SBI PO Sample Papers

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SBI PO Sample Paper
Practice Set - Reasoning
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Reasoning/Mental Aptitude
How to Solve Questions Based on Number Series

• Most of the number series can be solved by
  addition and subtraction ( Multiplication and
  Division being the Supersets for these). In plain
  English that means you need to find what to add
  or subtract to find the next (or missing) number
  in the series.
• We will understand the concept by solving a few
  questions and then you can attempt some on your
  own.

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Example 1
Find the next number in the series 1, 3, 6, 10,
15,____
Answer
Looking at the series we find that the series is
an INCREASING sequence. So we try to find what
is being added. Here the series is 1, 12, 123,
1234 Or Add 1,2,3,4 and so on to the last
number. 123, 336, 6410, 10515 So the
answer is 15621
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Practice Question 1 21, 25, 33, 49, 81 ___
(a) 145 (b)129 (c)113 (d)97
Ans (a)
Example 2
Find the next number in the series 87, 80, 74,
69, 65,___
Answer
Looking at the series we find that the series is
a DECREASING sequence. So we try to find what
is being subtracted. The series is 87, 87-780,
80-674, 74-569, 69-465 So the answer is 65-362
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Practice Question 2 66, 36, 21,___
(a) 13.5 (b)14.5 (c)13 (d)14
Ans (a)
Example 3
Find the next number in the series
40,15,30,25,20,35,___
Answer
Looking at the series we find that the series is
a MIXED sequence. By mixed series we mean that
it is composed of two different series. i.e.
40,30,20,(decreasing) and 15,25,35,(increasing)
The trick here is to know which series will give
us the answer. We see that the missing number
20-1010
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Practice Question 3 7.5, 5, 15, 4, 30, 3,60,
2,___
(a) 1 (b)75 (c)120 (d)135
Ans (c)
Complete the Series
Series completion involves finding the next item,
or the missing items in a given pattern. You have
to identify a repeating pattern in the given
series to get to the missing item.
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Complete the Series Solved Examples
I. Alphabet series
a. Increasing by a definite number
Q no 1. I J K L
Ans M (each letter increases by 1)
Q no 2. A G M S Y
Ans E (each letter increases by 6 place to its
right position)
b. Decreasing by a definite number
Q no 3. Z X V T R P
Ans N (each letter decreases by 6 place to its
right position)
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c. Increasing Successively
Q no 4. D E G J N S ?
Ans Y (1, 2, 3, 4, 5)
d. Decreasing successively
Q no 5. Z Y W T P
Ans K (-1, -2, -3, -4, -5)
e. Decreasing and Increasing by a constant value.
Q no 6. D F E B D A C Z
Ans B (2, -3, 2, -3,)
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II. Alphanumeric Series
Q no 1. Z1A, X2D, V6G, T21J, R88M, P445P,. ?
 
Q no 2. 2Z5, 7Y7, 14X9, 23W11, 34V13,. ?
Ans. First numeral 2, 7, 14, 23, 34 (5, 7, 9,
11) Second letter ZYXWV (decreases by 1 each
time) Third numeral 5, 7, 9 ,11, 13(increase by
2 each time) So next term is 47U15
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