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Introduction to Electrochemistry

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In calculation of the titration curve one may calculate Esystem from either the ... Cannot calculate the potential of the system. Titration Curves for Redox Systems ... – PowerPoint PPT presentation

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Title: Introduction to Electrochemistry


1
  • Introduction to Electrochemistry
  • Formal potentials are the potentials of
    half-cells relative to the SHE measured under
    conditions that the ratio of the analytical
    concentrations of reactants and products are
    exactly unity and the concentrations of other
    species in the system are carefully specified.
  • Symbol E0
  • Example for Fe(CN)63- e- Fe(CN)64-
    E0 0.36 V
  • in 1 M HClO4 or 1 M H2SO4, E vs. SHE 0.72 V
  • H reacts with the Fe(CN)63- and Fe(CN)64- to
    form protonated forms
  • The Hn Fe(CN)nn-3 is a stronger acid than
    HnFe(CN)6n-4 and the ratio Fe(CN)64-/Fe(CN)6
    3- will be less than 1 even though the ratio of
    analytical concentrations is 1
  • Use formal potentials when appropriate and be
    careful about other species in solution

2
  • Titration Curves for Redox Systems
  • The system
  • Add the titrant to the analytical solution which
    is part of a galvanic cell and allow the
    chemistry to come to equilibrium
  • Generally the titrant is an oxidizing agent
  • Often one of the electrodes is made of an inert
    material such as Pt and the other electrode is
    a secondary standard electrode such as Ag/AgCl or
    Hg/Hg2Cl2 separated from the analytical solution
    by a salt bridge
  • Measure the potential in volts or millivolts of
    the inert electrode vs. the reference electrode
    after equilibrium is established
  • At equilibrium in the analytical solution if and
    Eref 0.000 V,
  • Ecathode Eanode Esystem
  • In calculation of the titration curve one may
    calculate Esystem from either the anodic
    reaction or cathodic reaction
  • Use the half-equation that is most convenient
  • Example consider the titration of Fe2 with Ce4
  • Fe2 Ce4 Fe3 Ce2
  • Prior to the equivalence point, Fe2 and Fe3
    are easy to calculate but Ce4 requires an
    equilibrium constant calculation
  • After the equivalence point, Ce4 and Ce3
    are easy to calculate but Fe2 requires an
    equilibrium constant calculation
  • At the equivalence point, the Nernst equation
    does not provide enough information to
    calculate the potential

3
  • Titration Curves for Redox Systems
  • The system
  • At the equivalence point, but . . .
  • Fe3 Ce3 and
  • Fe4 Ce4 and are very small and require
    Keq to calculate
  • However,
  • Ce4 e- Ce3
  • Fe3 e- Fe2

4
  • Titration Curves for Redox Systems
  • Another Example Cr2O72- 6Fe2 14H
    2Cr3 6Fe3 H2O Cr2O72- 14H 6e-
    2Cr3 7H20
  • Fe3 1e- Fe2

5
  • Titration Curves for Redox Systems
  • Derive the titration curve for the titration of
    50.00 mL of 0.0500 M Fe2 with 0.01667 M
    Cr2O72-, both 1.0 M in H2SO4
  • Equivalence point occurs at 25.00 mL added
    Cr2O72-
  • Initial point
  • No Cr2O72- has been added, therefore no Cr3 or
    Fe3 has been produced
  • Cannot calculate the potential of the system

6
  • Titration Curves for Redox Systems
  • Derive the titration curve for the titration of
    50.00 mL of 0.0500 M Fe2with 0.01667 M
    Cr2O72-, both 1.0 M in H2SO4
  • Add 5.00 mL Cr2O72- make use of the Fe2/Fe3
    couple
  • At the equivalence point use earlier result

7
  • Titration Curves for Redox Systems
  • Derive the titration curve for the titration of
    50.00 mL of 0.0500 M Fe2with 0.01667 M
    Cr2O72-, both 1.0 M in H2SO4
  • Beyond the equivalence point 25.10 mL added
    Cr2O72-
  • Make use of the Cr3/Cr2O72- couple
  • At 30.00 mL
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