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Spectroscopy

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Title: Spectroscopy


1
Spectroscopy
  • Building A Toolset
  • For
  • The Identification of Organic Compounds

2
Spectroscopy
  • Spectroscopy Tools

3
Spectroscopy
  • Spectroscopy
  • The Absorption of Electromagnetic Radiation and
    the use of the Resulting Absorption Spectra to
    Study the Structure of Organic Molecules.
  • When continuous radiation passes through a
    transparent material, some of the radiation can
    be absorbed.
  • If the portion that is not absorbed is passed
    through a prism, a spectrum with gaps is
    produced.
  • This is called an
  • ABSORPTION SPECTRUM

4
Spectroscopy
  • Energy States
  • Energy absorption by transparent materials in any
    portion of the electromagnetic spectrum causes
    atoms or molecules to pass from a state of low
    energy (ground state) to a state of higher energy
    (excited state).
  • There are 3 types of Energy States
  • Electronic
  • Vibrational
  • Spin

5
Spectroscopy
  • Electromagnetic Spectrum
  • Cosmic ? (Gamma) X-Ray
  • Ultraviolet Visible Infrared
  • Microwave Radio
  • Energy States and the Electromagnetic Spectrum
  • Electronic Ultraviolet
  • Vibrational Infrared
  • Spin Radio

6
Spectroscopy
3 x 108 Hz
1.2 x 1014 Hz
Frequency
3 x 1019 Hz
3 x 1016 Hz
2 x 1013 Hz
6 x 107 Hz
1.5 x 1015 Hz
1 x 109 Hz
3 x 1011 Hz
4 x103cm-1
1.25 x104cm-1
Wave Number
0.002 cm-1
2.5 x104cm-1
0.01 cm-1
1 x109cm-1
10 cm-1
3 cm-1
1 x107cm-1
5 x104cm-1
667cm-1
Cosmic ? Ray
Vacuum UV
Microwave
Infrared
X-Ray
Radio
Frequency
1 m
5 m
0.01 nm
10 nm
30 cm
1 mm
Wavelength
400 nm
200 nm
800 nm
2.5 ?
15 ?
Visible
Near Ultraviolet
Nuclear Magnetic Resonance
Vibrational Infrared
Blue
Red
7
Spectroscopy
  • Quantization
  • The excitation process is quantized, in which
    only selected frequencies of energy are absorbed
    representing the energy difference (?E) between
    the excited and ground states.

?E E (excited) E (ground) h?
E hc / ?
? c / ?
Where
? Frequency (Hz) c Velocity of Light
(cm/sec) ? Wavelength (cm) h Plancks
Constant

8
Spectroscopy
  • Spectroscopy Types
  • Mass Spectrometry (MS) Hi-Energy Electron
    Bombardment
  • Use Molecular Weight, Presence of Nitrogen,
    Halogens
  • Ultraviolet Spectroscopy (UV) Electronic Energy
    States
  • Use Conjugated Molecules Carbonyl Group, Nitro
    Group
  • Infrared Spectroscopy (IR) Vibrational Energy
    States
  • Use Functional Groups Compound Structure
  • Nuclear Magnetic Resonance (NMR) Nuclear Spin
    States
  • Use The number, type, and relative position of
    protons (Hydrogen nuclei) and Carbon-13
    nuclei

9
Mass Spectroscopy
  • High energy electrons bombard organic molecules
    breaking some or all of the original molecules
    into fragments.
  • The process usually removes a single electron to
    produce a positive ion (cation radical) that can
    be separated in a magnetic field on the basis of
    the mass / charge ratio.
  • Removal of the single electron produces a charge
    of 1 for the cation.
  • Thus, the cation represents the Molecular Weight
    of the original compound or any of the fragments
    that are produced.
  • The mass spectrum produced is a plot of relative
    abundance of the various fragments (positively
    charged cation radicals) versus the Mass / Charge
    (M/Z) ratio.
  • The most intense peak is called the Base Peak,
    which is arbitrarily set to 100 abundance all
    other peaks are reported as percentages of
    abundance of Base Peak.

10
Mass Spectroscopy
M e- ? M
2e-
Molecule
High Energy Electron
Molecular Ion (Radical Cation)
1-Pentanol - MW 88CH3(CH2)3 CH2OH
M - (H2O and CH2 CH2)
Base Peak
M - (H2O and CH3)
Typical Mass Spectrum
M - H2O
CH2OH
Molecular Ion Peak (M 88)
11
Mass Spectroscopy
  • Molecular Ion Peak (M)
  • Largest mass/charge ratio
  • Always the last peak on the right side of
    spectrum
  • May or may not be the base peak (usually not)!
  • Abundance can be quite small, i.e., very small
    peaks
  • The Molecular Ion Peak represents the
  • Molecular Weight of the Compound

12
Mass Spectroscopy
Methyl Propyl Ketone (C5H10O) (CAS 107-87-9)
M 43(C2C2CH3) lostPropyl Group
M 28(CH2CH2) lost
M 15(CH3) lost
M 86
13
Mass Spectroscopy
  • The Presence of Nitrogen in the Compound
  • If the Mass / Charge (m/z) ratio for the
    Molecular Ion peak is Odd, then the molecule
    contains an Odd number of Nitrogen atoms, i.e.,
    1, 3, 5, etc.
  • Note An Even value for the Mass / Charge
    ratio could represent a compound with an even
    number of Nitrogen atoms, i.e., 0, 2, 4 etc.
  • The actual presence of Nitrogen in the compound
    is not explicitly indicated as it is with an
    Odd value for the ratio.

14
Mass Spectroscopy
  • Halogens in Organic Compounds
  • Most elements exist in several isotopic forms
  • Ex. 1H1, 2H1, 12C6, 13C6, 35Cl17, 37Cl17,
    79Br35, 81Br35
  • Average Molecular Weight
  • The average molecular weight of All isotopes of
    a given element relative to the abundance of the
    each isotope in nature
  • Integral Molecular Weight
  • The Number of Protons and Neutrons in a specific
    isotope
  • Each fragment represented in a Mass Spectrum
    produces several peaks each representing a
    particular isotopic mixture of the elements in
    the compound, i.e., an integral molecular weight.

15
Mass Spectroscopy
  • The Presence of Chlorine in a Compound
  • The two (2) principal Chlorine Isotopes in nature
    areCl-35 and Cl-37 (2 additional Neutrons in
    Cl-37)
  • The relative abundance ratio of Cl-35 to Cl-37
    is
  • 100 32.6 or 75.8 24.2 or ? 3 1
  • Therefore, a Molecule containing a single
    Chlorine atom will show two Mass Spectrum
    Molecular Ion peaks, one for Cl-35 (M) and one
    for Cl-37 (M2)
  • Note M2 denotes 2 more neutrons than M
  • Based on the natural abundance ratio of 100 /
    32.6 (about 31), the relative intensity (peak
    height) of theCl-35 peak will be 3 times the
    intensity of the Cl-37 peak

16
Mass Spectroscopy
  • The Presence of Chlorine in a Compound (Cont)

1-Chloropropane
Molecule contains 1 Chlorine atom resulting in
two Molecular Ion Peaks of about 31 relative
intensity, based on the 31 natural abundance
ratio ofCl-35 / Cl-37
Molecular Ion Peaks M 78 M2 80
very small
17
Mass Spectroscopy
  • The Presence of Bromine in a Compound
  • The two (2) principal Bromine Isotopes in nature
    areBr-79 and Br-81 (2 additional Neutrons in
    Br-81)
  • The relative abundance ratio of Br-79 to Br-81 is
  • 100 97.1 or 50.5 49.5 or ? 1 1
  • Molecules containing a single Bromine atom will
    also show two molecular ion peaks one for Br-79
    (M) and one for Br-81 M2
  • Based on the natural abundance ratio of 100 /
    97.1 (about 11), the relative intensity of the
    Br-79 peak will be about the same as the Br-81
    peak

18
Mass Spectroscopy
  • The Presence of Bromine in a Compound (Cont)

19
Mass Spectroscopy
  • The Presence of Fluorine in a Compound
  • Fluorine exists in nature principally as a single
    isotope 19F9
  • A compound containing any number of Fluorine
    atoms will have a single Molecular Ion peak
    (assuming no other Halogens present)

20
Mass Spectroscopy
  • Multiple Halogens in a Compound
  • Compounds containing two (2) Chlorine atoms will
    produce three (3) Molecular Ion peaks
    representing the 3 possible isotope combinations
    of Chlorine
  • 35Cl17 35Cl17 (Rel Peak Intensity - 100.0)
  • 35Cl17 37Cl17 (Rel Peak Intensity -
    65.3)
  • 37Cl17 37Cl17 (Rel Peak Intensity -
    10.6)

21
Mass Spectroscopy
  • Multiple Halogens in a Compound
  • Compounds containing three (3) Chlorine atoms
    will produce four (4) Molecular Ion peaks
    representing the 4 possible isotope combinations
    for Chlorine
  • 35Cl17 35Cl17 35Cl17 (Rel Peak
    Intensity - 100.0)
  • 35Cl17 35Cl17 37Cl17 (Rel Peak
    Intensity - 97.8)
  • 35Cl17 37Cl17 37Cl17 (Rel Peak
    Intensity - 31.9)
  • 37Cl17 37Cl17 37Cl17 (Rel Peak Intensity -
    3.5)

22
Mass Spectroscopy Molecular Formula
  • Information from the Mass Spectrum can used to
    determine the Molecular Formula of a compound
  • Ex. Molecular Ion Peaks M 94 M2 96 (95)
  • 2 Molecular Ion Peaks (31) suggest 1
    Chlorine atom
  • Partial Analysis C 25.4 H 3.2
  • Use 95 as average molecular weight
  • Carbon 95 x 0.254 24.1 / 12 2 C atoms
  • Hydrogen 95 x 0.032 3.0 / 1 3 H
    atoms
  • 95 (24 3) 68 unresolved mass
  • (Use oxygen, nitrogen, halides (Cl or Br) to
    resolve mass)
  • 2 Oxygen (16 16) 1 Chlorine (35.5) ? 68
  • Molecular Formula - C2H3O2Cl

23
Mass Spectroscopy
  • Summary
  • Fragmentation of Organic Molecules by high energy
    electrons
  • Base Peak 100 abundance
  • Molecular Ion Peak Highest Mass/Charge ratio
  • Molecular Ion Peak Last peak(s) on right side
    of chart
  • Molecular Ion Peak Represents Molecular Weight
    of compound
  • Molecular Ion Peak If value is Odd the
    compound contains an odd number of Nitrogen
    atoms
  • Molecular Ion Peak If two peaks occur and the
    relative abundance ratio is 31, then the
    compound contains a single Chlorine atom.
  • Molecular Ion Peak If two peaks occur and the
    relative abundance ration is 11, then the
    compound contains a single Bromine Atom

24
Ultraviolet/Visible (UV) Spectroscopy
  • UV-Visible Spectrum 190 nm 800 nm
  • In Ultraviolet and Visible Spectroscopy, the
    energy absorption transitions that occur are
    between electronic energy levels of valence
    electrons, that is, orbitals of lower energy are
    excited to orbitals of higher energy.
  • Thus, UV / Visible spectra often called
    Electronic Spectra
  • All organic compounds absorb Ultraviolet light to
    some degree, but in many cases at such short
    wavelengths to make its utility of very limited
    value in organic chemistry.
  • For the purpose of this course, the primary use
    of UV/Vis will be to confirm
  • The presence of conjugated molecules, either
    aliphatic alkene structures or aromatic ring
    structures.
  • To a lesser degree, the presence of the Carbonyl
    group and the Nitro group.

25
Ultraviolet/Visible (UV) Spectroscopy
  • When a molecule absorbs radiation a valence
    electron is generally excited from its highest
    occupied molecular orbital (HOMO) to the lowest
    unoccupied molecular orbital (LUMO)
  • For most molecules, the lowest energy orbitals
    are thesigma (?) orbitals (? - bonds)
  • The electrons of sigma bonds are too tightly
    bound to be promoted by radiation in the 200-700
    nm region.
  • Therefore alkanes, saturated alcohols, simple
    alkenes show no or very little UV absorption.
  • The ? orbitals occupy somewhat higher energy
    levels.
  • Orbitals that hold unshared pairs of electrons,
    the nonbonding (n) orbitals, lie at even higher
    energies.
  • Unoccupied or antibonding orbitals (? and ?)
    have the highest energies.

26
Ultraviolet/Visible (UV) Spectroscopy
  • Chromophores
  • The absorption of Ultraviolet radiation results
    from the excitation of electrons from ground to
    excited state
  • The Nuclei in molecules, however, determine the
    strength with which electrons are bound to the
    molecule, thus, influencing the spacing between
    ground and excited states
  • The characteristic energy of a transition and the
    wavelength of radiation absorbed are properties
    of a group of atoms rather than the electrons
    themselves.
  • The group of atoms producing such an absorption
    is called a Chromophore.
  • As the structure of the molecule (alkane, alkene,
    alkyne, alcohol, amine, nitrile, carbonyl, etc.)
    changes, the energy and intensity of the
    Ultraviolet absorption will change accordingly

27
Ultraviolet/Visible (UV) Spectroscopy
  • Radiation in the range 190nm 800nm causes
    valence electrons (those that participate in
    bonding) to be excited to a higher energy level.
  • The ground state of an organic molecule can
    contain valence electrons in three principal
    types of molecular orbitals

? (sigma) ? (pi) n (non-bonding)
Sigma pi bonds have antibonding
(unocuupied) orbitals associatedwith them
? ?
28
Ultraviolet/Visible (UV) Spectroscopy
Energy Transition Examples
  • n ? ? in carbonyl compounds
  • n ? ? in oxygen, nitrogen, sulfur, and halogen
    compounds
  • ? ? ? in alkenes, alkynes, carbonyl and azo
    compounds
  • ? ? ? in carbonyl compounds
  • ? ? ? in alkanes

IncreasingEnergy
  • ?
  • n
  • ?
  • ?

Antibonding (single bonds) Antibonding (double
bonds)
IncreasingEnergy
Nonbonding (as in lone electron pairs or the
propenyl (allyl) radical
Bonding (double bonds) Bonding (single bonds)
Note Electronic energy levels in aromatic
molecules are more complicated than are presented
here.
29
Ultraviolet/Visible (UV) Spectroscopy
  • Atoms produce sharp lines of absorption
  • Molecules have many excited modes of vibration
    and rotation at room temperature. The rotational
    and vibrational levels are superimposed on the
    electronic levels
  • Electron transitions may occur from any of
    several vibrational and rotational states of one
    electronic level to any of several vibrational
    and rotational states of a higher electronic
    level.
  • Thus, the UV spectrum of a molecule consists of a
    broad band of absorption centered near the
    wavelength of the major transition, i.e. where
    the radiation has its maximum absorption (?max).

30
Ultraviolet/Visible (UV) Spectroscopy
  • The Ultraviolet-Visible spectrum is generally
    recorded as a plot of absorbance versus
    wavelength but the plot is more often presented
    with the Absorptivity (?) or log ? plotted on the
    ordinate (y-axis) and the wavelength plotted on
    the abscissa (x-axis)
  • Ex Cyclohexane
  • (A Conjugated Aromatic Molecule)
  • Wavelength of Maximum Absorbance ?max 230 nm
  • Molar Absorptivity
  • ? 15,000 cm-1
  • Log ? 4.2

31
Ultraviolet/Visible (UV) Spectroscopy
  • The Beer-Lambert Law
  • The Ultraviolet/Visible Spectrum is a plot of the
    Wavelength (?) in nanometers (nm) over the entire
    Ultraviolet / Visible region versus the
    Absorbance (A) of the radiation at each
    wavelength.
  • A log (Ir / Is) ? C L
  • Is Intensity of light through sample solution
  • Ir Intensity of incident light passing through
    Reference cell
  • ? Molar Absorptivity (Molar Extinction
    Coefficient) A measure of the strength or
    intensity of the absorption.
  • Units l/(mol cm) (m2 x 10-2 /mol)
    (mmol/dm3)
  • C Concentration of solute (mol/L) or (g/L) if
    molecular mass is unknown
  • L Length of cell (cm)

32
Ultraviolet/Visible (UV) Spectroscopy
  • A ? C l
  • ? A / (C l )
  • Values of ? are usually expressed as Log ?
  • Aliphatic (single band) ? 10,000 20,000 (Log
    ? 4.0 4.3)
  • Aromatic (two bands ? 1,000 10,000 (Log ?
    3.0 4.0)
  • Carbonyl compounds ? 10 100 (Log ? 2)
  • Nitro compounds ? 10 (Log ? 1)

33
Ultraviolet/Visible (UV) Spectroscopy
  • Typical Transitions Associated Wavelengths of
    Maximum Absorption and Molar Absorptivities

34
Ultraviolet/Visible (UV) Spectroscopy
  • Typical Transitions and Absorptionsof Simple
    IsolatedChromophores

35
Ultraviolet/Visible (UV) Spectroscopy
  • Computation Example
  • An ??-unsaturated ketone of relative molecular
    weight 110 has an absorption band with ?max at
    215 nm and ? 10,000 (l / mol cm)
  • A solution of this ketone showed absorbance A
    2.0 with a 1 cm cell. Calculate the concentration
    of the ketone in this solution expressed in grams
    per liter.
  • Ans A ? c L
  • c A / ? L
  • c 2.0 / ((10,000 l/mol cm) 1.0 cm)
  • c 2 x 10-4 mol/l
  • c 2 x 10-4 mol/l x 110 g/mol
  • c 2.20 x 10-2 g/l

36
Ultraviolet/Visible (UV) Spectroscopy
  • Computation Example
  • Calculate the Molar Absorptivity, ?, for a
    solution containing 1.0 mmol dm-3 (1.0 x 10-3
    moles per liter) of solute, when the absorbance
    of a 1 cm cell was 1.5.
  • Ans A ? c L
  • ? A / c L
  • ? 1.5 / (1 x 10-3 mol / L) (1 cm)
  • ? 1.5 x 103 L / mol cm
  • What would be the Absorbance for a solution of
    double this concentration?
  • Ans A 1.5 x 103 L / mol cm 2.0 x 10-3
    moles / L 1 cm
  • A 3.0

37
Ultraviolet/Visible (UV) Spectroscopy
  • Alkanes
  • Contain single sigma bonds resulting in only ? ?
    ? transitions which absorb ultraviolet radiation
    at wavelengths generally too short for use in UV
    spectroscopy.
  • Utility None
  • Alcohols, Ethers, Amines, Sulfur Compounds
  • The n ? ? transitions absorb UV radiation within
    the experimentally accessible range (gt180 nm).
  • Utility Very little

38
Ultraviolet/Visible (UV) Spectroscopy
  • Alkenes and Alkynes
  • Absorb UV radiation in the range lt 180 nm.
  • Cumulated alkenes (? ? ? transitions), which
    have one or more ? sigma bonds between the
    double bounds usually have absorption maxima
    below 200 nm.
  • Utility Very little
  • Compounds with Oxygen double bonds
  • Unsaturated molecules containing oxygen or
    nitrogen structures such as Carbonyl (CO) and
    Nitro (NO2) have both n ? ? (280 - 290 nm) and ?
    ? ? transitions (188 nm).
  • Utility Moderate

39
Ultraviolet/Visible (UV) Spectroscopy
  • Conjugated unsaturated systems are molecules with
    two or more double or triple (?) bonds each
    alternating with a single or sigma bond (?).
  • Conjugated unsaturated systems have delocalized ?
    bonds, i.e., a p-orbital on an atom adjacent to a
    double bond producing ? ? ? transitions.
  • Single electron as in the allyl radical
    (CH2CH?CH2)
  • Vacant p orbital as in allyl cation
    (CH2CH?CH2)
  • P orbital of another double bond
    (CH2CH?CHCH2
  • Conjugated systems include the Aliphatic Alkenes
    as well as the Aromatic ring structures.
  • Compounds whose molecules contain conjugated
    multiple bonds absorb strongly in the UV /
    Visible portion of the electromagnetic spectrum
    (gt 200 nm).
  • Utility Good

40
Ultraviolet/Visible (UV) Spectroscopy
  • Conjugated Unsaturated Systems
  • Conjugated systems consist of alternating sigma
    (?) bonds and pi (?) bonds) and the Ultraviolet
    absorptions show large values of ?

2,5-Dimethyl-2,4-Hexadiene (in Methanol)
  • The Wavelength of Maximum Absorption ( ?max ) is
    obtained from the Absorption Spectrum
  • Wavelength of Maximum Absorbance (?max) 242.5
    nm
  • Molar Absorptivity ( ? ) 13,100 M-1 cm-1 (Log
    ? 4.1)

41
Ultraviolet/Visible (UV) Spectroscopy
  • Conjugated Unsaturated Systems (Cont)
  • ?,? - Unsaturated ketones, Dienes, Polyenes
  • Transitions ? - ?
  • High Intensity Bands
  • ? 10,000 to 20,000 (log ? 4.0 - 4.3)
  • ?max gt 210 nm
  • Aromatic Conjugated Systems
  • Transitions ? - ?
  • 2 Medium Intensity Bands
  • ? 1000 - 60,000 (log ? 3.0 - 4.8)
  • ?max both bands gt 200 nm
  • Note Substitution on ring increases Molar
    Absorptivity above 10,000

42
Ultraviolet/Visible (UV) Spectroscopy
  • Carbonyl (CO), Nitro Group (NO2) (Resonance
    effects on substituted benzene)
  • Transitions n - ? ? ? ?
  • Single Low Intensity Band ? 10 (log ? 1)
    to ? 300 (log ? 2.5)
  • ?max (250 - 360 nm)
  • Nitro (NO2) log ? (1.0)
  • Carbonyl (CO) log ? (2.0)
  • The presence of these functional groups should be
    used only as confirmations of species identified
    in the IR Spectra.

43
Ultraviolet/Visible (UV) Spectroscopy
  • Practical Approach to Interpreting UV/Vis
    Information
  • If the problem you are working on provides an
    UV/Vis spectrum and it indicates No absorption
    in the 200 700 nm range, the following
    conclusions are applicable
  • The compound is not conjugated, i.e., it does not
    contain alternating double/single bonds
    (including Benzene ring.)
  • The compound probably does not contain
    Carbonyl or Nitro groups (confirm with IR).
  • If the problem provides Log Absorptivity values
    (Log ?) the following possibilities exist
  • Log ? (gt 4.0) - Conjugated ?,? - Unsaturated
    ketones, Dienes, Polyenes
  • Log ? (3.0 4.0) - Aromatic ring (Check IR, NMR)
  • Log ? (1.5 2.5) - CO (Check IR)
  • Log ? (1.0 1.5) - NO2 (Check IR)

44
Infrared Spectroscopy
  • Infrared Spectroscopy References
  • Pavia, et al - pp. 873 - 909
  • Solomons et al - pp. 79 - 84 821 822
  • Infrared Radiation
  • That part of the electromagnetic spectrum between
    the visible and microwave regions 0.8 ?m
    (12,500 cm-1) to 50 ?m (200 cm-1).
  • Area of Interest in Infrared Spectroscopy
  • The Vibrational portion of infrared spectrum
  • 2.5 ?m (4,000 cm-1) to 25 ?m (400 cm-1)
  • Radiation in the vibrational infrared region is
    expressed in units called wavenumbers ( )

45
Infrared Spectroscopy
  • Wavenumbers are expressed in units of reciprocal
    centimeters (cm-1) i.e. the reciprocal of the
    wavelength (?) expressed in centimeters.
  • ? (cm-1) 1 /
    ? (cm)
  • Wave Numbers can be converted to a frequency (?)
    by multiplying them by the speed of light (c) in
    cm/sec
  • ? (Hz) ? c c / ? (cm
    /sec /cm 1/sec)
  • Recall E h c / ?
  • Thus, wavenumbers are directly proportional to
    energy

?
?
46
Infrared Spectroscopy
  • Polar Covalent Bonds Dipole Moments
  • Organic compounds are organized into families of
    compounds on the basis of certain groupings of
    atoms, i.e., Functional Groups.
  • The Electrons between atoms in an organic
    compound are shared forming Covalent bonds.
  • Covalent bonds between atoms with different
    electronegativities have an unequal sharing of
    the bond electrons setting up an electrostatic
    charge difference between the atoms.
  • The atom with the greater Electronegativity pulls
    the electrons closer to it forming a Polar
    Covalent Bond.

47
Infrared Spectroscopy
  • Polar Covalent Bonds Dipole Moments (Cont)
  • The relative strength of the Polar Covalent Bond
    impacts the ability of the molecule, i.e., a
    Functional Group, to attract or repel other polar
    entities (functional groups).
  • The separation of the positive and negative
    charges in a Polar Covalent Bond is referred to
    as a Dipole.
  • A dipole has a Dipole Moment defined as the
    product of the magnitude of the partial charges
    (in electrostatic units, esu) times the distance
    (in cm) of separation.
  • Only those Covalent bonds with Dipole Moments are
    capable of absorbing Infrared Radiation.

48
Infrared Spectroscopy
  • The Radiation (Energy) Absorption Process
  • The absorption of Infrared Radiation by a Polar
    Covalent Bond raises the molecule to a higher
    energy state.
  • This is a Quantized process in which only
    selected frequencies are absorbed dependent on
    the relative masses of the atoms, the force
    constants of the bond (electronegativity), and
    the geometry of the atoms.
  • Covalent Bonds possess Rotational and Vibrational
    frequencies.
  • Every type of bond has a natural frequency of
    vibration.
  • The same bond in different compounds has a
    slightly different frequency of vibration.

49
Infrared Spectroscopy
  • When the frequencies of Infrared Radiation match
    the natural vibrational frequencies of a bond
    with a Dipole Moment, the radiation is absorbed
    increasing the amplitude of the vibrational
    motions of the covalent bonds.
  • Infrared radiation is absorbed and converted by
    organic molecules with polar covalent bonds and
    dipole moments into energy of molecular rotation
    and molecular vibration.
  • Rotation - Less than 100 cm-1
    (Spectrum is lines)
  • Vibration - 10,000 cm-1 to 100 cm-1 (Spectrum is
    bands)
  • The vibrational bands appears because each
    vibrational energy change is accompanied by a
    number of rotational changes
  • Infrared Spectroscopy is concerned only with the
    vibrational spectrum (4,000 cm-1 to 400 cm-1)

50
Infrared Spectroscopy
  • Molecular Vibrations
  • Absorption of infrared radiation corresponds to
    energy changes on the order of 8-40 KJ/mole (2-10
    Kcal/mole
  • The frequencies in this energy range correspond
    to the stretching and bending frequencies of the
    covalent bonds with dipole moments.
  • Stretching (requires more energy than bending)
  • Symmetrical
  • Asymmetrical
  • Bending
  • Scissoring (in-plane bending)
  • Rocking (in-plane bending)
  • Wagging (out-of-plane bending)
  • Twisting (out of plane bending)

51
Infrared Spectroscopy
  • Stretching A rhythmical movement along the bond
    axis such that the interatomic distance is
    increasing or decreasing.
  • In any group of three or more atoms at least
    two of which are identical - there are two modes
    of stretching or bending Symmetric and
    Asymmetric
  • For the Methylene Group (CH2)

H C H
H C H
CH
Symmetric Stretch (2853 cm-1)
Asymmetric Stretch (2926 cm-1)
52
Infrared Spectroscopy
  • Bending A change in bond angle between bonds
    with a common atom or
  • A movement of a group of atoms with respect to
    the remainder of the molecule

H C H
Scissoring 1450 cm-1 (In Plane)
Wagging 1250 cm-1 (Out of Plane)
H H C
H C H
H H C
Twisting 1250 cm-1 (Out of Plane)
Rocking 750 cm-1 (In Plane)
53
Infrared Spectroscopy
  • Thus, no two molecules of different structure
    will have exactly the same natural frequency of
    vibration, each will have a unique infrared
    absorption pattern or spectrum.
  • Two Uses
  • IR can be used to distinguish one compound from
    another.
  • Absorption of IR energy by organic compounds will
    occur in a manner characteristic of the relative
    strengths of the Polar Covalent Bonds in the
    Functional Groups present in the compound thus,
    an Infrared Spectrum gives structural information
    about the functional groups present in a
    molecule.
  • The absorptions of each type of bond (NH, CH,
    OH, CX, CO, CO, CC, CC, CC, CN, etc.) are
    regularly found only in certain small portions of
    the vibrational infrared region, greatly
    enhancing analysis possibilities.

54
Infrared Spectroscopy
  • Instrumentation
  • Dispersive (Double Beam) IR Spectrophotometer

SplitBeams
Air
Detector
Recorder
Sample
Slit
IR Source
Lenz
Monochromator
The split beams pass into a Monochromator, which
consists of a rapidly rotating sector that passes
each beam to a diffraction grating or prism. The
slowly rotating diffraction grating varies the
wavelength of radiation reaching the
detector. The detector senses the ratio in
intensity between the reference (air) and sample
beams and records the differences on a chart.
55
Infrared Spectroscopy
  • Sample Preparation
  • Liquid Samples
  • 1 to 2 drops of liquid sample are placed between
    two single crystals of sodium chloride (Plates)
  • Note NaCL plates are water soluble keep
    dry
  • Solid Samples soluble in Acetone
  • Dissolve sample in acetone
  • Evaporate on Salt Plate
  • Solid Samples not soluble in acetone
  • Make Potassium Bromide (KBR) pellet
  • Put plates in plate holder
  • Place holder in IR Spectrometer
  • Obtain IR Spectrum
  • Clean Plates with Acetone

56
Infrared Spectroscopy
  • Fourier Transform (FT) Single Beam IR
  • Set background (air)
  • Press Scan button
  • Press Background button
  • Verify No. of Scans is 4 if not, push soft key
    to set 4
  • Press Execute
  • Obtain Sample Spectra
  • Insert Cell Holder into beam slot
  • Press SCAN button
  • Select Memory location ( X, Y, or Z)
  • Press Execute

57
Infrared Spectroscopy
  • Fourier Transform (FT) Single Beam IR (Cont)
  • If spectrum bottoms out (might have to check with
    instructor), then remove Cell Holder remove top
    of Salt Plate wipe lightly with tissue
    reassemble and insert cell holder into beam
    slot.
  • Rerun Scan again
  • Push Plot to produce chart
  • Remove Cell Holder and disassemble
  • Clean Salt Plate dry return to instructor
    place in desiccator

58
Infrared Spectroscopy
  • The Infrared Spectrum
  • A plot of absorption intensity ( Transmittance)
    on the y-axis vs. frequency on the x-axis.
  • Transmittance (T) - the ratio of the radiant
    power transmitted by a sample to the radiant
    power incident on the sample.
  • Absorbance (A) - the logarithm to base 10 of
    the reciprocal of the Transmittance.
  • A log10 (1 / T)
  • Frequency - The x-axis is represented by two
    scales
  • Wavelength (2.5 ? to 25 ? ) (Bottom)
  • Wavenumber (4000 cm-1 to 400 cm-1) (Upper)

59
Infrared Spectroscopy
  • IR SpectrumKetone

CO CarbonylOvertone
CH2
Methyl Isopropyl Ketone
CH3
Aliphatic C-H Stretch
CO Carbonyl
C5H10O
CAS 563-80-4
60
Infrared Spectroscopy
  • IR Spectrum Peak Characteristics
  • Primary Examination Regions of the Spectrum
  • High Frequency Region - 4000 to 1300 cm-1
  • Intermediate (Fingerprint Region) - 1300 to 900
    cm-1
  • High Frequency Region (Functional Group Region)
  • Characteristic Stretching frequencies of such
    groups as
  • C?H, OH, NH, CO, C?O, CN, CC,
    CC
  • The Fingerprint Region - 1300 to 900 cm-1
  • Absorption patterns frequently complex
  • Bands originate from interacting vibrational
    modes
  • Valuable when used in reference to other regions
  • Absorption unique for every molecular species
  • Effective use comes from experience

61
Infrared Spectroscopy
  • IR Spectrum Peak Characteristics (cont)
  • Shape
  • Sharp (narrow)
  • Broad
  • Intensity
  • Weak (w)
  • Medium (m)
  • Strong (s)
  • Note Peak intensity is dependent on amount of
    sample and sensitivity of instrument therefore,
    the actual intensity can vary from spectrum to
    spectrum

62
Infrared Spectroscopy
  • Principal Frequency Bands
  • O-H 3600 cm-1 (Acids, Alcohols)
  • N-H 3300 - 3500 cm-1 (Amino)
  • (1o - 2 peaks, 2o - 1 peak,
    3o 0 peaks)
  • NO2 1450 1650 cm-1 (2 absorptions)
  • CN 2250 cm-1 (Nitrile)
  • CC 2150 cm-1 (Acetylene)
  • -CC-H 3300 cm-1 (Terminal Acetylene)
  • CO 1685 - 1725 cm-1 (Carbonyl)
  • CC 1650 cm-1 (Alkene) 2 absorptions
  • CC 1450 1600 cm-1 (Aromatic) 4 absorptions

63
Infrared Spectroscopy
  • Principal Frequency Bands (Cont)
  • CH2 1450 cm-1 (Methylene)
  • CH3 1375 1450 cm-1 (Methyl)
  • C-O 900 - 1100 cm-1 (Alcohol, Acid, Ester,

    Ether, Anhydride)
  • -C-H Right side of 3000 cm-1 (Saturated Alkane)
  • C-H Left side of 3000 cm-1 (Unsaturated
    Alkene)
  • C-H 1667 2000 cm-1 (Aromatic
    Overtones)
  • C-H 2150 cm-1 (Stretch)

64
Infrared Spectroscopy
Functional Type of Frequency Group Vibration
cm-1 Intensity
Alkanes (C-H) (stretch) 3000-2850 s
-CH3 (bend) 1450 1375 m -CH2
(bend) 1465 m Alkenes (CC) (stretch) 3100-3000
m (bend) 1000-650 s Aromatics (stretch) 3150-30
50 s (OOP bend) 1000-650 s Alkyne
(C?) (stretch) 3300 s Aldehyde
(CHO) (stretch) 2900-2800 w (stretch) 2800-2700
w
65
Infrared Spectroscopy
  • Correlation Table
  • Functional Group Frequency (cm-1) Intensity
  • C?C Alkane Not Useful
  • CC Alkene 1680-1600 m-w
  • Aromatic 1600-1400 m-w
  • CC Alkyne 2250-2100 m-w
  • CC-H Alkyne (terminal) 3300 s
  • CO Anhydride 1810 s
  • 1760 s
  • Ester 1750-1730 s
  • Aldehyde 1740-1720 s
  • Ketone (acyclic) 1725-1705 s
  • Carboxylic Acid 1725-1700 s
  • Amide 1700-1640 s

66
Infrared Spectroscopy
  • Correlation Table
  • Functional Group Frequency(cm-1)
    Intensity
  • C-O Alcohols, Ethers 1300-1000
    s Esters, Acids
  • O-H Alcohols, Phenols
  • Free 3650-3600
    m
  • H-Bonded 3400-3200
    m
  • Carboxylic Acids 3300-2500 m
  • N-H Primary Sec Amines 3500
    m
  • CN Nitriles 2260-2240
    m
  • NO Nitro (R-NO2) 1600-1500
    s

  • 1400-1300 s
  • C-X Fluoride 1400-1000
    s
  • Chloride 800-600
    s
  • Bromide, Iodide lt600
    s

67
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 1. Check for the presence of the Carbonyl
    group (CO) in the range 1660 1820 cm-1.
  • If the Carbonyl Group is present, one of the
    following types of compounds is present
  • Carboxylic Acid
  • Ester
  • Amide
  • Anhydride
  • Aldehyde
  • Ketone
  • Acid Chloride
  • If the molecule is conjugated (alternating
    double single bonds), the strong (CO)
    absorption will be shifted to the right by 30
    cm-1

68
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 2. Check for the presence of Saturated
    Alkane structures
  • Compounds containing just Methyl (CH3)
    Methylene (CH2) groups produce generally simple
    IR spectra
  • CH sp3 absorption is a stretch in the range
    3000 2840 cm-1
  • Note It is important to remember that the
    Alkane sp3 stretch occurs on the
    right side of the 3000 cm-1 mark in the IR
    spectrum and that Alkene and Aromatic sp2
    stretches occur on the left side of the 3000
    cm-1 mark (see next slide).
  • CH3 Methyl groups (CH3) have a characteristic
    bending at 1375 cm-1 and a smaller
    absorption at 1450 cm-1.
  • CH2 Methylene groups (CH2) have characteristic
    bending at approximately 1465 cm-1

69
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 3. Check for the presence of unsaturated
    (CH) sp2 structures.
  • CH sp2 absorption is a stretch in the range
    3000 3100 cm-1, i.e., on the left side of the
    3000 cm-1 mark on the x-axis scale.
  • Step 4. Determine whether the CH bond is
    Aliphatic Alkene, Aromatic, or both.
  • For Alkene CH bonds, look for the CC stretch
    at 1600 1650 cm-1, usually an unequal pair of
    absorptions.
  • Out-of-Plan (OOP) bending at 650 1000 cm-1
  • Note See next slide or the table on page 895 of
    Pavia text for guide to substitution patterns
    on substituted alkenes.

70
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Out of Plane (OOP) substitution patterns
    (substituted alkenes)

71
Infrared Spectroscopy
  • IR SpectrumAliphatic Alkene

1-Hexene
CAS 592-41-6
C6H12
72
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 4 (Cont)
  • Aromatic C-H bonds.
  • Look for CC stretch - (pair of absorptions at
    1450 cm-1 and a pair of absorptions at 1650 cm-1
  • Overtone/Combination bands appear between1667
    2000 cm-1
  • Out-of-Plain (OOP) bending between 650 1000
    cm-1
  • Note See next slide or the table on page 897 of
    Pavia text for guide to substitution
    patterns on Benzene ring.
  • Note The substitution pattern information in
    the Overtone area and the OOP
    area is duplicative. Use both tables
    to confirm substitution pattern

73
Infrared Spectroscopy
74
Infrared Spectroscopy
  • IR Spectrum(Aromatic)

Toluene (Methyl Benzene)
C7H8
CAS 108-88-3
75
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 5. Carbonyl Compounds (Carboxylic Acids)
  • Strong band of CO group appears in range
    1700-1725 cm-1.
  • Very broad absorption band of the OH group in the
    range2400-3400 cm-1.
  • This broad band will usually obscure the Alkane
    C-H stretch bands from 2849-3000 cm-1.
  • Medium intensity C-O stretch (as in C-OH) occurs
    in the range 1210-1320 cm-1

76
Infrared Spectroscopy
  • IR SpectrumCarboxylic Acids

Isobutyric Acid
C4H8O2
CAS 79-31-2
77
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 6. Carbonyl Compounds (Esters)
  • CO stretch appears in the range 1730-1750 cm-1
  • Check for 2 or more C-O stretch bands, one
    stronger and broader than the other, in the range
    1100-1300 cm-1


78
Infrared Spectroscopy
  • IR SpectrumEsters

Methyl Benzoate
C8H8O2
CAS 93-58-3
79
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 7. Carbonyl Compounds (Anhydrides)
  • 2 CO stretch bands (1740-1775 cm-1 1800-1830
    cm-1)
  • Conjugation will move these bands to lower
    frequency
  • Multiple C-O stretch bands in the range 900
    1300 cm-1

80
Infrared Spectroscopy
  • IR SpectrumAnhydrides

Propionic Anhydride
C6H10O3
CAS 123-62-6
81
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 8. Carbonyl Compounds (Amides)
  • CO stretch at approximately 1640-1700 cm-1
  • N-H stretch (medium absorptions) near 3500 cm-1
  • Primary Amino (-NH2) - 2 Peaks (3180 3350 cm-1)
  • Secondary Amino (-NH) - 1 Peak (3300 cm-1)
  • N-H Scissoring - 1550 - 1640 cm-1
  • N-H Bend - 800 cm-1


82
Infrared Spectroscopy
  • IR SpectrumAmides

Benzamide
Aromatic Overtones
UnsatdC-H Stretch
-C-N str
N-H Scissoring
NH2 Stretch2 peaks Primary Amino

CC Aromatic
CO Carbonyl
C7H7NO
CAS 55-21-0
83
Infrared Spectroscopy
Acetanilide (N-Phenylacetamide)
  • IR SpectrumAmides

C8H9NO
CAS 103-84-4
84
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 9. Carbonyl Compounds (Aldehydes)
  • CO stretch appears in the range 1720 - 1740
    cm-1
  • 2 weak Aldehyde C-H stretch absorptions near 2850
    and 2750 cm-1)

85
Infrared Spectroscopy
  • IR SpectrumAldehydes

Nonanal
C9H18O
CAS 124-19-6
86
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 10. Carbonyl Compounds (Ketones)
  • CO stretch occurs at approximately 1705 1725
    cm-1
  • Ketones are confirmed when the other five
    compound types containing a Carbonyl group have
    been eliminated.
  • Ketone IR Spectra can sometimes be confused with
    Ester spectra because of an absorption in the
    1100 -1300 cm-1 range similar to the location of
    the C-O stretch in esters. Usually, however, the
    ester will have 2 or more of the C-O stretch
    absorptions.

The Ketone structure produces a medium to strong
absorption in the 1100 1300 cm-1 range due to
coupled Stretching and Bending vibrations
87
Infrared Spectroscopy
  • IR SpectrumKetones

Ethyl Isopropyl Ketone (2-Methyl-3-Pentanone)
C6H12O
CAS 565-69-5
88
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 11. Triple Bonds
  • Alkynes
  • R C C R weak, sharp stretch near 2150 cm-1
  • R C C H (Terminal Acetylene)
  • Weak, sharp stretch near 2150 cm-1
  • and a second stretch at
    3300 cm-1
  • Nitriles
  • C N Medium, sharp stretch near 2250 cm-1

89
Infrared Spectroscopy
Propargyl Alcohol (2-Propyn-1-ol)
IR SpectrumAlkynes (C?C)
CCStretch
Aliphatic C-H Stretch
OH H - Bonded
CH2
C-H Terminal Alkyne Stretch
C-O
C3H4O
CAS 107-19-7
90
Infrared Spectroscopy
IR SpectrumNitriles
Benzonitrile
C7H5N
CAS 100-47-0
91
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 12. - Alcohols Phenols
  • Broad absorption near 3600 - 3300 cm-1
  • Confirm presence of CO (COH) near 1000 - 1300
    cm-1

92
Infrared Spectroscopy
IR SpectrumAlcohols Phenols
2-Naphthol (Nujol Mull)
C10H9O
CAS 135-19-3
93
Infrared Spectroscopy
IR SpectrumAlcohols Phenols
2-Naphthol (CCl4 Soln)
C10H9O
CAS 135-19-3
94
Infrared Spectroscopy
IR SpectrumAlcohols Phenols
2-Naphthol (KBr Disc)
C10H9O
CAS 135-19-3
95
Infrared Spectroscopy
IR SpectrumAlcohols Phenols
2-Butanol
C4H10O
CAS 78-92-2
96
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 13. Ethers
  • CO absorptions near 1000 - 1300 cm-1
  • Absence of OH
  • Absence of CO group
  • Aliphatic Ethers give a single strong C-O band
    at1120 cm-1
  • Unbalanced Ethers will show 2 CO groups
  • Phenyl Alkyl Ethers give two (2) strong bands at
    about 1040 1250 cm-1

97
Infrared Spectroscopy
IR SpectrumEthers
Butyl Ether(Balanced Ether)
CH3
CH2
Aliphatic C-H Stretch
C-O
CH3(CH2)3 O (CH2)3CH3
C8H18O
CAS 142-96-1
98
Infrared Spectroscopy
IR SpectrumEthers
Phenetole (Unbalanced Phenyl Alkyl Ether)
C8H10O
CAS 103-73-1
99
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 14. Amines
  • N-H stretch (Medium absorptions) near 3500 cm-1
  • Primary Amino - 2 Peaks
  • Secondary Amino - 1 Peak
  • Tertiary Amino - No peaks
  • N-H Scissoring at 1560 - 1640 cm-1
  • N-H Bend at 800 cm-1

100
Infrared Spectroscopy
n-Butylamine(Primary Amine)
IR SpectrumAmines
C4H11N
CAS 109-73-9
101
Infrared Spectroscopy
N-Methylbenzylamine(Sec Amine)
IR SpectrumAmines
AromaticOvertones
N-H Scissoring
Sec-Amino
Unsat C-H Stretch
Sat C-H Stretch
Aromatic ring CC Absorptions
CH3
CH3
-N-H OOP Bending
C-N Str
N-H Scissoring
CH2
OOP Bending Aromatic Monosubstitution
CH2
Aliphatic C-H Stretch
C6H11N
CAS 103-67-3
102
Infrared Spectroscopy
  • Analyzing the Spectrum A Suggested Approach
  • Step 15. Nitro Compounds
  • Two strong absorptions
  • Aliphatic Nitro Compounds
  • Asymmetric strong stretch 1530 - 1600 cm-1
  • Symmetric medium stretch 1300 - 1390 cm-1
  • Aromatic Nitro Compounds
  • Asymmetric strong stretch 1490 - 1550 cm-1
  • Symmetric strong stretch 1315 - 1355 cm-1

103
Infrared Spectroscopy
IR SpectrumNitro Compounds
Nitro Benzene
C6H5NO2
CAS 98-95-3
104
Infrared Spectroscopy
IR SpectrumNitro Compounds
1-Nitro Propane
C3H5NO2
CAS 108-03-2
105
Infrared Spectroscopy
  • Step 16. If none of the above apply then the
    compound is most likely a
  • Hydrocarbon
  • Alkyl Halide (see slides 105 - 109).
  • Hydrocarbons
  • Generally, very simple spectrum
  • C-H Satd Alkanes 2900 - 3000 cm-1
  • Methyl (CH3) 1370 cm-1
  • Methylene (CH2) 1450 cm-1
  • t-Butyl Group 525 cm-1
  • Long Alkane (CH2) Chain 720 cm-1

106
Infrared Spectroscopy
IR Spectrum Alkane
Decane
CH3(CH2)8CH3
C10H22
CAS 124-18-5
107
Infrared Spectroscopy
  • Step 17. Halogens
  • The Halogens as CH2 - X absorptions show up in
    the region (1000 1300 cm-1).
  • Halogens (Cl, Br, I) show in the Fingerprint
    region (485 800 cm-1) as one or two absorptions
    see next slide.
  • Using IR to identify Halogens in this region can
    be difficult, especially if OOP Bending
    absorptions (used for Substitution Pattern
    information) from Alkene and Aromatic unsaturated
    Pi (?) bond structures are present.
  • Halogen identification should be restricted to
    Aliphatic Alkane structures containing mainly CH2
    CH3 groups.
  • Iodide and Bromide absorptions in the range 485
    650 cm-1 are generally out range on NaCL Salt
    Plates, however, if other substrates, e.g.,KBr
    pellets, are used, the absorptions are extended
    to this range.

108
Infrared Spectroscopy
  • Step 17. Halogens (Cont)
  • Fluoride 1000 1400 cm-1
  • Monofluorides 1000 1200 cm-1
  • Polyfluorides 1100 1300 cm-1
  • Aryl Fluorides 1100 1250 cm-1
  • Chloride (2 or more bands) 540 785 cm-1
  • CH2-CL (Bend Wagging) 1230 1300 cm-1
  • t-Butyl Group
    525 cm-1
  • Bromine (KBr Pellets) 510 650 cm-1
  • CH2-Br (Bend Wagging) 1190 1250 cm-1
  • Aryl Bromides 1030 1075 cm-1
  • Iodide (KBr Pellets) 485 600 cm-1
  • CH2-I (Bend Wagging) 1150 1200 cm-1

109
Infrared Spectroscopy
IR SpectrumHalogens
2-Bromobutane
Br
CH3
-C-H Satn
CH2
CH2-Br
C4H9Br
CAS 78-76-2
110
Infrared Spectroscopy
IR SpectrumHalogens
1-Chloropropane
C3H7Cl
CAS 540-54-5
111
Infrared Spectroscopy
IR SpectrumHalogens
o-Chlorotoluene
C7H7Cl
CAS 95-49-8
112
Infrared Spectroscopy
IR Spectrum Halogens
T-Pentyl Chloride (2-Chloro-2-MethylButane
T-Pentyl 525 cm-1
CH3
CH2
Saturated Aliphatic C-H Stretch
CH2-Cl
C5H14CL
CAS 594-36-5
113
IR Analysis Scheme
Carbonyl (CO) _at_ 1715-1685 (Conjugation moves
absorption to right 30 cm-1
Yes
No
Acid Ester Amide Anhydride Aldehyde Ketone
Alcohol Amine Ether
Saturation lt 3000 cm-1
Unsaturation gt 3000 cm-1
Alkanes -C-H Methylene -CH2 Methyl -CH3
Alkenes (Vinyl) -CC Alkynes (Acetylenes) -CC Aro
matic -CC
Nitriles
Nitro
Hydrocarbons
114
IR Analysis Scheme
Carbonyl (CO) is Present Acid - Broad OH
Absorption _at_ 3300-2500 cm-1 Ester - C-O
Absorption _at_ 1300-1000 cm-1 Amide - NH Absorption
_at_ 3500 cm-1 (1 or 2 peaks) Anhydride - 2 CO
Absorptions 1810 1760 cm-1 Aldehyde - Aldehyde
C-H Absorptions _at_ 2850 2750 cm-1 Ketone - None
of the above except CO
Carbonyl is Absent Alcohol - Broad OH absorption
_at_ 3300 - 3000 cm-1 Also C-O
absorption _at_ 1300 - 1000 cm-1 Amine - 1 to 2
equal NH absorptions _at_ 3500 cm-1 Ether - C-O
absorption _at_ 1300 - 1000 cm-1
115
IR Analysis Scheme
Saturation
Alkanes -C-H Stretch several absorptions to
right of 3000 cm-1 Methylene -CH2 1450
cm-1 Methyl -CH3 1375 cm-1
Unsaturation
Double Bonds C-H Stretch several absorptions
to left of 3000 cm-1 OOP bending at 1000
650 cm-1 Alkenes (Vinyl) -CC- Stretch (weak) _at_
1675 1600 cm-1
Conjugation moves absorption to
the right Alkynes -CC-H Terminal Acetylene
Stretch at 3300 cm-1 Alkynes (Acetylenes) -CC Str
etch _at_ 2150 cm-1
Conjugation moves absorption to the
right Aromatic (Benzene) C-H Stretch absorptions
also to left of 3000 cm-1 OOP bending at 900
690 cm-1 OOP absorption patterns allow
determination of ring substitution (p.
897 Pavia text) -CC 4 Sharp absorptions (2
pairs) _at_ 1600 1450 cm-1 Overtone absorptions
_at_ 2000 1667 cm-1 Relative shapes and numbers
of peaks permit determination of ring
substitution pattern (p. 897 Pavia text).
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