Hypergeometric Distribution - PowerPoint PPT Presentation

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Hypergeometric Distribution

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... = 0.5637 P(X2) = 1 [P(0)+P(1)] = 1-0.7982=0.2018 P(X 1) = 0.556 + 0.222 = 0.778 h(0;100,5,20) = (20 choose 0)(95 choose 5)/(100 choose 5) ... – PowerPoint PPT presentation

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Title: Hypergeometric Distribution


1
Hypergeometric Distribution
  • Example
  • Automobiles arrive in a dealership in lots of
    10. Five out of each 10 are inspected. For one
    lot, it is know that 2 out of 10 do not meet
    prescribed safety standards.
  • What is probability that at least 1 out of the 5
    tested from that lot will be found not meeting
    safety standards?
  • from Complete Business Statistics, 4th ed
    (McGraw-Hill)

2
  • This example follows a hypergeometric
    distribution
  • A random sample of size n is selected without
    replacement from N items.
  • k of the N items may be classified as successes
    and N-k are failures.
  • The probability associated with getting x
    successes in the sample (given k successes in the
    lot.)
  • Where,
  • k number of successes 2 n number in
    sample 5
  • N the lot size 10 x number found
  • 1 or 2

3
Hypergeometric Distribution
  • In our example,
  • _____________________________

4
Expectations of the Hypergeometric Distribution
  • The mean and variance of the hypergeometric
    distribution are given by
  • What are the expected number of cars that fail
    inspection in our example? What is the standard
    deviation?
  • µ ___________
  • s2 __________ , s __________

5
Your turn
  • A worn machine tool produced defective parts for
    a period of time before the problem was
    discovered. Normal sampling of each lot of 20
    parts involves testing 6 parts and rejecting the
    lot if 2 or more are defective. If a lot from the
    worn tool contains 3 defective parts
  • What is the expected number of defective parts in
    a sample of six from the lot?
  • What is the expected variance?
  • What is the probability that the lot will be
    rejected?

6
Binomial Approximation
  • Note, if N gtgt n, then we can approximate this
    with the binomial distribution. For example
  • Automobiles arrive in a dealership in lots of
    100. 5 out of each 100 are inspected. 2 /10
    (p0.2) are indeed below safety standards.
  • What is probability that at least 1 out of 5
    will be found not meeting safety standards?
  • Recall P(X 1) 1 P(X lt 1) 1 P(X 0)

Hypergeometric distribution Binomial distribution
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