Consider two genes, A with two alleles A and a, and B with two alleles B and b. - Each of the alleles will be assigned metric values ... – PowerPoint PPT presentation
Many traits that are important in agriculture biology and biomedicine are continuous in their phenotypes. For example
Crop Yield
Stemwood Volume
Plant Disease Resistances
Body Weight in Animals
Fat Content of Meat
Time to First Flower
IQ
Blood Pressure
2 The following image demonstrates the variation for flower diameter number of flower parts and the color of the flower Gaillaridia pilchella (McClean 1997). Each trait is controlled by a number of genes each interacting with each other and an array of environmental factors. 3
Number of Genes Number of Genotypes
1 3
2 9
5 243
10 59049
4 Consider two genes A with two alleles A and a and B with two alleles B and b.- Each of the alleles will be assigned metric values- We give the A allele 4 units and the a allele 2 units- At the other locus the B allele will be given 2 units and the b allele 1 unit
Genotype Ratio Metric value
AABB 1 12
AABb 2 11
AAbb 1 10
AaBB 2 10
AaBb 4 9
Aabb 2 8
aaBB 1 8
aaBb 2 7
aabb 1 6
5 A grapical format is used to present the above results 6 Normal distribution of a quantitative trait may be due to
Many genes
Environmental effects
The traditional view polygenes each with small effect and being sensitive to environments
The new view A few major gene and many polygenes (oligogenic control) interacting with environments
7 Traditional quantitative genetics research Variance component partitioning
The phenotypic variance of a quantitative trait can be partitioned into genetic and environmental variance components.
To understand the inheritance of the trait we need to estimate the relative contribution of these two components.
We define the proportion of the genetic variance to the total phenotypic variance as the heritability (H2).
- If H2 1.0 then the trait is 100 controlled by genetics
- If H2 0 then the trait is purely affected by environmental factors.
8
Fisher (1918) proposed a theory for partitioning genetic variance into additive dominant and epistatic components
Cockerham (1954) explained these genetic variance components in terms of experimental variances (from ANOVA) which makes it possible to estimate additive and dominant components (but not the epistatic component)
I proposed a clonal design to estimate additive dominant and part-of-epistatic variance components
Wu R. 1996 Detecting epistatic genetic variance with a clonally replicated design Models for low- vs. high-order nonallelic interaction. Theoretical and Applied Genetics 93 102-109.
These two heritabilities are important in understanding the relative contribution of genetic and environmental factors to the overall phenotypic variance.
11 What is a(q-p)d
It is the average effect due to the substitution of gene from one allele (A say) to the other (a).
Each of male parents is mated to a subset of different female parents
21
Cov(HSM)1/4VA
V(female/male) Cov(FS) Cov(HSM)
1/2VA1/4VD 1/4VA
1/4VA 1/4VD
- Provide information for parents and full-sib families
- Provide estimates of both additive and dominance effects
- Provide estimates of genetic gains from both VA and VD
- Not efficient for selection
- Low cost for controlled mating
22 Example Date structure for NC Design I
Sample Male Female Full-sib family Individual Phen otype
1 1 A 1 1 y1A1
2 1 A 1 2 y1A2
3 1 B 2 1 y1B1
4 1 B 2 2 y1B2
5 1 C 3 1 y1C2
6 1 C 3 2 y1C2
7 2 D 4 1 y2D1
8 2 D 4 2 y2D2
9 2 E 5 1 y2E1
10 2 E 5 2 y2E2
11 2 F 6 1 y2F1
12 2 F 6 2 y2F2
13 3 G 7 1 y3G1
14 3 G 7 2 y3G2
15 3 H 8 1 y3H1
16 3 H 8 2 y3H2
17 3 I 9 1 y3I1
18 3 I 9 2 y3I2
23 Estimates by statistical software
VTotal 40
VFS Cov(FS) 10
VM Cov(HSM) 4
VE VTotal VFS 40 10 30
V(female/male) Cov(FS) Cov(HSM)
10 4 6
VA 4Cov(HSM) 4 4 16 h2 16/40 0.x
V(female/male) 1/4VA 1/4VD 4 1/4VD 6
VD 8 VG VA VD 16 6 22
H2 22/40 0.x
24 Factorial mating (NC Design II)
Each member of a group of males is mated to each member of group of females
25
Cov(HSM) 1/4 VA
Cov(HSF) 1/4 VA
V(female male) Cov(FS)Cov(HSM)Cov(HSF)
1/4 VD
- Provide good information for parents and full-sib families
- Provide estimates of both additive and dominance effects
- Provide estimates of genetic gains from both VA and VD
- Limited selection intensity
- High cost
26 Tester mating design (Factorial)
Each parent in a population is mated to each member of the testers that are chosen for a particular reason
27
Cov(HSM)1/4VA
Cov(HSF)1/4VA
V(female male) Cov(FS)COV(HSM)-COV(HSF)
1/4VD
- Provide good information for parents and full-sib families
- Provide estimates of both additive and dominance effects
- Provide estimates of genetic gains from both VA and VD
- Limited selection intensity
- High cost
28 Diallel mating design
Full diallel each parent is mated with every other parent in the population including selfs and reciprocal
29
Half diallel each parent is mated with every other parent in the population excluding selfs and reciprocal
30
Partial Diallel selected subsets of full diallels
31
Disconnected half diallel selected subsets of full diallels
32
Diallel analysis
Cov(HS) 1/4VA
Cov(FS) 1/2VA 1/4VD
Cov(FS) Cov(FS) 2Cov(HS) 1/4VD
- Provide good evaluation of parents and full-sib families
- Provide estimates of both additive and dominance effects
- Provide estimates of genetic gains from both VA and VD
- High cost
33 Genomic Imprinting or parent-of-origin effectThe same allele is expressed differently depending on its parental origin
Consider a gene A with two alleles A (in a frequency p) and a (in a frequency q)
Genotype Frequency Value
AA p2 a Average effect
Aa pq di No imprinting a d(q-p)
aA qp d-i Imprinting M a i d(q-p) A a
aa q2 -a P a i d(q-p) A a
Mean a(p-q)2pqd
No imprinting g2 2pq2 (2pqd)2
Imprinting gi2 2pq2 (2pqd)2 2pqi2
Imprinting leads to increased genetic variance for a quantitative trait and therefore is evolutionarily favorable.
34 Genomic Imprinting The callipygous animals 1 and 3 compared to normal animals 2 and 4 (Cockett et al. Science 273 236-238 1996) 35 (No Transcript) 36 (No Transcript) 37 (No Transcript) 38 (No Transcript) 39 (No Transcript) 40 (No Transcript) 41 Predicting Response to Selection 42 (No Transcript) 43 Population Mean Xp - phenotypic mean of the animals or plants of interest and expressed in measurable units. Selection Mean Xs - phenotypic mean of those animals or plants chosen to be parents for the next generation and expressed in measurable units. Selection Differential SD - difference between the phenotypic means of the entire population and its selected mean. 44 Genetic Gain the amount that the phenotypic mean in the next generation change by selection. - that change can be or - 45 Selection Differential G h2 SD 46 How to Calculate Genetic Gain M2 M h2 (M1 - M) M2 resulting mean phenotype M mean of parental population M1 mean of selected population h2 heritability of the trait M2 - M h2 (M1 - M) G h2 SD (SD/p)h2p ih2p i selection intensity h2 narrow-sense heritability p standard phenotypic deviation 47
Factors that influence
the Genetic Gain
Magnitude of selection differential
Selection intensity
Broad-sense heritability heritability
Phenotypic variation
48 Knowing the Selection Differential and the response to selection an estimate of the traits heritability can be calculated G / SD Realized Heritability 49 Realized heritability can also be calculated as M2 M h2 (M1 - M) rearranged (M2 - M) (M1 - M) h2 50
Maximizing Genetic Gain
Examples
51 N48 Population Mean 109.7 52 Goal Improve the Mean Select those in red N 6 Mean of Selected 119.5 SD 9.8 G h2 SD 0.7 x 9.8 6.86 53 Goal Reduce the Mean Select those in blue N 8 Mean of Selected 100.4 54 Nature 432 630 - 635 (02 December 2004)The role of barren stalk1 in the architecture of maize
ANDREA GALLAVOTTI12 QIONG ZHAO3 JUNKO KYOZUKA4 ROBERT B. MEELEY5 MATTHEW K. RITTER1 JOHN F. DOEBLEY3 M. ENRICO PÈ2 ROBERT J. SCHMIDT1
1 Section of Cell and Developmental Biology University of California San Diego La Jolla California 92093-0116 USA2 Dipartimento di Scienze Biomolecolari e Biotecnologie Università degli Studi di Milano 20133 Milan Italy3 Laboratory of Genetics University of Wisconsin Madison Wisconsin 53706 USA4 Graduate School of Agriculture and Life Science The University of Tokyo Tokyo 113-8657 Japan5 Crop Genetics Research Pioneer-A DuPont Company Johnston Iowa 50131 USA Present address Biological Sciences Department California Polytechnic State University San Luis Obispo California 93407 USA
55 Mapping Quantitative Trait Loci (QTL) in the F2 hybrids between maize and teosinte 56 Maize Teosinte tb-1/tb-1 mutant maize 57 Effects of ba1 mutations on maize development Mutant Wild type No tassel Tassel 58 Data format for a backcross
Sample Height Marker 1 Marker 2 QTL
(cm y)
1 184 Mm (1) Nn (1)
2 185 Mm (1) Nn (1)
3 180 Mm (1) Nn (1)
4 182 Mm (1) nn (0)
5 167 mm (0) nn (0)
6 169 mm (0) nn (0)
7 165 mm (0) nn (0)
8 166 mm (0) Nn (1)
59
Heights classified by markers (say marker 1)
Marker Sample Sample Sample
group size mean variance
Mm n1 4 m1182.75 s21
mm n0 4 m0166.75 s20
60 The hypothesis for the association between the marker and QTL
H0 m1 m0
H1 m1 m0
Calculate the test statistic
t (m1m0)/s2(1/n11/n0)
where s2 (n1-1)s21(n0-1)s20/(n1n02)
Compare t with the critical value tdfn1n2-2(0.05) from the t-table.
If t gt tdfn1n2-2(0.05) we reject H0 at the significance level 0.05 there is a QTL
If t lt tdfn1n2-2(0.05) we accept H0 at the significance level 0.05 there is no QTL
61 Why can the t-test probe a QTL
Assume a backcross with two genes one marker (alleles M and m) and one QTL (allele Q and q).
These two genes are linked with the recombination fraction of r.
MmQq Mmqq mmQq mmqq
Frequency (1-r)/2 r/2 r/2 (1-r)/2
Mean effect ma m ma m
Mean of marker genotype Mm
m1 (1-r)/2 (ma) r/2 m m (1-r)a
Mean of marker genotype mm
m0 r/2 (ma) (1-r)/2 m m ra
The difference
m1 m0 m (1-r)a m ra (1-2r)a
62
The difference of marker genotypes can reflect the size of the QTL
This reflection is confounded by the recombination fraction
Based on the t-test we cannot distinguish between the two cases
- Large QTL genetic effect but loose linkage with the marker
- Small QTL effect but tight linkage with the marker
63 Example marker analysis for body weight in a backcross of mice
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