Title: Physics 111: Lecture 1 Mechanics for Physicists and Engineers Agenda for Today
1Physics 111 Lecture 1Mechanics for Physicists
and EngineersAgenda for Today
- Advice
- Scope of this course
- Measurement and Units
- Fundamental units
- Systems of units
- Converting between systems of units
- Dimensional Analysis
- 1-D Kinematics (review)
- Average instantaneous velocity and acceleration
- Motion with constant acceleration
2Course Info Advice
- See info on the World Wide Web (heavily used in
Physics 111) - Go to http//www.physics.uiuc.edu and follow
courses link to the Physics 111 homepage - Course has several components
- Lecture (me talking, demos and Active learning)
- Discussion sections (group problem solving)
- Homework sets, Web based
- Labs (group exploration of physical phenomena)
- If you miss a lab or discussion you should always
try to make it up as soon as possible in another
section!! - The first few weeks of the course should be
review, hence the pace is fast. It is important
for you to keep up!
3Lecture Organization
- Three main components
- Lecturer discusses class material
- Follows lecture notes very closely
- Lecturer does as many demos as possible
- If you see it, you gotta believe it!
- Look for the symbol
- Students work in groups on conceptualActive
Learning problems - Usually three per lecture
4Scope of Physics 111
- Classical Mechanics
- Mechanics How and why things work
- Classical
- Not too fast (v ltlt c)
- Not too small (d gtgt atom)
- Most everyday situations can be described in
these terms. - Path of baseball
- Orbit of planets
- etc...
5Units
- How we measure things!
- All things in classical mechanics can be
expressed in terms of the fundamental units - Length L
- Mass M
- Time T
- For example
- Speed has units of L / T (i.e. miles per hour).
- Force has units of ML / T2 etc... (as you will
learn).
6Length
- Distance Length (m)
- Radius of visible universe 1 x 1026
- To Andromeda Galaxy 2 x 1022
- To nearest star 4 x 1016
- Earth to Sun 1.5 x 1011
- Radius of Earth 6.4 x 106
- Sears Tower 4.5 x 102
- Football field 1.0 x 102
- Tall person 2 x 100
- Thickness of paper 1 x 10-4
- Wavelength of blue light 4 x 10-7
- Diameter of hydrogen atom 1 x 10-10
- Diameter of proton 1 x 10-15
7Time
- Interval Time (s)
- Age of universe 5 x 1017
- Age of Grand Canyon 3 x 1014
- 32 years 1 x 109
- One year 3.2 x 107
- One hour 3.6 x 103
- Light travel from Earth to Moon 1.3 x 100
- One cycle of guitar A string 2 x 10-3
- One cycle of FM radio wave 6 x 10-8
- Lifetime of neutral pi meson 1 x 10-16
- Lifetime of top quark 4 x 10-25
8Mass
- Object Mass (kg)
- Milky Way Galaxy 4 x 1041
- Sun 2 x 1030
- Earth 6 x 1024
- Boeing 747 4 x 105
- Car 1 x 103
- Student 7 x 101
- Dust particle 1 x 10-9
- Top quark 3 x 10-25
- Proton 2 x 10-27
- Electron 9 x 10-31
- Neutrino 1 x 10-38
9Units...
- SI (Système International) Units
- mks L meters (m), M kilograms (kg), T
seconds (s) - cgs L centimeters (cm), M grams (gm), T
seconds (s) - British Units
- Inches, feet, miles, pounds, slugs...
- We will use mostly SI units, but you may run
across some problems using British units. You
should know how to convert back forth.
10Converting between different systems of units
- Useful Conversion factors
- 1 inch 2.54 cm
- 1 m 3.28 ft
- 1 mile 5280 ft
- 1 mile 1.61 km
- Example convert miles per hour to meters per
second
11Dimensional Analysis
- This is a very important tool to check your work
- Its also very easy!
- Example
- Doing a problem you get the answer distance
- d vt 2 (velocity x time2)
- Units on left side L
- Units on right side L / T x T2 L x T
- Left units and right units dont match, so answer
must be wrong!!
12Lecture 1, Act 1Dimensional Analysis
- The period P of a swinging pendulum depends only
on the length of the pendulum d and the
acceleration of gravity g. - Which of the following formulas for P could be
correct ?
P 2? (dg)2
(a)
(b)
(c)
Given d has units of length (L) and g has
units of (L / T 2).
13Lecture 1, Act 1 Solution
- Realize that the left hand side P has units of
time (T ) - Try the first equation
(a)
Not Right !!
(a)
(b)
(c)
14Lecture 1, Act 1 Solution
(b)
Not Right !!
(a)
(b)
(c)
15Lecture 1, Act 1 Solution
(c)
This has the correct units!! This must be the
answer!!
(a)
(b)
(c)
16Motion in 1 dimension
- In 1-D, we usually write position as x(t1 ).
- Since its in 1-D, all we need to indicate
direction is or ?. - Displacement in a time ?t t2 - t1 is
?x x(t2) - x(t1) x2 - x1
x
some particles trajectoryin 1-D
x2
??x
x1
t
t1
t2
??t
171-D kinematics
- Velocity v is the rate of change of position
- Average velocity vav in the time ??t t2 - t1
is
x
trajectory
x2
??x
Vav slope of line connecting x1 and x2.
x1
t
t1
t2
??t
181-D kinematics...
- Consider limit t1 t2
- Instantaneous velocity v is defined as
x
so v(t2) slope of line tangent to path at t2.
x2
??x
x1
t
t1
t2
??t
191-D kinematics...
- Acceleration a is the rate of change of
velocity - Average acceleration aav in the time ?t t2 -
t1 is
- And instantaneous acceleration a is defined as
using
20Recap
- If the position x is known as a function of time,
then we can find both velocity v and acceleration
a as a function of time!
x
t
v
t
a
t
21More 1-D kinematics
- We saw that v dx / dt
- In calculus language we would write dx v dt,
which we can integrate to obtain
- Graphically, this is adding up lots of small
rectangles
v(t)
...
displacement
t
221-D Motion with constant acceleration
- High-school calculus
- Also recall that
- Since a is constant, we can integrate this using
the above rule to find - Similarly, since we can
integrate again to get
23Recap
Plane w/ lights
- So for constant acceleration we find
x
t
v
t
a
t
24Lecture 1, Act 2Motion in One Dimension
- When throwing a ball straight up, which of the
following is true about its velocity v and its
acceleration a at the highest point in its path? - (a) Both v 0 and a 0.
- (b) v ? 0, but a 0.
- (c) v 0, but a ? 0.
y
25Lecture 1, Act 2Solution
- Going up the ball has positive velocity, while
coming down it has negative velocity. At the top
the velocity is momentarily zero. - Since the velocity is
- continually changing there must
- be some acceleration.
- In fact the acceleration is caused
by gravity (g
9.81 m/s2). - (more on gravity in a few lectures)
- The answer is (c) v 0, but a ? 0.
x
t
v
t
a
t
26Derivation
27Average Velocity
v
v
vav
v0
t
t
28Recap
Washers
- For constant acceleration
29Problem 1
- A car is traveling with an initial velocity v0.
At t 0, the driver puts on the brakes, which
slows the car at a rate of ab
30Problem 1...
- A car is traveling with an initial velocity v0.
At t 0, the driver puts on the brakes, which
slows the car at a rate of ab. At what time tf
does the car stop, and how much farther xf does
it travel?
v0
ab
x 0, t 0
v 0
x xf , t tf
31Problem 1...
- Above, we derived v v0 at
- Realize that a -ab
- Also realizing that v 0 at t tf
- find 0 v0 - ab tf or
- tf v0 /ab
32Problem 1...
- To find stopping distance we use
- In this case v vf 0, x0 0 and x xf
33Problem 1...
- So we found that
- Suppose that vo 65 mi/hr 29 m/s
- Suppose also that ab g 9.81 m/s2
- Find that tf 3 s and xf 43 m
34Tips
- Read !
- Before you start work on a problem, read the
problem statement thoroughly. Make sure you
understand what information is given, what is
asked for, and the meaning of all the terms used
in stating the problem. - Watch your units !
- Always check the units of your answer, and carry
the units along with your numbers during the
calculation. - Understand the limits !
- Many equations we use are special cases of more
general laws. Understanding how they are derived
will help you recognize their limitations (for
example, constant acceleration).
35Recap of todays lecture
- Scope of this course
- Measurement and Units (Chapter 1)
- Systems of units (Text 1-1)
- Converting between systems of units (Text 1-2)
- Dimensional Analysis (Text 1-3)
- 1-D Kinematics (Chapter 2)
- Average instantaneous velocity and
acceleration (Text 2-1, 2-2) - Motion with constant acceleration (Text 2-3)
- Example car problem (Ex. 2-7)
- Look at Text problems Chapter 2 6, 12, 56, 119