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Lecture Problem 42

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... is no longer proportional to the strain, permanent plastic deformation occurs. The stress corresponding to the plastic deformation region is the yield strength, ... – PowerPoint PPT presentation

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Title: Lecture Problem 42


1
Lecture Problem 42
  • Diana Hawkins
  • Problems Focus Section 7.6
  • February 16,2007

2
(No Transcript)
3
Concepts Required
  • Plastic Deformation
  • Stress, s
  • Von Mises Yielding Criterion

4
Plastic Deformation
  • When a material is deformed such that the stress
    is no longer proportional to the strain,
    permanent plastic deformation occurs.
  • The stress corresponding to the plastic
    deformation region is the yield strength, sy.
  • For Aluminum 7075-T6, sy 505 MPa

sy
5
Stress
  • Stress occurs when a load is applied
    perpendicularly to an area.
  • For the Cube in Question
  • A 0.0001m2, Fxx F, Fzz -2F
  • So,

6
Von Mises Criterion
  • Want to avoid applying a force greater than the
    yield stress to prevent plastic deformation.
  • How big of a force can you apply when multiple
    forces are acting on a body?
  • Von Mises Criterion answers this question using
    the following equation

7
Recap
  • A 0.0001m2
  • Fxx F
  • Fzz -2F
  • sy 505 MPa

8
Solution
F 19.1 kN
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