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3'2 Polynomial Functions and Their Graphs

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Title: 3'2 Polynomial Functions and Their Graphs


1
3.2 Polynomial Functions and Their Graphs
MAC 1140 Mrs. Kessler
2
Definition of a Polynomial Function
  • Let n be a nonnegative integer and let
  • an, an-1,, a2, a1, a0, be real numbers with
  • an ¹ 0. The function defined by
  • f (x) anxn an-1xn-1 a2x2 a1x a0
  • is called a polynomial function of x of degree n.
    The number an, the coefficient of the variable to
    the highest power, is called the leading
    coefficient.

3
Smooth, Continuous Graphs
Two important features of the graphs of
polynomial functions are that they are smooth and
continuous. By smooth, we mean that the graph
contains only rounded curves with no
sharp corners. By continuous, we mean that the
graph has no breaks and can be drawn without
lifting your pencil from the rectangular
coordinate system..
4
Smooth, Continuous Graphs
What functions have you studied that are not
smooth?
y sin(x)
y tan(x)
What functions have you studied that are not
continuous?
5
End Behavior of Polynomial
  • We can determine the end behavior of a
    polynomial by analyzing the coefficient of the
    leading term.
  • What does the expression end behavior mean?

6
The Leading Coefficient Test
7
The Leading Coefficient Test
Every odd polynomial will end like either f(x)
x3 or f(x)
-x3
These are easy to remember!
8
The Leading Coefficient Test
9
The Leading Coefficient Test
Every even polynomial will end like either f(x)
x2 or f(x)
-x2
These are also easy to remember!
10
Example 1
Use the Leading Coefficient Test to determine the
end behavior of the graph of Graph the quadratic
function f (x) 2x3 3x2 - x - 3.
Rises right
Because the degree is odd and the leading
coefficient, 2, is positive, the graph falls to
the left and rises to the right
Falls left
11
Example 2
Find the zeros of a polynomial algebraically
Algebraically, find all zeros of f (x) -x4
6x3 - 9x2.
Solution We find the zeros of f by setting
f (x) equal to 0.
-x4 6x3 - 9x2 0 We now have a
polynomial equation.
-x2(x2 - 6x 9) 0 Factor out -x2.
x2(x - 3)2 0 Factor completely.
x2 0 or (x - 3)2 0 Set each
factor equal to zero.
x 0 x 3 Solve for
x.
12
Example 3
Find the zeros of a polynomial using the TI 83/84
Use the calculator to find all zeros of f (x)
-x4 4x3 - 4x2.
Enter function into Y1 2nd CALC 2
If you dont remember how to do this, please come
in for help or download a help sheet.
13
Multiplicity and x-Intercepts
  • If a factor of a polynomial occurs more than one,
    this is called multiplicity. We say the root or
    the zero has multiplicity n, where n is the
    number of times it repeats.
  • y (x 3)2(x 5) (2x-1)3
  • 3 is a root of multiplicity 2
  • ½ is a root of multiplicity 3

14
Multiplicity and x-Intercepts
  • If r is a zero (root) of even multiplicity, then
    the graph touches the x-axis and turns around at
    r. If r is a zero of odd multiplicity, then the
    graph crosses the x-axis at r.
  • Regardless of whether a zero is even or odd,
    graphs tend to flatten out at zeros with
    multiplicity greater than two.

15
Multiplicity and x-Intercepts
  • Regardless of whether a zero is even or odd,
    graphs tend to flatten out at zeros with
    multiplicity greater than two.
  • Graph y (x -1)5(x - 5)2

make Ymin -50 Ymax 300
16
Example 4
  • Find the x-intercepts and multiplicity of
  • f(x) 2(x 2)2(x - 3)
  • What are the zeros?
  • What is each ones multiplicity?
  • x -2 is a zero of multiplicity 2 meaning it
    just touches the x-axis.
  • x 3 is a zero of multiplicity 1
  • - it crosses

17
Graphing a Polynomial Function see page 299
  • f (x) anxn an-1xn-1 an-2xn-2 ¼ a1x a0
    (an ¹ 0)
  • Use the Leading Coefficient Test to determine the
    graph's end behavior.
  • Find x-intercepts by setting f (x) 0 and
    solving the resulting polynomial equation. If
    there is an x-intercept at r as a result of (x -
    r)k in the complete factorization of f (x),
    then
  • a. If k is even, the graph touches the x-axis
    at r and turns around.
  • b. If k is odd, the graph crosses the x-axis
    at r.
  • c. If k gt 1, the graph flattens out at (r, 0).
  • 3. Find the y-intercept by setting x equal to 0
    and computing f (0).

18
Graphing a Polynomial Function
  • f (x) anxn an-1xn-1 an-2xn-2 ¼ a1x a0
    (an ¹ 0)
  • Use symmetry, if applicable, to help draw the
    graph
  • a. y-axis symmetry f (-x) f (x)
  • b. Origin symmetry f (-x) - f (x).
  • Use the fact that the maximum number of
    turning points of the graph is n - 1 to check
    whether it is drawn correctly.

19
Example 5
Graph by hand f (x) x4 - 2x2 1.
f(x) (x 1)2(x - 1)2
Step 1 Determine end behavior.
20
Example 5 contd
Graph f (x) x4 - 2x2 1.
f(x) (x 1)2(x - 1)2
Solution
Step 2 Find the x-intercepts (zeros of the
function) by setting f (x) 0.
x4 - 2x2 1 0
(x2 - 1)(x2 - 1) 0 Factor.
(x 1)(x - 1)(x 1)(x - 1) 0 Factor
completely.
(x 1)2(x - 1)2 0 Express the
factoring in more compact notation.
(x 1)2 0 or (x - 1)2 0 Set
each factor equal to zero.
x -1 x 1 Solve
for x.
21
Example 5 contd
Graph f (x) x4 - 2x2 1.
f(x) (x 1)2(x - 1)2
Solution
Step 2 We see that -1 and 1 are both repeated
zeros with multiplicity 2. Because of the even
multiplicity, the graph touches the x-axis at -1
and 1 and turns around. Furthermore, the graph
tends to flatten out at these zeros with
multiplicity greater than one
22
Example 5 contd
f(x) (x 1)2(x - 1)2
Graph f (x) x4 - 2x2 1.
Step 3 Find the y-intercept. Replace x with
0 in f (x) -x 4x - 1.
f (0) 04 - 2 02 1 1
There is a y-intercept at 1, so the graph passes
through (0, 1).
23
Example 5 contd
Graph f (x) x4 - 2x2 1.
f(x) (x 1)2(x - 1)2
Step 4 Use possible symmetry to help draw the
graph. Our partial graph suggests y-axis
symmetry. Let's verify this by finding f (-x).
f (x) x4 - 2x2 1
f (-x) (-x)4 - 2(-x)2 1 x4 - 2x2 1
Because f (-x) f (x), the graph of f is
symmetric with respect to the y-axis. The
following figure shows the graph.
24
Example 5 contd
f(x) (x 1)2(x - 1)2
Graph f (x) x4 - 2x2 1.
Step 5 Use the fact that the maximum number
of turning points of the graph is n - 1 to check
whether it is drawn correctly. Because n 4, the
maximum number of turning points is 4 - 1, or 3.
Because our graph has three turning points, we
have not violated the maximum number possible.
25
Example 6 Use the methods learned to sketch by
hand
a. End behavior
b. x- intercepts
26
Ex. 6 contd. Use the methods learned to sketch
by hand
c. y - intercept
d. symmetry
None
e. max number of turning points
3 1 2
27
(No Transcript)
28
You try this!
Example 7
  • f(x) -x4 4x2

29
You try this!
Example 8
  • f(x) x3 x2-4x- 4
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