Title: Types of Chemical Reactions and Solution Stoichiometry
1Types of Chemical Reactions and Solution
Stoichiometry
2The Bottom LineChapter 4
- Aqueous reactions account for virtually all
chemistry that takes place in living systems.
3Water, the Common Solvent
- Shape- bent 1050
- Electrons not distributed evenly
- Polar molecule
- Likes dissolve likes
- Polar and ionic
- Polar and polar
- Nonpolar and nonpolar
4Likes Dissolve Likes
- State whether each pair of substances will mix.
State Why or why not. - NaNO3 and H2O
- C6H14 and H2O
- I2 and C6H14
- I2 and H2O
5Polar Water Molecules Interact with the Positive
and Negative Ions of a Salt
6Water Also Dissolves Many Nonionic Substances
- Why is Ethanol (C2H5OH) very soluble in water?
- Ethanol contains a polar -OH bond like those in
water
7Polar Bond
8Water Does Not Dissolve all Nonionic Substances
- Water Polar
- Fats Nonpolar
- Likes dissolve likes
- Hydrophilic / Hydrophobic
9Solute / Solvent
- Solute
- If it and the solvent are present in the same
phase, it is the one in lesser amount. - If it and the solvent are present in different
phases, it is the one that changes phase. - The one that dissolves into the solvent.
- Aqueous solution means that water is the solvent.
10Strong, Weak, Non-Electrolytes
Electrolyte Conductivity Degree of Dissociation Examples
Strong High Total Strong acids, many salts, strong bases
Weak Low to moderate Partial Weak organic acids, weak bases
Non None Close to zero Highly nonpolar organic compounds like sugar, insoluble salts like AgCl
11Acids
- Strong acids - dissociate completely to produce
H in solution - hydrochloric and sulfuric acid
- Weak acids - dissociate to a slight extent to
give H in solution - acetic and formic acid
12Bases
- Strong bases - react completely with water to
give OH? ions. - sodium hydroxide
- Weak bases - react only slightly with water to
give OH? ions. - ammonia
13- Strong Acids-
- Virtually every molecule dissociates into given
ions - HCl, hydrochloric
- HBr, hydrobromic
- HI, hydroiodic
- HClO3, chloric
- HClO4, perchloric
- HNO3, nitric
- H2SO4, sulfuric
- Strong Bases- soluble compounds containing the
hydroxide (-OH-) ion - Group IA metal hydroxides LiOH, NaOH, KOH,
RbOH, CsOH - Heavy group 2 metal hydroxides Ca(OH)2,
Sr(OH)2, Ba(OH)2
14List whether each of the following is a strong,
weak, or nonelectrolyte
- HClO4
- C6H12
- LiOH
15Common Terms of Solution Concentration
- Stock - routinely used solutions prepared in
concentrated form. - Concentrated - relatively large ratio of solute
to solvent. (5.0 M NaCl) - Dilute - relatively small ratio of solute to
solvent. (0.01 M NaCl)
16The Composition of Solutions
- Molarity moles of solute / liters of solution.
- Example 4.1 pg. 96
- Calculate the molarity of a solution prepared by
bubbling 1.56 g of gaseous HCl into enough water
to make 26.8 mL of solution.
17Standard Solutions- a solution whose
concentration is accurately known.
- Example 4.4 pg. 97
- To analyze the alcohol content of a certain wine,
a chemist needs 1.00 L of an aqueous 0.200 M
K2Cr2O7 (potassium dichromate) solution.
Describe how to prepare this solution.
18Ion Concentration in Solutions
- Determine the molarity of Fe3 ions and SO42-
ions in a solution prepared by dissolving 48.05 g
of Fe2(SO4)3 in enough water to make 800. mL of
solution.
19Dilution- water is added to a stock concentrated
stock solution to achieve desired molarity.
- Concept
- Moles of solute after dilution moles of solute
before dilution - M1V1 M2V2
- Example
- What volume of 12 M hydrochloric acid must be
used to prepare 600. mL of a 0.30 M HCl solution?
20Types of Chemical Reactions
- Single Replacement
- Double Replacement
- Synthesis or Combination
- Decomposition
- Combustion
- Acid- Base
- Oxidation-Reduction (Redox)
21Single Replacement Reactions
- In these reactions, a free element reacts with a
compound to form another compound and release one
of the elements of the original compound in the
elemental state. There are two different
possibilities - One metal replaces another metal.
- One nonmetal replacement another nonmetal.
22General Format
- A BC ? B AC (when A is a metal)
- K (s) LiCl (aq) ? Li (s) KCl (aq)
- A BC ? C BA ( when A is a nonmetal)
- F2 (g) 2NaBr (aq) ? 2 NaF(aq) Br2 (l)
23SR Reaction Guidelines
- Not every metal can react and replace or displace
a metal out of solution.
24 SR Reaction Guidelines
- 2. A nonmetal can also replace another nonmetal
to form a compound. This replacement is usually
limited to the halogens (F2 , Cl2 , Br2 , I2 ).
The activity of the halogens decreases as you go
down the column on the periodic table.
25SRR Examples
- Mg Zn(NO3 )2 ?
- Mg LiNO3 ?
- Cl2 2NaBr ?
26SRR Net Ionic Equations
27Double Replacement Reactions
- During double replacement, the cations and anions
of two different compounds switch places, if and
only if an insoluble product is formed.
28General Format
29DR Reaction Guidelines
- All formulas of the products must be written
correctly. - These reactions never involve a change in ionic
charge. - A reaction takes place if
- A gas is formed (H2S, CO2 , SO2)
- A covalent substance is formed (H2O, NH3)
- A precipitate is formed (solubility guidelines!)
30Solubility Guidelines
Always Soluble Generally Soluble Generally Insoluble
Alkali metals ions (Li, Na, K, Rb, Cs), NH4, NO3-, ClO3-, ClO4-, C2H3O2- Cl-, Br-, I- Soluble except Ag, Pb2, Hg22 (AP/H). O2-, OH- insoluble except with alkali metals, and NH4, Ca2, Sr2, Ba2 (CBS) somewhat soluble.
F- Soluble except Ca2, Sr2, Ba2, Pb2, Mg2 (CBS-PM). CO32-, PO43-, S2-, SO32-, C2O42-, CrO42- insoluble except with alkali metals or NH4.
SO42- Soluble except Ca2, Sr2, Ba2, Pb2, (CBS/PBS).
31DRR Examples
- AgNO3 (aq) NaCl (aq)?
- CaCO3 (aq) HCl (aq) ?
- Pb(NO3 ) (aq) CuSO4 (aq) ?
32DRR Net Ionic Equations
33The Reaction of K2CrO4(aq) and Ba(NO3)2(aq)
34Describing Reactions in Solution
The Reaction of KCI(aq) and AgNO3(aq)
35Describing Reactions in Solution
- 1. Molecular equation (reactants and products
as compounds) - AgNO3(aq) NaCl(aq) ? AgCl(s) NaNO3(aq)
- 2. Complete ionic equation (all strong
electrolytes shown as ions) - Ag(aq) NO3?(aq) Na(aq) Cl?(aq) ?
AgCl(s) Na(aq) NO3?(aq)
36Describing Reactions in Solution (continued)
- 3. Net ionic equation (show only components
that actually react) - Ag(aq) Cl?(aq) ? AgCl(s)
- Na and NO3? are spectator ions.
37Write the molecular, complete ionic, and net
ionic forms
- Aqueous nickel (II) chloride reacts with aqueous
sodium hydroxide
38Selective Precipitation
- Precipitation reactions allow us to target
specific substances, and separate and recover
them from a solution. - Example
- A solution contains Ca2, Cu2, and Pb2. What
anions can we add, and in what order , to
separate and recover each cation?
39Stoichiometry of Precipitation Reactions
- Solving problems involving precipitates from
solutions makes use of molarity, solubility
rules, balancing equations, and limiting reactant
calculations. - Take a systematic approach!
- Example
- What mass of precipitate is produced when 35.mL
of a 0.250 M Fe(NO3)3 solution is mixed with 55
mL of a 0.180 M KOH solution?
40Synthesis or Combination Reactions
- In these reactions, two different molecules or
atoms unite to usually form a single substance. - Format
- A B ? AB
41Synthesis Reaction Guidelines
- Direct union of two elements will produce a
binary compound. - Metallic oxides and carbon dioxide react to
produce carbonates. - Binary salts and oxygen react to produce
chlorate. - Metallic oxides and water react to produce a
base. - Nonmetallic oxides and water react to produce an
acid.
42Synthesis Examples
- 2 Mg (s) O2 (g) ?
- Na2 O (s) CO2 (g) ?
- KCl (s) O2 (g) ?
- Na2 O (s) H2O (l) ?
- N2 O5 (s) H2O(l) ?
43Now You Try- Synthesis Reactions
- K (s) O2 (g)?
- SO2 (g) H2O (l) ?
- LiCl (s) O2 (g) ?
- K2 O (s) H2 O (l) ?
44Decomposition Reaction
- During decomposition, one compound splits apart
into two or more substances. These substances
can be elements or simpler compounds. - Reaction Format
- AB ? A B
45Decomposition Reaction Guidelines
- Binary compounds decompose into their component
elements. - Carbonates decompose into an oxide and carbon
dioxide. - Chlorates decompose into binary salt and oxygen.
- Bases decompose into oxide of their metal and
water. - Acids decompose into the oxide of the nonmetal
plus water. - Most require a large investment of energy in
either the form of heat or electricity.
46 Decomposition Examples
- 2 NaCl (s) ?
- 2 Na2 CO3 (s) ?
- Ba(ClO3 )2 (s) ?
- Ca(OH)2 (s) ?
- 2H3PO4 (aq) ?
47Now You Try- Decomposition Reacations
- Ba(OH)2 (s) ?
- Ca(ClO3 )2 (s) ?
- K2CO3 (s) ?
- H2 SO3 (aq) ?
48Combustion Reactions
- There are 2 types of combustion reactions,
- During a complete combustion reaction, a
hydrocarbon reacts with pure oxygen to produce
carbon dioxide and water as the only products. - During a partial or incomplete combustion
reactions, a hydrocarbon reacts with atmospheric
oxygen to produce carbon dioxide, water, carbon
monoxide, and carbon in the form of soot, smoke
or ash.
49Combustion Reaction Format
- Cx Hy (O) O2 (g) ? CO2 (g) H2 O(g)
(complete) - Cx Hy (O) O2 (g) ? CO2 (g) H2 O(g)
CO C (incomplete)
50Combustion Reaction Example
- 2C6 H6 (g) 15 O2 (g) ?
51Now You Try- Combustion Reactions
- Assume all are complete combustion unless
otherwise stated. - 1. C3 H6 O2 ?
- 2. C3 H8 O2 ?
- 3. C6 H12 O6 O2 ?
- 4. C9 H20 O2 ?
52Acid / Base Reactions
- Acid / Base reactions are a specialized double
replacement reaction. Where the cation from the
base hooks up with the anions from the acid to
form a salt and water. - Acids are usually compounds that contain loosely
held hydrogen ions. Follow the pattern HX, where
X is an anion. - Bases are compounds that contain loosely held
hydroxide ions. They follow the pattern YOH,
where Y is a metal cation.
53Acid / Base Reaction Examples
- 1. HCl (aq) NaOH (aq) ?
- 2. H2 C3H3O2 (aq) Mg(OH)2 (aq)?
54Acids and Bases Neutralize Each Other
- When acids and bases react, they form water and a
salt. The acid is neutralized by the base and
the base is neutralized by the acid. - The concentration of an acid can be determined by
reacting a set volume with a known concentration
of base through a process called titration.
55Acid / Base Titration
Ma Va Mb Vb
56Key Titration Terms
- Titrant - solution of known concentration used
in titration - Analyte - substance being analyzed
- Equivalence point - enough titrant added to
react exactly with the analyte - Endpoint - the indicator changes color so you
can tell the equivalence point has been reached.
57Acid-Base Neutralization Reactions
- Example 1
- How many mL of a 0.800M NaOH solution is needed
to just neutralize 40.00 mL of a 0.600M HCl
solution?
58- Example 2
- You wish to determine the molarity of a solution
of sodium hydroxide. To do this, you titrate a
25.00 mL aliquot of your sample, which has had 3
drops of phenolphthalein indicator added so that
it is pink, with 0.1067 M HCl. The sample turns
clear (indicating that the NaOH (aq) has been
precisely neutralized by the HCl solution) after
the addition of 42.95 mL of the HCl. Calculate
the molarity of your NaOH solution.
59Now You Try- Titration Problems
- A volume of 90. mL of 0.20 M HBr neutralizes a
60. mL sample of NaOH solution. What is the
concentration of the NaOH solution? - A volume of 46 mL of 0.40 M NaOH neutralizes an
80. mL sample of HCN solution. What is the
concentration of the HCN? - A volume of 60. mL of 0.60 M HBr solution
neutralizes a 80. mL sample of Ca(OH)2 solution.
What is the concentration of Ca(OH)2 ?
60Oxidation /Reduction ReactionREDOX
- REDOX reactions primarily involve the transfer of
electrons between 2 chemical species. - In these reactions, the oxidation numbers of the
reactants change.
61Oxidation-Reduction Reactions
- Redox reactions involve a transfer of electrons.
In order to determine if an electron has been
transferred, one must be able to assign oxidation
states. - Assigning oxidation states to an element in a
molecule requires knowledge of a set of rules.
These rules are outlined on page 120 of your text.
62Rules for Assigning Oxidation States
- OS of an atom in an element is 0.
- Na (s), O2 (g)
- 2. OS of a monatomic ion is the same as its
charge. - Na OS 1, Cl- OS -1
- 3. In its covalent compounds with nonmetals,
hydrogen is assigned an OS of 1. - HCl, NH3, H2O.
- 4. Oxygen is assigned an OS of -2 in its
covalent compounds. - CO, CO2, SO2, SO3
- The exception to this rules occurs in peroxides
(compounds contains the O22- group), where each
oxygen is assigned an OS of -1. - H2O2
63- 5. In binary compounds the element with the
greater attraction for the electrons in the bond
is assigned a negative OS equal to its charge in
its ionic compounds. - HF, NH3, H2S, HI
- 6. The sum of the oxidation states must be zero
for an electrically neutral compound and must be
equal to the overall charge for an ionic species. - NH4, CO32-
64Determine the Oxidation States
- Fe2O3 2Al --gt Al2O3 2Fe
- Iron (III) gains 3 electrons to become elemental
iron. - Elemental aluminum lost 3 electrons to become the
aluminum ion.
65LEO the Lion Says GEROIL RIG
- Loss of Electrons is Oxidation
- Gain of Electrons is Reduction
- Oxidation Involves Loss
- Reduction Involves Gain
66A Summary of an Oxidation-Reduction Process
LEO the lion says GER or OIL RIG
67Fe2O3 2Al --gt Al2O3 2Fe
- Iron (III) ion gained electrons. It has been
reduced. - The aluminum lost electrons. It has been
oxidized. - The oxidizing agent is the species that is
reduced (Iron (III)). - The reducing agent is the species that is
oxidized (aluminum).
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69Which Atoms Undergo Redox?
- 2H2 (g) O2 (g) --gt 2H2O (g)
- Zn (s) Cu2(aq) --gt Zn2 (aq) Cu(s)
- 2AgCl (s) H2 (g) --gt 2H (aq) 2Ag(s) 2Cl-
(aq) - 2MnO4- (aq) 16H (aq) 5C2O42- (aq) --gt
2Mn2(aq) 10 CO2 (g) 8 H2O (l)
70Now You Try- Redox Reactions
- What is the oxidation number of nitrogen in the
following molecules? - NO2 b. NO3- c. N2O5 d. NH4
71Now You Try- Redox Reactions
- K (s) MgCl2 (aq) ?
- 2. In the reaction above determine the following
- The products of the reaction.
- The substance oxidized.
- The substance reduced.
- The oxidizing agent.
- The reducing agent.
72The Half-Reaction Method for Balancing Redox
Reactions
- Half Reactions the two parts of an oxidation
reduction reaction, one representing oxidation,
the other reduction. - Balance the following equation in acid solution
using the half reaction method. - Cu(s) HNO3 (aq) --gt Cu2 (aq) NO(g)
73Cu(s) HNO3 (aq) --gt Cu2 (aq) NO(g)
- Identify and write equations for the half
reactions. - Copper is being oxidized Cu --gt Cu2
- Nitrogen is being reduced HNO3 --gt NO
74- 2. Balance each half reaction.
- (oxidation) Cu --gt Cu2 2e-
- (reduction) HNO3 --gt NO
- Balance all atoms that are neither oxygen nor
hydrogen. - Balance oxygens by adding water to the side that
needs oxygen. - HNO3 --gt NO 2H2O
- c. Balance hydrogens by adding H to the side
that needs hydrogen. - HNO3 3H --gt NO 2H2O
- d. Balance charges by adding electrons to the
side that is more positive - HNO3 3H 3 e - --gt NO 2H2O
75- 3. Equalize the electron transfer. The same
number of electrons must be gained as are lost in
the reaction - 3 Cu --gt 3Cu2 6 e-
- 2HNO3 6H 6e- --gt 2NO 4H2O
- 4. Add the half reactions and cancel
appropriately to get a complete redox reaction. - 3 Cu --gt 3Cu2 6 e-
- 2HNO3 6H 6e- --gt 2NO 4H2O
- 3Cu 2HNO3 6H 6e- --gt 3Cu2 2NO 4 H2O
6e- - Cancel electrons on both sides and double check.
Do we have the correct number of electrons on
both sides?
76Cr2O72- (aq) NO (g) --gt Cr3 (aq) NO3- (aq)
77Balancing Redox Equations in Basic Solutions
- Balance the following equation (it is already
balanced in acid) assuming it is now in basic
solution. - Cr2O72-(aq) 2NO (g) 6H (aq) --gt 2Cr3 (aq)
2NO3- (aq) 3H2O (l) - We need to get rid of excess H, because OH- is
the dominate acid base related species. - Solution add 6 OH- to both sides of the
equation. - Cr2O72-(aq) 2NO (g) 6H (aq) 6OH- --gt
2Cr3 (aq) 2NO3- (aq) 3H2O (l) 6OH- - Cr2O72-(aq) 2NO (g) 6 H2O --gt 2Cr3 (aq)
2NO3- (aq) 3H2O (l) 6OH- - Cancel waters on both sides
- Cr2O72-(aq) 2NO (g) 3 H2O --gt 2Cr3 (aq)
2NO3- (aq) 6OH- (aq)
78Simple Oxidation-Reduction Titrations
- Balance the redox equation.
- Determine the moles of titrant.
- Use the balanced redox equation to determine the
number of moles of unknown. - Convert from moles of unknown to grams, percent,
molarity, or whatever.
79- The use of potassium permanganate (KMnO4) as an
oxidizing agent is described in your text. A
0.0483M KMnO4 solution was used to titrate a
solution containing 0.8329 g of impure calcium
oxalate, CaC2O4. If 30.25 mL of the KMnO4
solution was required to reach the titration
endpoint, calculate the percent purity of the
CaC2O4. - MnO4- (aq) C2O42- (aq) --gt Mn2 (aq) CO2 (g)