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Chemical Thermodynamics

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1 mole at 1 atm and any temperature (usually 25 ) Elements are not '0' ... ?G = ?H T ?S (standard conditions, 1 mole, 1 atm pressure. Calculations ... – PowerPoint PPT presentation

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Title: Chemical Thermodynamics


1
Chemical Thermodynamics
  • Chapter 19 in Brown, LeMay, and Bursten

2
Thermodynamics vs Kinetics
  • Thermodynamics answers the question Will the
    reaction proceed spontaneously as written?
  • Kinetics answers the question How fast will it
    proceed?
  • Ice melting at room temperature vs. nail rusting.

3
Exothermic Reactions
  • Most of these are spontaneous at room temperature
    and pressure (nail).
  • Why? System releases energy to the surroundings
    and ends up at a lower energy state.
  • What about ice melting?
  • Something else must be involved.

4
Entropy
  • Nature tends to move spontaneously from more
    ordered to more random states.
  • Many examples in life
  • Chemistry example (two gases)
  • Sometimes called degrees of freedom

5
S
  • Symbolized S
  • The more random, the greater the value of S
  • ?S Sfinal Sinitial (state function)
  • Increasing entropy solid to liquid to gas
  • Third Law of Thermodynamics Entropy of a pure
    crystalline solid at 0 K is 0
  • What was the first law?

6
Standard Molar Entropy S
  • Can be determined precisely
  • 1 mole at 1 atm and any temperature (usually 25
    )
  • Elements are not 0!!
  • All values of elements and molecules are
    positive!
  • Ions are calculated relative to H(aq) 0, so
    ions may be negative.

7
Trends
  • Solid to liquid to gas increase in entropy
  • Same structure, entropy increases with increasing
    mass (CH4 vs. C2H6)
  • You can use the table of standard values the same
    way that you did ?H problems.
  • Can also predict sign.

8
Second Law of Thermodynamics
  • In a spontaneous process, there is a net increase
    in entropy, taking into account both system and
    surroundings.
  • Example Using the table for rusting, you get a
    ?S, but the change in entropy of the
    surroundings must be greater than that value
    because it is spontaneous.
  • Very difficult to calculate

9
Gibbs Free Energy
  • Combines H and S
  • Symbolized G
  • Represents energy that is free (released from
    system) to do useful work.
  • G H TS

10
Sign
  • - ?G spontaneous reaction
  • ?G reverse will occur spontaneously
  • ?G 0 means that the system is at equilibrium
  • Reactions at constant temperature and pressure go
    in such a direction as to decrease the free
    energy of the system.

11
Gibbs-Helmholtz Equation
  • ?G ?H T ?S
  • Two forces that contribute to making a reaction
    spontaneous
  • Exothermic (forming a strong bond)
  • Increase in disorder
  • ?G ?H T ?S (standard conditions, 1 mole, 1
    atm pressure

12
Calculations
  • Can use equation to find ?G if you use a table
    to calculate the other two.
  • This will tell about spontaneity.
  • Usually we do not use tables to do ?G directly
    because they are temperature-dependent and
    difficult to calculate.

13
?G at Other Temperatures
  • Only change T in the equation because S and H
    vary little.
  • ?G varies greatly with temperature.
  • What would a plot of ?G vs T look like?
  • Line with ?S slope and y intercept of ?H.

14
Four Situations
?G ?H T ?S
15
?G Under Any Condition
  • General equation under any conditions
  • ?G ?G RT(lnQ)
  • What is Q
  • Called reaction Quotient
  • T in Kelvin, R 8.31 J/K, atm and molarity
  • Example

16
?G and Equilibrium
  • Look at the equation again
  • ?G ?G RT(lnQ)
  • What is ?G for equilibrium?
  • ?G -RT(lnK)
  • You can use this to calculate K
  • Read about coupling reactions at the end of
    Masterton chapter.
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