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Fire Dynamics I

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Physical Chemistry: Ideal Gas Law ... Physical Chemistry: Vapour Pressure of Liquids. In the open, liquids evaporate forming vapours ... – PowerPoint PPT presentation

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Title: Fire Dynamics I


1
Fire Dynamics I
  • Lecture 2
  • Physical Chemistry
  • Chemical Reactions
  • Jim Mehaffey
  • 82.575 or CVG7300

2
  • Physical Chemistry Chemical Reactions
  • Outline
  • Flaming combustion
  • Ideal gas law
  • Vapour pressure of liquids
  • Chemical reactions
  • Chemical equations

3
  • Flaming Combustion
  • Premixed Flames
  • Fuel mixed with air (O2) before burning
  • Examples Industrial burners dust suspensions
  • Provide insight into ignition flame processes
  • Diffusion Flames
  • Fuel and air (O2) initially separated but burn in
    region where they mix
  • Examples Gas jets // Combustible liquid or
    solids

4
  • Diffusion Flames
  • The Fire Triangle
  • HEAT
  • FUEL
    OXYGEN

5
  • Diffusion Flames
  • The Fire Tetrahedron
  • HEAT
  • REACTIONS
  • FUEL
    OXYGEN

6
  • Diffusion Flames

7
  • Rate of Burning (Mass Loss Rate)
  • Eqn (2-1)

8
  • Rating of Burning (Heat Release Rate)
  • Eqn (2-2)

9
  • Heat Release Rate
  • Eqn (2-3)
  • governs fire dynamics and depends on
  • material properties (LV and HC)
  • flame properties (? and )
  • heat transfer ( )

10
  • Combustion of Liquids
  • Flaming combustion occurs in gas phase
  • Volatile generated by evaporation
  • Molecular composition of volatile same as liquid
  • Heat of vaporization Heptane LV 0.55
    kJ / g Octane LV 0.60 kJ /
    g Styrene LV 0.64 kJ / g MMA LV
    0.52 kJ / g

11
  • Combustion of Solid
  • Combustible solids polymers (macro-molecules)
  • Thermoplastics melt before they burn (no char)
    (polyethylene, polystyrene, PMMA)
  • Thermosets char as they burn (most do not melt)
    (polyurethane, wood)
  • Flaming combustion occurs in gas phase

12
  • Combustion of Solids
  • Flaming combustion occurs in gas phase
  • Volatile created by thermal decomposition
  • Molecular composition of volatile is simpler than
    that of solid
  • Heat of gasification Polyethylene LV
    2.30 kJ / g Polystyrene LV 1.76 kJ /
    g PMMA LV 1.62 kJ / g Wood LV 1.80
    kJ / g

13
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14
  • Physical Chemistry Ideal Gas Law
  • Gas generated or heated by fire can be assumed
    to obey the ideal gas law
  • P V n R T Eqn (2-4)
  • P pressure (atm)
  • V volume (m3)
  • n number of moles (mol)
  • R 8.20575 x 10-5 m3 atm mol-1 K-1
  • T temperature (K)

15
  • Alternative Units
  • P V n R T Eqn (2-4)
  • P pressure (N m-2 Pa)
  • V volume (m3)
  • n number of moles (mol)
  • R 8.31431 J mol-1 K-1
  • T temperature (K)
  • 1 atm 101,325 Pa 101.325 kPa

16
  • Mole
  • Mole amount of a substance containing as many
    atoms or molecules as 12 g of Carbon-12
  • Mole 6.02 x 1023 atoms or molecules (Avagadro
    number)
  • Molecular weight
  • Mass of 1 mole of substance (g mol-1)

17
  • Ideal Gas Law
  • P V n R T Eqn (2-4)
  • Incorporates
  • Boyless Law PV constant at constant T
  • Gay-Lussacs Law V/T constant at constant P
  • Avogadros hypothesis equal Vs of different
    gases at the same T P contain the same
    number of molecules (moles)

18
  • Volume Occupied by One Mole if
  • P 1 atm n 1 mol T 293.17 K (20C)
  • Substituting into the ideal gas law yields
  • V 0.0241 m3
  • 24.1 litres
  • ? 5 gal (imp)
  • At atmospheric pressure and 20C this volume is
    occupied by 28 g of N2, 32 g of O2 or 44 g of CO2

19
  • Molecular Weight of Air
  • One mole of dry air is composed of
  • 0.7809 mol of N2
  • 0.2095 mol of O2
  • 0.0093 mol of Ar
  • 0.0003 mol of CO2
  • MW(air) 0.7809 x 28 0.2095 x 32
  • 0.0093 x 39.9 0.0003 x 44
  • MW(air) 28.95 (g mol-1)

20
  • Atomic Weights of Selected Elements

21
  • Density of Air
  • P 1 atm and T 293.17 K (20C)
  • ? M / V
  • n MW / V
  • P MW / R T Eqn (2-5)
  • 1203 g m-3
  • 1.203 kg m-3

22
  • Ideal Gas Mixtures
  • Partial Pressure Pi
  • P n R T / V
  • (? ni) R T / V
  • ? Pi Eqn (2-6)
  • Mole fraction (species i)
  • ni / n
  • Number (volume) concentration (species i)
  • Vi ni / n x 106 ppm Eqn (2-7)

23
  • Proportion of O2 in Air
  • Mole fraction of O2 in air
  • Number (volume) concentration of O2 in air
  • Mass fraction of O2 in air
  • Density of O2 in air (20C)

24
  • Variations in ?, T and P
  • Wide range of temperatures in gas associated with
    fire (flame, smoke, heated gas, ambient)
  • Large differences in densities between hot gas
    ambient (induce buoyant flows)
  • Pressure differences draw air into base of fire
    cause exchange of gas through vents in bldgs
  • For fires burning in atmosphere, pressure
    differentials are small (15 Pa ? 1.5 x 10-4 atm)
  • First approximation Ignore pressure
    differentials

25
  • Variations in ? T
  • ? P MW / R T Eqn (2-5)
  • For fires burning in atmosphere, P ? 1 atm
  • Assume MW ? 28.95. Fire gases are mainly N2
  • ? T P MW / R constant
  • ?1 T1 ?2 T2 Eqn (2-8)
  • Temperature differences between adjacent masses
    of gas induce density differences
  • Density differences between adjacent masses of
    gas induce buoyant flows

26
  • Physical Chemistry Vapour Pressure of Liquids
  • In the open, liquids evaporate forming vapours
  • In a closed vessel, at equilibrium vapour
    pressure no net evaporation occurs
  • Flammability of vapour-air mixture depends on
    partial pressure of vapour
  • Correlation for closed vessels
  • log10 p0 F 0.2185 E / T Eqn (2-9)
  • p0 equilibrium vapour pressure (mm Hg) (760 mm
    Hg 1 atm)
  • E and F constants (see next slide)
  • T temperature (K)

27
  • Equilibrium Vapour Pressure of Liquids

28
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29
  • Liquid Fuel Mixtures
  • Hydrocarbon mixtures approximate ideal
    solutions for which Raoults law applies
  • pA xA Eqn (2-10)
  • pA partial pressure of A above liquid
    mixture
  • equilibrium vapour pressure of pure A
  • xA mole fraction of A in the liquid mixture
  • xA nA / (nA nB )

30
  • Chemical Reactions
  • HC heat of combustion when fuel at T 25C P
    1 atm is completely oxidized
  • Complete (stoichiometric) combustion of propane
  • C3H8 5 O2 ? 3 CO2 4 H2O Eqn (2-11)
  • Gross heat of combustion (liquid water produced)
  • HC 2220 kJ / mol
  • Net heat of combustion (water vapour produced)
  • HC 2044 kJ / mol (appropriate for fire)
  • Difference is latent heat of evaporation of water
    (44 kJ / mol H2O)

31
  • Net Heat of Combustion of C3H8
  • Can be expressed per unit mole as
  • HC 2044 kJ / mol
  • 1 mole of propane has mass 44 g, so can write
  • HC 2044 kJ mol-1 / (44 g mol-1) 46.45
    kJ / g
  • Since combustion of 1 mole of C3H8 consumes 5
    moles of O2 or 5 x 32 g 160 g of O2
  • 2044 kJ / (160 g of O2) 12.78 kJ
    / g of O2
  • Since the mass fraction of O2 in air is 0.232
  • HC,air 12.78 kJ/g(O2) x 0.232 g(O2)/g(air)
    2.96 kJ/g(air)

32
  • Net Heat of Combustion of Fuels at 25C
  • Net heat of combustion of combustibles is
    measured in an oxygen bomb calorimeter.
  • Combustion initiated in a pure O2 atmosphere
    with a surplus of O2
  • Results in complete combustion

33
  • Net Heat of Combustion of Fuels at 25C

34
  • Heat of Combustion / g(O2)
  • Heat of combustion / g(O2) is almost constant
  • For most organic liquids and gases
  • 12.72 ? 3 kJ / g(O2)
  • For most polymers
  • 13.02 ? 4 kJ / g(O2)
  • O2 consumption calorimetry used to calculate heat
    release rate in many fire tests.
  • For ventilation-controlled fires, heat release
    rate estimated from supply rate of fresh air and
  • 3 kJ / g(air)

35
  • Incomplete Combustion
  • Values on slide 33 are for complete combustion in
    oxygen bomb calorimeter. Fuel burns in pure O2
    and CO2 H2O are generated.
  • Real fires burn in air which causes incomplete
    combustion (CO soot are also generated)
  • Reduction in combustion efficiency means net heat
    of combustion is not released
  • Example, combustion of octane
  • heat of combustion in O2 44.77 kJ / g
  • heat of combustion in air 41.0 kJ / g

36
  • Stoichiometric Air Requirements
  • 1 mol (air) 0.21 mol (O2) 0.79 mol (N2)
  • 0.21 1 mol (O2) 3.76 mol (N2)
  • Empirical formula for PMMA is C5H8O2n
  • Complete (stoichiometric) combustion of PMMA
  • C5H8O2 6 O2 6 x 3.76 N2 ? 5 CO2 4 H2O
    22.56 N2
  • 1 mol (PMMA monomer) requires 28.56 mol air
  • MW(PMMA monomer) 100 MW(air) 28.95
  • Therefore 1 g (PMMA) requires 8.27 g (air)

37
  • Stoichiometric Air Requirements
  • Equation for complete combustion of fuel in air
  • 1 g fuel r g air ? (1 r) g products
    Eqn (2-12)
  • r stoichiometric air requirement
  • r 8.27 for PMMA

38
  • References
  • D. Drysdale, An Introduction to Fire
    Dynamics,Wiley, 1999, Chap 1
  • A. Tewardson, Generation of Heat and Chemical
    Compounds in Fires" Section 3 / Chapter 4, SFPE
    Handbook, 2nd Ed. (1995)
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