8.4 Similar Triangles - PowerPoint PPT Presentation

1 / 18
About This Presentation
Title:

8.4 Similar Triangles

Description:

Title: 8.4 Similar Triangles Author: Robert Spitz Last modified by: tshum Created Date: 2/13/2005 5:25:32 AM Document presentation format: On-screen Show – PowerPoint PPT presentation

Number of Views:199
Avg rating:3.0/5.0
Slides: 19
Provided by: Robert1809
Category:

less

Transcript and Presenter's Notes

Title: 8.4 Similar Triangles


1
8.4 Similar Triangles
  • Geometry
  • Ms. Shum

2
Objectives/Assignment
  • Identify similar triangles.
  • Use similar triangles in real-life problems such
    as using shadows to determine the height of the
    Great Pyramid

3
Identifying Similar Triangles
  • In this lesson, you will continue the study of
    similar polygons by looking at the properties of
    similar triangles.

4
Ex. 1 Writing Proportionality Statements
  • In the diagram, ?BTW ?ETC.
  • Write the statement of proportionality.
  • Find m?TEC.
  • Find ET and BE.

34
79
5
Ex. 1 Writing Proportionality Statements
  • In the diagram, ?BTW ?ETC.
  • Write the statement of proportionality.

34
ET
TC
CE


BT
TW
WB
79
6
Ex. 1 Writing Proportionality Statements
  • In the diagram, ?BTW ?ETC.
  • Find m?TEC.
  • ?B ? ?TEC, SO m?TEC 79

34
79
7
Ex. 1 Writing Proportionality Statements
  • In the diagram, ?BTW ?ETC.
  • Find ET and BE.

34
CE
ET
Write proportion.

WB
BT
3
ET
Substitute values.

12
20
3(20)
ET
Multiply each side by 20.

79
12
ET

5
Simplify.
Because BE BT ET, BE 20 5 15. So, ET
is 5 units and BE is 15 units.
8
Postulate 25 Angle-Angle Similarity Postulate
  • If two angles of one triangle are congruent to
    the two angles of another triangle, then the two
    triangles are similar.
  • If ?JKL ? ?XYZ and ?KJL ? ?YXZ, then ?JKL ?XYZ.

9
Ex. 2 Proving that two triangles are similar
  • Color variations in the tourmaline crystal shown
    lie along the sides of isosceles triangles. In
    the triangles, each vertex measures 52. Explain
    why the triangles are similar.

10
Ex. 2 Proving that two triangles are similar
  • Solution. Because the triangles are isosceles,
    you can determine that each base angle is 64.
    Using the AA Similarity Postulate, you can
    conclude the triangles are similar.

11
Ex. 3 Why a Line Has Only One Slope
  • Use the properties of similar triangles to
    explain why any two points on a line can be used
    to calculate slope. Find the slope of the line
    using both pairs of points shown.

12
Ex. 3 Why a Line Has Only One Slope
  • By the AA Similarity Postulate, ?BEC ?AFD, so
    the ratios of corresponding sides are the same.
    In particular,

CE
BE
By a property of proportions,

DF
AF
CE
DF

BE
AF
13
Ex. 3 Why a Line Has Only One Slope
  • The slope of a line is the ratio of the change in
    y to the corresponding change in x. The ratios

Represent the slopes of BC and AD, respectively.
and
CE
BE
DF
AF
14
Ex. 3 Why a Line Has Only One Slope
  • Because the two slopes are equal, any two points
    on a line can be used to calculate its slope.
    You can verify this with specific values from the
    diagram.

3-0
3

Slope of BC
4-2
2
6-(-3)
9
3


Slope of AD
6-0
6
2
15
Ex. 4 Using Similar Triangles
  • Aerial Photography. Low-level photos can be
    taken using a remote-controlled camera suspended
    from a blimp. You want to take an aerial photo
    that covers a ground of g of 50 meters. Use the
    proportion

n
f
h
f
n

h
g
g
To estimate the altitude h that the blimp should
fly at to take the photo. In the proportion, use
f 8 cm and n 3 cm. These two variables are
determined by the type of camera used.
16
Ex. 4 Using Similar Triangles
f
n

Write proportion.
h
g
n
f
8cm
3cm

Substitute values.
h
50 m
3h 400 h 133
Cross product property.
h
Divide each side by 3.
The blimp should fly at an altitude of about 133
meters to take a photo that covers a ground
distance of 50 meters.
g
17
Note
  • In Lesson 8.3, you learned that the perimeters of
    similar polygons are in the same ratio as the
    lengths of the corresponding sides. This concept
    can be generalized as follows If two polygons
    are similar, then the ratio of any two
    corresponding lengths (such as altitudes,
    medians, angle bisector segments, and diagonals)
    is equal to the scale factor of the similar
    polygons.

18
Ex. 5 Using Scale Factors
  • Find the length of the altitude QS.
  • Solution Find the scale factor of ?NQP to ?TQR.

NP
1212
24
3



TR
8 8
16
2
Now, because the ratio of the lengths of the
altitudes is equal to the scale factor, you can
write the following equation
QM
3

QS
2
Substitute 6 for QM and solve for QS to show that
QS 4
Write a Comment
User Comments (0)
About PowerShow.com