Polynomial Functions and Models - PowerPoint PPT Presentation

1 / 20
About This Presentation
Title:

Polynomial Functions and Models

Description:

A polynomial of degree n is a function of the form. P(x) = anxn an-1xn-1 ... a1x a0 ... Corner or cusp. End Behavior of Polynomials ... – PowerPoint PPT presentation

Number of Views:62
Avg rating:3.0/5.0
Slides: 21
Provided by: channingh
Category:

less

Transcript and Presenter's Notes

Title: Polynomial Functions and Models


1
Section 3.1
  • Polynomial Functions and Models

2
Polynomial Functions
  • A polynomial of degree n is a function of the
    form
  • P(x) anxn an-1xn-1 ... a1x a0
  • Where an 0. The numbers a0, a1, a2, . . .
    , an are
  • called the coefficients of the polynomial. The
    a0 is
  • the constant coefficient or constant term. The
  • number an, the coefficient of the highest power,
    is
  • the leading coefficient, and the term anxn is the
  • leading term.

3
Example of a Polynomial Function
4
Graphs of Polynomial Functions and Nonpolynomial
Functions
5
Graphs of Polynomials
  • Graphs are smooth curves
  • Degree greater than 2
  • ex. f(x) x3
  • These graphs will not have the following
  • Break or hole
  • Corner or cusp
  • Graphs are lines
  • Degree 0 or 1
  • ex. f(x) 3 or f(x) x 5
  • Graphs are parabolas
  • Degree 2
  • ex. f(x) x2 4x 8

6
End Behavior of Polynomials
  • End Behavior- a description of what happens as x
    becomes large in the positive and negative
    direction.
  • End Behavior is determined by
  • Term with the highest power of x
  • Sign of this terms coefficient

7
Even- and Odd-Degree Functions
8
The Leading-Term Test
9
Finding Zeros of a Polynomial
  • Zero- another way of saying solution
  • Zeros of Polynomials
  • Solutions
  • Place where graph crosses the x-axis
  • (x-intercepts)
  • Zeros of the function
  • Place where f(x) 0

10
X-Intercepts (Real Zeros)
  • A polynomial function of degree n will have at
    most n x-intercepts (real zeros).

11
Number of Turning Points (relative maxima/minima)
  • The number of relative maxima/minima of the
    graph of a polynomial function of degree n is at
    most n 1.
  • ex. f(x) x4 3x3 2x2 1
  • Determine number of relative maxima/minima
  • n 1 4 1 3

12
Using the Graphing Calculator to Determine Zeros
Graph the following polynomial function and
determine the zeros.
Before graphing, determine the end behavior and
the number of relative maxima/minima.
In factored form P(x) (x 2)(x 1)(x 3)²
13
MultiplicityIf (x-c)k, k 1, is a factor of a
polynomial function P(x) and
  • K is even
  • The graph is tangent to the x-axis at (c, 0)
  • K is odd
  • The graph crosses the x-axis at (c, 0)

14
Multiplicity
y (x 2)²(x - 1)³  Answer.    -2 is a root of
multiplicity 2, and 1 is a root of multiplicity
3.   These are the 5 roots -2,  -2,  1,  1,  1.
15
Multiplicity
y x³(x 2)4(x - 3)5 Answer.    0 is a root of
multiplicity 3, -2 is a root of multiplicity 4,
and 3 is a root of multiplicity 5.  
16
True or False?
  • 1.) The function
    must
  • have 1 real zero.
  • 2.) The function
    has no real zeros.
  • 3.) An odd degree polynomial function must have
    at least 1 real zero.
  • 4.) An even degree polynomial function must have
    at least 1 real zero.

17
To Graph a Polynomial
  • Use the leading term to determine the end
    behavior.
  • Find all its real zeros (x-intercepts).
  • Set y 0.
  • Use the x-intercepts to divide the graph into
    intervals and choose a test point in each
    interval to graph.
  • Find the y-intercept. Set x 0.
  • Use any additional information (i.e. turning
    points or multiplicity) to graph the function.

18
(No Transcript)
19
The Intermediate Value Theorem
  • Consider a polynomial function P(x) with the
    points (a, P(a)) and (b, P(b)) on the function.
  • For any P(x) with real coefficients, suppose
    that for a ? b, P(a) and P(b) are of opposite
    signs. Then the function has a real zero between
    a and b.

20
The Intermediate Value Theorem
  • In other words, if one point is above the
    x-axis and the other point is below the x-axis,
    then because P(x) is continuous and will have to
    cross the x-axis to connect the two points, P(x)
    must have a zero somewhere between a and b.
Write a Comment
User Comments (0)
About PowerShow.com