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Lecture 6 Capacitance and Capacitors Electrostatic Potential Energy

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Depends on the geometry of the conductors -the dielectric constant of the ... 2- assume Q Vab (in terms of Q) Q Vab. Step 1Chose coordinate system for given geometry ... – PowerPoint PPT presentation

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Title: Lecture 6 Capacitance and Capacitors Electrostatic Potential Energy


1
Lecture 6Capacitance and CapacitorsElectrostat
ic Potential Energy
  • Prof. Viviana Vladutescu

2
Capacitance
  • A conductor in electrostatic field is
    equipotential and charges distribute themselves
    on the surface such way that E0 inside the
    conductor Q on the surface is producing V

3
linear dependence
kC
4
Capacitance (of the isolated conducting body) -
is the electric charge that is added to the body
per unit increase in its electric potential (is a
constant of proportionality)
Depends on the geometry of the conductors
-the dielectric constant of the
medium between conductors

5
Capacitors
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Electrolytic capacitors
9
Determine capacitance
  • 1- assume Vab Q (in terms of Vab)
  • use boundary conditions
  • 2- assume Q Vab (in terms of Q)

10
Q Vab
  • Step 1Chose coordinate system for given geometry
  • Step 2 Assume Q and Q on the conductors
  • Step 3 Q E from DeE?s or
  • Step 4 E
  • Step 5 CQ/Vab

11
Example
12
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13
Vab Q
  • Step 1Chose coordinate system for given geometry
  • Step 2 Assume Vab between plates
  • Step 3 Vab E D (from Laplaces
    equation)
  • Step 4 Boundary conditions at each plate
  • conductor dielectric boundary
  • ?s
    Q
  • . Step 5 CQ/Vab

14
Example
15
There is no f and z variation
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Step 4
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Q on the inner conductor
Step 5
19
Series Connected Capacitors
Parallel Connected Capacitors
20
Electrostatic Potential Energy
21
  • Electric potential at a point in an electric
    field is the work required to bring a unit
    positive charge from infinity (at reference zero
    potential) to that point.

22
Now suppose we want to bring Q3 at R13 from
Q1 and R23 from Q2
23
-can be negative -represents only interaction
energy
24
For a group of N discrete charges at rest
For a continuous charge distribution of density ?
25
Electrostatic energy in terms of field quantities
Substitute ?
And by using
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Electrostatic Energy Density
27
Example
Along AB, W -q?V zero!

Equipotential surfaces are at right angles to
the electric field. Otherwise a force would act
and work would be done on the path A to B.For a
uniform electric field, equipotentials form
planes perpendicular to the field.
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