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I-5 Special Electrostatic Fields

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Charging a conductor means to introduce in it some excess charges of the same polarity. ... Electrostatic xerox copier. 8/7/09. 14. Homework ... – PowerPoint PPT presentation

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Title: I-5 Special Electrostatic Fields


1
I-5 Special Electrostatic Fields
2
Main Topics
  • Electric Charge and Field in Conductors.
  • The Field of the Electric Dipole.
  • Behavior of E. D. in External Electric Field.
  • Examples of Some Important Fields.

3
A Charged Solid Conductor
  • Charging a conductor means to introduce in it
    some excess charges of the same polarity.
  • These charges repel themselves and since they can
    move freely as far as the surface, in
    equilibrium, they must end on a surface.
  • In equilibrium there must be no forces acting on
    the charges, so the electric field inside is zero
    and also the whole solid conductor must be an
    equipotential region.

4
A Hollow Conductive Shell I
  • In equilibrium again
  • the charges must remain on the surface.
  • the field inside is zero and the whole body is an
    equipotential region.
  • The above means the validity of the Gauss law.
  • To proof that lets return to the Gauss law.

5
The Gauss Law Revisited I
  • Let us have a positive point charge Q and a
    spherical Gaussian surface of radius r centered
    on it. Let us have a radial field
  • EkQ/rp
  • The field lines are everywhere parallel to the
    outer normals, so the total flux is
  • ?e E(r)A Qr2-p/?0
  • If p?2 the flux would depend on r !

6
The Gauss Law Revisited II
  • The validity of the Gauss law ? p 2.
  • By using a concept of the solid angle it can be
    shown that the same is valid if the charge Q is
    anywhere within the volume surrounded by the
    spherical surface.
  • By using the same concept it can be shown that
    the same is actually valid for any closed
    surface.
  • It is roughly because from any point within some
    volume we see any closed surface confining it
    under the solid angle of 4?.

7
A Hollow Conductive Shell II
  • Let first the shell be spherical. Then the charge
    density ? on its surface is constant.
  • From symmetry, in the center the intensities from
    all the elementary surfaces that make the whole
    surface always compensate themselves and E 0.
  • For any other point within the sphere E 0 they
    compensate themselves only if p 2.
  • Again, using the concept of solid angle, it can
    be shown, the same is valid for any closed
    surface.

8
A Hollow Conductive Shell III
  • Conclusion The existence of a zero electric
    field within a charged conductive shell is
    equivalent to the validity of the Gauss law.
  • This is the principle of
  • experimental proof of the Gauss law with a very
    high precision p 2 2.7 ? 3.1 10-16.
  • of shielding and grounding.

9
Electric Field Near Any Conducting Surface
  • Let us take a small cylinder and submerge it into
    the conductor so its axis is perpendicular to the
    surface.
  • The electric field
  • within the conductor is zero
  • outside is perpendicular to the surface
  • A non-zero flux is only through the outer cup ?
  • E ?/?0.
  • Beware the edges! ? is not generally constant!

10
The Electric Dipole I
  • An electric fields can be produced even if the
    total charge is zero by so called electric
    multipoles. Their fields are not centrosymmetric
    and decrease generally faster than the field of
    the single point charge.
  • The simplest one is the electric dipole. It is
    the combination of two charges of the same
    absolute value but different sign Q and Q
    separated by some distance l. We define the
    dipole moment
  • p Ql .

11
The Electric Dipole II
  • Electric dipoles (multipoles) are important
    because they are responsible for all the
    electrical behavior of neutral matter.
  • The components of material (molecules, domains)
    can be polar or their dipole moment can be
    induced.

12
Behavior of the Electric Dipole in External
Electric Fields
  • In uniform electric fields the dipoles are
    subjected to a torque which is trying to turn
    their dipole moments in the direction of the
    field lines
  • In non-uniform electric fields the dipoles are
    also dragged.

13
Some Examples
  • The field of homogeneously charged sphere
  • Parallel uniformly charged planes
  • Electrostatic xerox copier

14
Homework
  • Now, you should be able to solve all the problems
    due Monday!

15
Things to read
  • Repeat the chapters 21, 22, 23 !
  • Try to see the physicist Bible
  • The Feynman Lectures on Physics

16
The Solid Angle I
  • Let us have a spherical surface of radius r. From
    its center we see an element of the surface da
    under a solid angle d?

The whole surface we see under
17
The Solid Angle II
  • If there is a point charge Q in the center the
    elementary flux through da is

Since the last fraction is d?, the total flux is

18
Intensities near more curved surfaces are
stronger!
  • Lets have a large and a small conductive spheres
    R, r connected by a long conductor and lets
    charge them. Charge is distributed between them
    to Q, q so that the system is equipotential


19
Potential of Electric Dipole I
  • Let us have a charge Q at the origin and a Q in
    l. What is the potential in r? We use the
    superposition principle and the gradient

20
Potential of Electric Dipole II
  • The first two terms cancel
  • The potential has axial symmetry with the dipole
    in the axis and axial anti-symmetry perpendicular
    to it. It decreases with 1/r2!


21
Electric Dipole - The Torque
  • Let us have a uniform field with intensity E.
    Forces on both charges contribute simultaneously
    to the torque
  • The general relation is a cross product


22
Electric Dipole - The Drag
  • Let us have a non-uniform field with intensity E
    with the dipole parallel to a field line (-Q in
    the origin).
  • Generally


23
The vector or cross product I
  • Let ca.b
  • Definition (components)

The magnitude c
Is the surface of a parallelepiped made by a,b.
24
The vector or cross product II
The vector c is perpendicular to the plane made
by the vectors a and b and they have to form a
right-turning system.
?ijk 1 (even permutation), -1 (odd), 0 (eq.)
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