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THERMOCHEMISTRY or Thermodynamics

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Title: THERMOCHEMISTRY or Thermodynamics


1
THERMOCHEMISTRY- A
By Dr. Hisham E Abdellatef
http//www.staff.zu.edu.eg/ezzat_hisham/browseMyFi
les.asp?path./userdownloads/physical20chemistry
20for20clinical20pharmacy/
2
THERMOCHEMISTRY
The study of heat released or required by
chemical reactions or heat changes caused by
chemical reactions
3
What is Energy?
4
Internal Energy (E)
  • Internal Energy, E, The total energy of a system
  • E(system) EK (system) EP (system)

5
Potential Kinetic Energy
  • Potential energy energy a motionless body has
    by virtue of its position.

6
Potential Kinetic Energy
Kinetic energy
Energy of Motion EK ½ mv2
  • i.e. the kinetic energy of an object depends on
  • both its mass and its speed.

7
Potential Kinetic Energy
Kinetic energy energy of motion.
8
Problem
  • What is the kinetic energy of a person whose
    mass is 130 lb (59.0 kg) traveling in a car at 60
    mph (26.8 m/s).
  • The SI unit of energy, kg.m2/s2, is the Joule.

9
UNITS OF ENERGY
  • 1 calorie heat required to raise temp. of 1.00
    g of H2O by 1.0 oC.
  • 1000 cal 1 kilocalorie 1 kcal
  • But we use the unit called the JOULE
  • 1 cal 4.184 joules

10
FIRST LAW OF THERMODYNAMICS
  • ?E q w

Energy is conserved!
?????????
11
SYSTEM
?E q w
12
  • 1st Law of Thermodynamics
  • Energy can neither created not destroyed, only
    transformed from one form to another

13
System and Surroundings
  • In chemical reactions, heat is often transferred
    from the system to its surroundings, or vice
    versa.
  • The substance or mixture of substances under
    study in which a change occurs is called the
    thermodynamic system (or simply the system.)
  • The surroundings are everything outside of the
    thermodynamic system.

14
SURROUNDINGS
HEAT
HEAT
HEAT
HEAT
SYSTEM
SYSTEM
EXOTHERMIC
ENDOTHERMIC
15
Exothermic
If ?E lt 0, Efinal lt Einitial
cellular respiration of glucose
16
Endothermic
If ?E gt 0, Efinal gt Einitial
Photosynthesis is an endothermic reaction
(requires energy input from sun)
17
Heat of Reaction
  • An exothermic process is a chemical reaction or
    physical change in which heat is evolved (q is
    negative).
  • An endothermic process is a chemical reaction or
    physical change in which heat is absorbed (q is
    positive).

18
Exothermic
Endothermic
6.2
19
Enthalpy Diagrams
  • Values of DH are measured experimentally.
  • Negative values indicate exothermic reactions.
  • Positive values indicate endothermic reactions.

An increase in enthalpy during the reaction DH
is positive.
A decrease in enthalpy during the reaction DH is
negative.
20
Exothermic Examples
  • Oxidation wooden splint burning (giving off
    light, heat, CO2, H2O
  • Burning H2 in air,
  • body reactions,
  • dissolving metals in acid,
  • mixing acid and water,
  • sugar dehydration

21
Endothermic Examples
  • Electrolysis (breaking water down into H2 and O2
    by running electricity in it)
  • Photosynthesis, pasteurization, canning
    vegetables
  • 2 H2 O2 ? 2H2O energy
  • 4 g 32 g ? 36 g 136 600 cal
  • 2H2O energy ? 2H2 O2
  • 36 g 136 600 cal ? 4g 32 g

22
Changes in Internal Energy
  • If ?E gt 0, Efinal gt Einitial
  • Therefore, the system absorbed energy from the
    surroundings.
  • This energy change is called endergonic.

23
Changes in Internal Energy
  • If ?E lt 0, Efinal lt Einitial
  • Therefore, the system released energy to the
    surroundings.
  • This energy change is called exergonic.

24
Enthalpy (H) of the reaction(Comes from Greek
for heat inside)
  • the sum of internal energy and the product of
    this pressure and volume.
  • H E PV
  • E is the internal energy,
  • P is the pressure and
  • V is the volume of the system.
  • It is also called heat content.
  • ?H H product H reactants Hp Hr

25
Calculation of ?H from ?E
  • When the system changes at constant pressure, the
    change in enthalpy, ?H, is
  • ?H ?(E PV)
  • ?H ?E P?V
  • At constant pressure and temperature
  • The enthalpy of a chemical is measured in
    kilojoules per mole (kJmol-1).

26
?H ?E P?V
For solid and liquid
?H ?E
  • At constant volume

27
  • In case of gases
  • ?H ?E P?V (I)
  • ?V ?n x V
  • ?n no of moles of products - no of moles of
    reactants
  • Px?V PVx?n (II)
  • But PV RT (for one mole of gas)
  • Putting RT in place of PV in equation (II) we get
  • P?V RT?n
  • Substituting the value of P AV in equation (I) we
    get
  • ?H ?E ?n RT

28
  • R 1.987 cal. (2 cal.)
  • or
  • 8.314 joules

29
Example- 1
  • The heat of combustion of ethylene at 17 C and
    at constant volume is -332.19 kcal. Calculate the
    heat of combustion at constant pressure
    considering water to be in liquid state (R 2
    cal.).

The chemical equation for the combustion of
ethylene is C2H4 3 O2 2CO2(g) 2H2O
(1) 1 mole 3 moles 2moles
negligible volume No. of moles of the
products 2 No. of moles of the reactants
4 ?n (2-4) -2
?H ?E ?n RT ?H -332.19 2 x
I0-3x -2 x 290 -333.3 kcal
Given that ?E-332. 19 kcal. T 27317
290k R2cal2xlO-3kcals.
30
Example 2
  • The heat of combustion of carbon monoxide at
    constant volume and at 17 C is -283.3 Kj.
    Calculate its heat of combustion at constant
    pressure(R 8.314 J degree-1 mole-1).

CO(g) ½ O2(g) ?CO2(g) 1 mole ½ mole 1
mole No. of mles of products 1 No. of moles of
reactants 1.5 n No. of moles of products - No.
of moles of reactants 1-1.5 -0.5 ?H ?E
?n x RT ?H -283.3 (-0.5x (8.314x10-3) x 290
- 283.3-1.20 -284.5 KJ Heat of combustion of CO
at constant pressure is -284.5 kJ.
Given that ?E -283.3 kJ T (27317) 290
K. R 8.314 J or 8.314x10-3 KJ
31
Problem
  • How much heat could be obtained by the combustion
    of 10.0 grams CH4burning in the presence of
    oxygen at constant pressure.

32
Thermochemical equations
  • factors which affects the quantity of heat
    evolved or absorbed during a physical or a
    chemical transformation.
  • Amount of the reactants and products
  • Physical state of the reactants and products
  • Temperature
  • Pressure

33
Thermochemical equations
  • It must essentially
  • be balanced
  • give the value of ?E or ?H corresponding to the
    quantities of substances given by the equation
  • mention the physical states of the reactants and
    products . The physical states are represented by
    the symbols (s), (L), (g) and (aq) for solid,
    liquid, gas and aqueous states respectively.

34
Example of thermochemical equation
  • H2 ½ O2 ? H2O ?H -68.32 Kcal
  • 1 mole of hydrogen reacts with 0.5 mole of
    oxygen, one mole of water is formed and 68.32
    Kcal of heats evolved at constant pressure.
  • But, not specify whether water is in the form of
    steam or liquid
  • H2 (g) ½ O2 (g)? H2O (L) ?H -68.32
    Kcal
  • H2 (g) ½ O2 (g)? H2O (g) ?H -57.80
    Kcal.

Effect of temperature ?????
35
Standard enthalpy change ?H.
  • The heat change at
  • 298 K and
  • one atmosphere pressure
  • is called the standard heat change or standard
    enthalpy change. It is denoted by ?H.

36
How do we relate change in temp. to the energy
transferred? Heat capacity (J/oC) heat
supplied (J)
temperature (oC)
Heat Capacity heat required to raise temp. of
an object by 1oC
37
Specific heat capacity is the quantity of energy
required to change the temperature of a 1g sample
of something by 1oC
38
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39
Variation of heat (or enthalpy) of reaction with
temperature Kirchoff's equations.
internal energies of the reactants and products.
  • 1. At constant volume,
  • ?EE2-E1
  • Differentiating this equation with respect to
    temperature at constant volume, we get

40
Kirchoff's equations.
  • But we have already seen that

heat capacities
heat capacities of the products and reactants
Integrating between temperature T l and T2 ,
we have
?E2- ?E1 ? E2 -?E1 ? Cv
(T2-T1) (3)
41
Kirchoff's equations.
  • 2. At constant pressure

  ?HH2-H1
And finely . ?H2- ?H1 ?Cp (T2-T1) (6)
42
Example 3 3
  • The heat of reaction
  • ½ H2 ½ Cl2 HCl at 27 C is -22.1
    Kcal.
  • Calculate the heat of reaction at 77C. The
    molar heat capacities at constant pressure at 27
    C for hydrogen, chlorine and HCl are 6.82, 7.70
    and 6.80 cal mol-1, respectively.

Here ½ H2 ½Cl- ? HCl ? H -22.1 Kcal ? Cp
Heat capacities of products - Heat capacities of
reactants 6.80-½(6.82) ½ (7.70) 6.80 -
7.26 -0.46 x 10-3 Kcal ?H2- ?H1 ?Cp
(T2-T1) ?H2 - (-22.1) (-0.46 x 10 -3) x 50
-21.123
T2 273 77 350 K T1 273 27 300 K
T2-T1 (350-300)K50K
43
HEAT CAPACITY
  • The heat required to raise an objects T by 1 C.

44
Specific Heat Capacity
  • How much energy is transferred due to T
    difference?
  • The heat (q) lost or gained is related to
  • a) sample mass
  • b) change in T and
  • c) specific heat capacity

45
Specific Heat Capacity
  • Substance Spec. Heat (J/gK)
  • H2O 4.184
  • Ethylene glycol 2.39
  • Al 0.897
  • glass 0.84

Aluminum
46
Specific Heat Capacity
  • If 25.0 g of Al cool from 310 oC to 37 oC, how
    many joules of heat energy are lost by the Al?

47
Specific Heat Capacity
  • If 25.0 g of Al cool from 310 oC to 37 oC, how
    many joules of heat energy are lost by the Al?

where ?T Tfinal - Tinitial q (0.897
J/gK)(25.0 g)(37 - 310)K q - 6120 J
Notice that the negative sign on q signals heat
lost by or transferred OUT of Al.
48
  • We define the standard state of a substance as
    the state of the pure substance at 1 atm pressure
    and the temperature of interest (usually 25 C).
  • The standard enthalpy change (?H) for a reaction
    is the enthalpy change in which reactants and
    products are in their standard states.
  • The standard enthalpy of formation (?Hf) for a
    reaction is the enthalpy change that occurs when
    1 mol of a substance is formed from its component
    elements in their standard states.

49
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End of par A
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