the emf is known as motional emf.
42Review Questions
- 2.11. State Faradays law.
- 2.12. What are the different ways in which an emf
is induced - around a loop?
- 2.13. Discuss the right-hand screw rule
convention - associated with the application of
Faradays law. - 2.14. To find the induced emf around a planar
loop, is it - necessary to consider the magnetic flux
crossing the - plane surface bounded by the loop?
Explain. - 2.15. What is Lenz law?
- 2.16. Discuss briefly the motional emf concept.
- 2.17. How would you orient a loop antenna in
order to receive - maximum signal from an incident
electromagnetic wave - which has its magnetic field linearly
polarized in the - north-south direction?
-
43Problem S2.4. Induced emf around a rectangular
loop of metallic wire falling in the presence of
a magnetic field
44Problem S2.5. Induced emf around a rectangular
metallic loop revolving in a magnetic field
45- 2.4 Ampéres Circuital Law
- (EEE, Sec. 2.4 FEME, Sec. 2.4)
46 472-46
Magnetomotive force (only by analogy with
electromotive force),
Current due to flow of charges crossing S,
Displacement flux, or electric flux, crossing S,
48 Time rate of increase of displacement flux
crossing S, or, displacement current crossing S,
Right-hand screw rule. Any surface S bounded by
C, but the same surface for both terms on the
right side.
49- Three cases to clarify Ampéres circuital law
- (a) Infinitely long, current carrying wire
No displacement flux
50(b) Capacitor circuit (assume electric field
between the plates of the capacitor is confined
to S2)
51 52 53Displacement current emanating from a closed
surface (current due to flow of charges
emanating from the same closed surface)
542-53
D2.9 (a) Current flowing from Q2 to Q3.
552-54
- (b) Displacement current emanating from the
- spherical surface of radius 0.1 m and
centered at Q1. - (c) Displacement current emanating from the
spherical - surface of radius 0.1 m and centered at Q3.
56- Interdependence of Time-Varying Electric and
Magnetic Fields
57 58Radiation from Hertzian Dipole
59Review Questions
- 2.18. State Amperes circuital law.
- 2.19. What is displacement current? Compare and
contrast - displacement current with current due to
flow of - charges, giving an example.
- 2.20. Why is it necessary to have the
displacement current - term on the right side of Amperes
circuital law? - 2.21. Is it meaningful to consider two different
surfaces - bounded by a closed path to compute the
two different - currents on the right side of Amperes
circuital law to - find the line integral of H around the
closed path? - 2.22. When can you say that the current in a wire
enclosed by - a closed path is uniquely defined? Give
two examples.
60Review Questions (Continued)
- 2.23. Give an example in which the current in a
wire enclosed - by a closed path is not uniquely
defined. - 2.24. Discuss the relationship between the
displacement - current emanating from a closed surface
and the current - due to flow of charges emanating from
the same closed - surface.
- 2.25. Discuss the interdependence of time-varying
electric - and magnetic fields through Faradays
law and - Amperes circuital law, and, as a
consequence, the - principle of radiation from a wire
carrying time-varying - current.
-
61Problem S2.6. Finding the displacement current
emanating from a closed surface for a given
current density J
62Problem S2.7. Finding the rms value of current
drawn from a voltage source connected to a
capacitor
63- 2.5 Gauss Laws
- (EEE, Sec. 2.5 FEME, Secs. 2.5, 2.6)
64- Gauss Law for the Electric Field
- Displacement flux emanating from a closed
surface S charge contained in the volume
bounded by S charge enclosed by S.
r
65- Gauss Law for the Magnetic Field
- Magnetic flux emanating from a closed
surface S 0.
66- P2.21 Finding displacement flux emanating from a
surface - enclosing charge
- (a)
- Surface of cube bounded by
67- (b)
- Surface of the volume x gt 0, y gt 0, z gt 0,
and (x2 y2 z2) lt 1.
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70Review Questions
- 2.26. State Gauss law for the electric field.
- 2.27. How do you evaluate a volume integral?.
- 2.28. State Gauss law for the magnetic field.
- 2.29. What is the physical interpretation of
Gauss law for the - magnetic field.
71Problem S2.8. Finding the displacement flux
emanating from a surface enclosing charge
72Problem S2.9. Application of Gauss law for the
magnetic field in integral form
732.6 The Law ofConservation of Charge(EEE, Sec.
2.6 FEME, Sec. 2.5)
74- Law of Conservation of Charge
r(t)
75 2-74
- Summarizing, we have the following
- Maxwells Equations
(1)
(2)
(3)
(4)
76- Law of Conservation of Charge
- (4) is, however, not independent of (1), whereas
(3) follows from (2) with the aid of (5).
(5)
77E2.3
(Ampéres Circuital Law)
(Gauss Law for the electric field and symmetry
considerations)
78(Law of Conservation of Charge)
79Review Questions
- 2.30. State the law of conservation of charge..
- 2.31. How do you evaluate a volume integral?.
- 2.32. Summarize Maxwells equations in integral
form for - time-varying fields.
- 2.33. Which two of the Maxwells equations are
independent? - Explain..
80Problem S2.10. Combined application of several
of Maxwells equations in integral form
812.6 Application to Static Fields(EEE, Sec. 2.7)
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93Review Questions
- 2.34. Summarize Maxwells equations in integral
form for - static fields.
- 2.35. Are static electric and magnetic fields
interdependent? - 2.36. Discuss briefly the application of Gauss
law for the - electric field in integral form to
determine the electric - field due to charge distributions.
- 2.37. Discuss briefly the application of Amperes
circuital - law in integral form for the static case
to determine the - magnetic field due to current
distributions.
94Problem S2.11. Application of Gauss law for the
electric field in integral form and symmetry
95Problem S2.12. Application of Amperes circuital
law in integral form and symmetry
96The End