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Single i.v. bolus dose into one compartment. Dose = 400 mg. V = 100 Litres. K = 0.3 h-1 ... For a single i.v. bolus injection into a one compartment system ... – PowerPoint PPT presentation

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Title: Pharmacokinetics lecture 5 Contents ...


1
Pharmacokinetics lecture 5Contents ...
  • Single i.v. bolus into a one
  • compartment system
  • Area Under the Curve

2
Single i.v. bolus dose into one compartment
D
Dose 400 mg V 100 Litres K 0.3 h-1 Initial
conc (C0) 4 mg/L
V
K
3
D 400 mg V 100 L K 0.3 h-1
Mass 4 mg/L x 100 L 400 mg Rate of elim 400
mg x 0.3 h-1 120 mg/h
4 3 2 1 0
Mass 2 mg/L x 100 L 200 mg Rate of elim 200
mg x 0.3 h-1 60 mg/h
Conc (mg/L)
Mass 1 mg/L x 100 L 100 mg Rate of elim 100
mg x 0.3 h-1 30 mg/h
Exponential curve
0 2 4 6 8
10
Time (h)
4
Half-life and K
4 3 2 1 0
C0 4 mg/L
Inefficiently eliminated
Efficiently eliminated
Conc (mg/L)
Low K / Long t ½
t ½ 2.3 h
t ½ 5.4 h
High K / Short t ½
0 2 4 6 8
10
Time (h)
5
Predicting concentration at a given time point
C0
4 3 2 1 0
Ct C0.e-Kt
Conc (mg/L)
Ct
t
0 2 4 6 8
10
Time (h)
6
Predicting concentration at a given time point
D 10 mg V 50 L K 0.05
h-1 What conc. after 12 hours? C0 D/V
10mg/50L 0.2mg/L 200µg/L Ct C0 .e-Kt
200µg/L . e-0.05h-1 x 12h 200µg/L .
e-0.6 200µg/L . 0.55 110 µg/L
7
Predicting the time to reach a given concentration
C0 5 mg/L K 0.02h-1 How long until C 1
mg/L? Ct C0 .e-Kt Ct / C0 e-Kt 1/5
e-Kt 0.2 e-Kt (Take natural logs of both
sides) Ln(0.2) -Kt -1.609 -Kt (Drop minus
from both sides) 1.609 0.02h-1 x t t 1.609 /
0.02h-1 80.5 hours
8
Area Under the Curve (AUC)
3 2 1 0
  • Area under the concentration
  • versus time curve
  • Area Under the Curve
  • AUC

Conc (mg/L)
0 2 4 6 8
10
Time (h)
9
Units of AUC
3 2 1 0
Area is height x width Units are mg/L x h
mg.L-1.h Usually rearranged as
mg.h .L-1 In general Mass.Time.Volume-1
Conc (mg/L)
0 2 4 6 8
10
Time (h)
10
AUC between time limits
3 2 1 0
AUC assumed to mean AUC 0- (The complete area
under the whole curve)
AUC2-4h
Conc (mg/L)
0 2 4 6 8
10
Time (h)
11
Relationship between AUC, Dose and Clearance
Total amount of drug entering the body. (More
drug greater AUC)
AUC F.D Cl
Efficiency of removal. (Greater clearance
lower AUC)
12
Calculation of AUC following single i.v. bolus
AUC F.D Cl e.g. D 5 mg Cl
4 L/h AUC 1.0 x 5mg 4
L/h 1.25 mg.h.L-1
Conc (mg/L)
0 2 4 6 8
10
Time (h)
13
Example calculation
1mg of drug is administered (i.v) at time
zero. Vol Dis 50 L. Elim rate constant
0.015h-1 What will blood concentration be 2 days
later? Tip Calculate C0 first, then Ct.
14
Answer
C0 D/V 1mg / 50L 0.02 mg/L
20 µg/L Ct C0.e-Kt 20µg/L x e-0.015h-1
x 2days 20µg/L x e-0.015h-1 x 48h
20µg/L x e-0.72 20µg/L x 0.487
9.7µg/L
Mixed units
2 calculator is no good. Need a good one!
15
Terms with which you should be familiar ...
Area Under the Curve (AUC)
16
What you should beable to do
  • For a single i.v. bolus injection into a one
    compartment system ...
  • Describe why the graph of concentration versus
    time adopts its distinctive shape
  • Calculate remaining concentration from initial
    concentration, elimination rate constant and time
    elapsed (etc)
  • Apply appropriate units to an AUC
  • Calculate AUC following single i.v. injection
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