6'3 Inverse Functions - PowerPoint PPT Presentation

1 / 4
About This Presentation
Title:

6'3 Inverse Functions

Description:

The line of reflection is the line y = x, a 45 line drawn through the origin of ... 1 and g(x) = (1/3)x 1/3, check algebraically if these functions are inverses. ... – PowerPoint PPT presentation

Number of Views:18
Avg rating:3.0/5.0
Slides: 5
Provided by: msea1
Category:

less

Transcript and Presenter's Notes

Title: 6'3 Inverse Functions


1
6.3 Inverse Functions
  • To find an inverse of a function, switch the
    coordinates of the ordered pairs.
  • Example
  • Relation (0,-3), (1,-1), (2,1)
  • Inverse (-3,0), (-1,1), (1,2)
  • Therefore, an inverse is a reflection of the
    original relation.
  • The line of reflection is the line y x, a 45
    line drawn through the origin of the x-y plane.

2
Example
  • Find the inverse of f(x) 3x 1
  • Step 1 Replace f(x) with y.
  • y 3x 1 (graphing m 3/1, y-intercept
    (0,-1)
  • Step 2 Switch x and y.
  • x 3y 1
  • Step 3 Write equation in slope intercept form.
  • 3y 1 x
  • 3y 1 1 x 1
  • 3y x 1
  • 3y/3 x/3 1/3
  • y (1/3)x 1/3 (graphing m 1/3,
    y-intercept (0,1/3)

3
Graphing
  • Given y 3x 1, we found the inverse, y (1/3)x
    1/3
  • Graphically, we would have two lines.
  • Each line would be a reflection of the other over
    the line of reflection.

4
Verifying Inverses
  • Rule If f(g(x)) x and g(f(x)) x then f and g
    are inverses.
  • Example
  • Using the previous example f(x) 3x 1 and g(x)
    (1/3)x 1/3, check algebraically if these
    functions are inverses.
  • Solution
  • f(g(x)) 3 (1/3 x 1/3) 1 Replaced x with
    g(x).
  • x 1 1 x
  • g(f(x) 1/3 (3x 1) 1/3 Replaced x with
    f(x).
  • x 1/3 1/3 x
  • Since f(g(x)) x and g(f(x) x the functions
    are inverses.
Write a Comment
User Comments (0)
About PowerShow.com