Forces%20B/w%20Dislocations - PowerPoint PPT Presentation

About This Presentation
Title:

Forces%20B/w%20Dislocations

Description:

When the two dislocations are separated by large distance: The total elastic ... opposite signs will prefer to come together and annihilate (cancel) each other. ... – PowerPoint PPT presentation

Number of Views:108
Avg rating:3.0/5.0
Slides: 20
Provided by: drpete
Learn more at: https://eng.fsu.edu
Category:

less

Transcript and Presenter's Notes

Title: Forces%20B/w%20Dislocations


1
Forces B/w Dislocations
  • Consider two parallel (//) edge dislocations
    lying in the same slip plane.
  • The two dislocations can be of same sign or
    different signs
  • (a) Same Sign (on same slip plane)

2
  • When the two dislocations are separated by large
    distance The total elastic energy per unit
    length of the dislocation is given by
  • When dislocations are very close together The
    arrangement can be considered approximately a
    single dislocation with Burgers vector 2b
  • In order to reduce the total elastic energy,
    same sign dislocations will repel each other
    (i.e., prefer large distance separation).

(14.34)
(14.35)
3
  • Dislocations of opposite sign (on same slip
    plane)
  • If the dislocations are separated by large
    distance
  • If dislocations are close together Burgers
    vector b - b 0
  • Hence, in order to reduce their total energy,
    dislocations of opposite signs will prefer to
    come together and annihilate (cancel) each other.

4
  • The same conclusions are obtained for dislocation
    of mixed orientations
  • (a) and (b) above can be summarized as
  • Like dislocations repel and
  • unlike dislocations attract

5
  • Dislocations Not on the Same Slip Plane
  • Consider two dislocations lying parallel to the z
    (x3) -axis
  • In order to solve this
  • (a) We assume that dislocation I is at the
    origin
  • (b) We then find the interaction force on
    dislocation II due to dislocation I

II
I
6
  • Recall Eqn. 14.29
  • Note that the dislocation at the origin
    (dislocation I) provides the stress field, while
    the Burgers vector and the dislocation length
    belongs to dislocation II
  • Since is edge
  • Also bII is parallel to x1 Therefore,
  • This means that b2 b3 0 and b1 b

14.29
7
  • Since tII is parallel to x3, then
  • This means that t1 t2 0 and t3 1
  • From Eqn. 14.31, we can write
  • Therefore

8
  • But
  • Therefore, F along the x1 Direction is given as
    ?21b
  • This component of force is responsible for
    dislocation glide motion - i.e., for dislocation
    II to move along x1 axis.

14.30
9
  • F along the x2 Direction is given as - ?11b
  • This component of force is responsible for climb
    (along x2).
  • At ambient (low) temperature, Fx2 is not
    important (because, no climb).
  • For edge dislocation, movement is by slip slip
    occurs only in the plane contained by the
    dislocation line its Burgers vector.

14.31
10
  • Consider only component Fx1
  • For x1gt0 Fx1 is negative (attractive)
  • when x1ltx2 for
    same sign, or
  • x1gtx2 for
    opposite sign.
  • For x1lt0 Fx1 is positive (repulsive)
  • when x1gt-x2 same sign disl. or x1lt-x2 for
    opposite sign disl.
  • Fx10 when x1 0, ? ? ? x2,

Usually for edge dislocations of same sign
For edge dislocations of opposite signs
11
  • Hence
  • Stable positions for two edge dislocations.

900
450
12
  • Equations 14-30 and 14-31 can also be obtained by
    considering both the radial and tangential
    components. The force per unit length is given
    by
  • Because edge dislocations are mainly confined to
    the plane, the force component along the the x
    direction, which is the slip direction, is of
    most interest, and is given by

14.32
14.33
13
  • Eqn. 14-34 is same as 14-30. Figure 14-5 is a
    plot of the variation of Fx with distance x,
    using equation 14-34. Where x is expressed in
    units of y. Curve A is for dislocations of the
    same sign curve B is for dislocations of
    opposite sign. Note that dislocations of the
    same sign repel each other when x gt y, and
    attract each other when x lt y.

14.34
14
Figure 14-5. Graphical representation of Eq.
(14-21). Solid curve A is for two edge
dislocations of same sign. Dashed curve B is for
two unlike two dislocations.
15
  • Example A dislocations lies parallel to 100
    with Burgers vector blt110gt. Compute the force
    acting on the dislocation due to the stress field
    of a neighboring screw dislocation lying parallel
    to 001.
  • Assume that for the
    screw dislocations

Solution
16
  • Let the screw dislocation be dislocation I at
    the origin.
  • The stress field for screw dislocation is given
    by
  • based on the assumption,
  • we have

17
  • For the other dislocation

18
  • (continued)

19
(b)
(a)
Figure 14-6. (a) Diffusion of vacancy to edge
dislocation (b) dislocation climbs up one
lattice spacing
Write a Comment
User Comments (0)
About PowerShow.com