Title: Tools of the Trade math, physics, and chemistry for understanding and assessing environmental proble
1Tools of the Trademath, physics, and chemistry
for understanding and assessing environmental
problems
2Data Sources
- COW appendices for conversion factors, physical
constants, data on earth, natural stocks/flows of
air/water/nutrients/energy, biosphere, elements,
chemical reactions - World Resources for up-to-date data on
population, economics, food, land use change,
energy supply/consumption, emissions - http//earthtrends.wri.org/
3Whats wrong with this table?
4Reporting Numbers
- Report only significant digits. This tells the
reader how accurately the number is known. - WR reports 1996 CO2 emissions as 23,881,952
thousand tons (8 sig digits!). This implies an
accuracy of 1000 tons, or 0.00001. - The true accuracy of this estimate is about ?5
(?1 billion tons) only 2 digits are significant
and should be reported 24 billion tons - Few estimates are accurate to more than 2 or 3
significant digits
5Significant Digits
- Results have as many significant digits as the
least-significant number used in the calculation.
- Examples
Rounding should be the very last step. Keep at
least one more significant digit in intermediate
calculations.
6Spurious Rounding
Physicist rounds on measurement boobs Monday
December 9, 2002 Large numbers of women are
wearing the wrong-sized bra because of a
mathematical error known as "spurious rounding"
claims a University of Southampton physicist. In
"Graphical Analysis of Bra Size Calculation
Procedures", published in the International
Journal of Clothing, Science and Technology, Dr
Matthew Wright has analysed the effects of small
errors in measurements. "To do this properly
requires making two measurements, one around the
rib cage and one around the bust. These two
numbers then have to be converted to an even
number and a letter, and this is where the
problem arises." The standard procedure for
making this calculation instructs the user to
convert the first number by adding four if it is
even and five if it is odd, effectively rounding
it to the nearest two inches. This rounded number
is then subtracted from the second number (also
rounded to the nearest inch) to give the cup
size. Because one rounded number is subtracted
from another any errors will accumulate. Dr
Wright explains "It's a well-known effect called
- perhaps somewhat unfortunately in this context
- 'spurious rounding'. It might seem surprising
but if this procedure was obeyed exactly then a
small error could, in principle, make the
difference between predicting a size of 36A and
one of 34D." His paper suggests an alternative
method of measurement for women fitting
themselves, which reduces the possibility for
error, where the subtraction is done before the
rounding.
7Scientific Notation
- Because we will often deal with very small or
very large numbers, we will sometimes use
scientific notion - Examples
- 1,000 10?10?10 103
- 2,000 2?103
- 321,000 3.21?105
- 0.0029 2.9?103
- 0.000006 6?106
8Units of Measure
- We will use metric units in this course, also
known as SI (international system) units - Because English units are common in the US, we
will convert from English to/from metric - SI units have been officially adopted and steps
have been taken to convert from older units of
measure in all but three countries. - Can you name the other two?
9SI Base Units
- meter (m)
- kilogram (kg)
- second (s)
- kelvin (K)
- mole (mol) 6.02?1023 atoms or molecules
- nucleons (protons and neutrons) have a mass of
1.67?1024 gram thus, 6.02?1023 nucleons have a
mass of 1 gram (g) - (1.67?1024 g/nucleon)(6.02?1023 nucleons) 1 g
- 6.02?1023 carbon atoms (each with 6 protons and
6 neutrons) have a mass of exactly 12 g - Also ampere and candela, but not used in this
class
10Derived Units
11Other Units
12Prefixes
13Prefixes
- Examples
- kilogram kg 103 g
- kilometer km 103 m
- centimeter cm 102 m
- exajoule EJ 1018 J
- kilowatt kW 103 W 1 kJ/s
- teragram Tg 1012 g 109 kg 106 t 1 Mt
- 23,881,952 thousand tons 24 Gt 24 Pg
14A Few Conversion Factors
- 1 foot 0.3048 m 1 mile 1609 m
- 1 acre 4047 m2 1 ha 2.47 acre
- 1 gal 3.785 L 1 bbl 42 gal 1 acre-ft 1234
m3 - 1 year (y) 8766 hours (h) 3.15?107 s
- 1 pound 0.454 kg
- 1 BTU 1055 J 1 calorie 4.184 J
- 1 horsepower 746 W
- 1 K 1 ?C 1.8 ?F K 273 ?C
15Other Useful Facts
- Density of water 1 t/m3 1 kg/L 1 g/cm3
- Density of air ? 1 kg/m3 1 g/L
- Density of any gas at STP 0.045 mol/L
- Acceleration of gravity 9.81 m/s2
16Unit Conversion
- Line up units so they cancel.
- Susquehanna River average discharge 27 million
acre-feet per year to convert into m3/s
- Do it in your headits easier than you think!
17- Earth is approximately a sphere with a radius of
6370 km the surface area is therefore
- 510 million square kilometers 51 Gha
- Oceans cover 70 of this area. The mean depth is
4 km, so the volume is
- The mass of the oceans is
18Basic Physics
- The most important physics concepts in this
course are energy (J) and power (W J/s) - Energy comes in many forms
- Electromagnetic
- Chemical (stored in atomic bonds)
- Nuclear (stored in nuclear bonds)
- Mechanical (kinetic and potential)
- Thermal (heat)
- Power is a flow of energy
19Dimensional Analysis
- Many problems can be solved by getting the units
right you dont have to know physics. - How much power can you generate with a dam
10-meter-high across the Susquehanna? - I want
- power W J/s kg?m2/s3
- I know
- average water flow 1100 m3/s
- water density 1 t/m3 1000 kg/m3
- head or distance water falls 10 m
20Power in Susquehanna River
Turbines can convert 90 into electricity. The
16-m-high Holtwood dam in Lancaster County, PA,
has a capacity of 108 MW.
21Holtwood dam, Lancaster, PA16 m, 108 MW
Conowingo dam, Cecil Co., MD32 m, 512 MW
22Power in Susquehanna River
23Power in the Wind
- A large wind turbine has 70-m rotor diameter. How
much power generated in a 20 mph wind? - We know
- area swept ?r2 ?(35 m)2 3848 m2
- density of air 1.3 kg/m3 (COW, p. 236)
- velocity of wind
24- This omits a factor of ½, because kinetic energy
is ½mv2. So the power in the wind is
- One cannot extract all this powerthe air would
pile up! Theoretical maximum is 59 40-50 can
be achieved in practice (800 kW).
2544 1.5-MW turbines are being installed in Tucker
County, WVA Blades are 34 m long tower is 70 m
high
26Chalk Point683 MW coal-fired electricity
27Chalk Point How Much Coal?
- Chalk Points two coal-fired steam generators
produce 683 MW of electricity - Energy content of coal 29 MJ/kg 29 GJ/t (COW,
p. 242)
28Chalk Point How Much Coal?
- This assumes that 100 of the coal energy is
converted into electrical energy - In practice, only 35-40 is converted the rest
is rejected as heat to the environment
At 55 t/car, this requires about one 100-car
train per day!
29Thermal Efficiency
- Coal plants produce steam at ?840 K (570 ?C or
1050 ?F) waste heat is discharged to the air or
water at ?300 K (27 ?C or 80 ?F) - Theoretical maximum (Carnot) efficiency
- Efficiency that maximizes power production
30Thermal Efficiency
- As temperature difference between heat source and
heat sink in reduced, efficiency is reduced - Geothermal
- TH 520 K, TC 350 K, ?max 0.18
- (250 C, 480 F) (80 C, 170 F)
- Ocean thermal
- TH 300 K, TC 277 K, ?max 0.04
- (27 C, 80 F) (4 C, 40 F)
31Other Basic Physics
- Conservation of energy
- (potential kinetic internal) constant
- Example mgh ½mv2 mCT
- Conservation of mass
- total mass before total mass after
- Conservation of charge
- total charge before total charge after
32Basic Chemistry
- Know how to read a periodic table
- How to read molecular formula
- How to determine molecular weight
- How to compute gas mixtures
- How to read basic chemical equations
33(No Transcript)
34Atomic number 6 All carbon atoms have six
protons
Atomic weight 12.01 One mole of carbon
(6.02x1023 atoms) has a mass of about 12
grams (not exactly 12 1.1 is carbon-13, which
has 7 neutrons the rest is carbon-12, with 6
neutrons (0.011)(13) (0.989)(12) 12.011)
35Periodic Tables on the Web
- http//pearl1.lanl.gov/periodic/
- http//www.webelements.com/
- http//www.chemicalelements.com/
- http//environmentalchemistry.com/
- http//www.chemicool.com/
36Molecular Weight
- Atomic weights H 1, C 12, N 14, O 16
- Molecular weights
- N2 2(14) 28 g/mol
- O2 2(16) 32 g/mol
- H2O 2(1) 16 18 g/mol
- CO2 12 2(16) 44 g/mol
- In 1996, 23.9 Gt of CO2 released how much C?
37Average Molecular Weight
- A mole of any gas (6.02?1023 molecules) at a
given T, P occupies the same V (22.4 L _at_ STP) - Thus, gas mixtures are given in by volume
molecules - Air is 78 N2, 21 O2, 1 Ar, 375 ppm CO2
- 78 of air molecules are N2 molecules
- 375 of every million air molecules are CO2
- Average molecular weight of air
- (0.78)(28) (0.21)(32) (0.01)(40) 28.96
38If you are fastidious about units
By knowing the pressure and composition of air at
sea level, one can estimate with fair accuracy
the total mass of the atmosphere and the number
of air molecules
39Mass, Moles of Atmosphere
- Mass of atmosphere 5.14?1018 kg
- Number of moles of dry air 1.78?1020
40CO2 Emissions
- CO2 emissions from fossil-fuels, 1996 23.9 Gt
- How many moles? How would CO2 concentration
increase if all this stayed in atmosphere?
- Actual increase 1.5 ppmv ?50 absorbed by
oceans, forest regrowth
41Fraction by Weight
- CO2 is 27 C, 73 O by weight
- Very roughly, biomass is C6H12O6, or 40 C
1 t CO2 273 kg C
42Estimation
- In addition to physics and chemistry,
environmental science relies heavily on
estimation and bookkeeping (stocks, flows) - One would might prefer to look up the right
answer or best value, but often this is not
easily available and may not even exist - This class will help you become comfortable with
estimation, and better at it - Sometimes called back-of-the-envelope
calculations
43Area, Volume of Chesapeake Bay
- How long is the Bay (north-south)?
- What is the average width?
- What is the average depth?
44Chesapeake Bay
200 mi
25 mi
15 mi
100 miles
45Area, Volume of Chesapeake Bay
- How long is the Bay (north-south)?
- What is the average width?
- (200 mi)(15 mi) 3,000 mi2
- actual area 3,238 mi2
- What is the average depth?
46Volume of Chesapeake Bay
47How Many Haircutters in CP?
- Population ? 25,000 8,000 students ??
- How many haircuts per person per year?
- How many haircuts per haircutter per day?
Yellow Pages lists 15 barbershops and hair salons
in College Park. Assuming an average of 4 cutters
per salon, there are 60 cutters.
- Average cost per cut?
- Average gross income per cutter per year?
48How Many Rubber Bands?
- I used rubber bands in mail, food, etc. for 3 y
to make a 3-lb ball 14 cm in diameter. - How many rubber bands are in the ball?
- I estimated the number of rubber bands in four
different ways. How many can you think of? - Answers 1300, 1400, 1500, and 1600.
49How Many Rubber Bands?
- Method 1 Rate of collection
Method 2 Mass ratio Using a postage scale, 28
RB weigh 1 oz
50How Many Rubber Bands?
- Method 3 Volume ratio
- RB is 20 cm long, 0.5 cm wide, 0.1 cm thick
- (20 cm)(0.5 cm)(0.1 cm) 1 cm3
Method 4 Ratio to known standard A 12.7-lb ball
is known to contain 6,200 RB
51Size of Asteroid
- The mass extinction 65 My BP probably was caused
by asteroid impact. Geologists have discovered a
65-My-old, 0.1-mm-thick, Ir-rich layer of dust
everywhere on earth. - About 20 of the asteroid ended up as fine dust
in the upper atmosphere, eventually settling out
uniformly over the earths surface. - How large was the asteroid?
524 times the volume of Chesapeake Bay
5 miles in diameter!
53For comparison, yield of combined US Russian
nuclear stockpiles ? 1019 J, so asteroid impact ?
10,000 x energy released in an all-out nuclear
war!
54Drilling in ANWR
- USGS estimates that, if opened for drilling, ANWR
would yield 6 to 16 billion barrels - Is this a lot of oil? Most oil is used for
gasoline. What is U.S. gasoline consumption? - How many cars?
- What is the average miles/year?
- What is the average miles/gallon?
55US Gasoline Consumption
- Actual gasoline consumption 126?109 gal/y
- Total oil consumption (diesel, fuel oil,
lubricants, solvents, asphalt, etc.) 7.2
Gbbl/y ANWR 0.8 to 2.2 y of US consumption at
current rate
56US Gasoline Consumption
- WRI gives US consumption of liquid fuels 855
million metric tons oil equivalent (toe) using
toe 41.868 GJ, and energy content of bbl oil
from COW VII.4
57Caesars Last Breath
- How likely is it that you will inhale, in your
next breath, at least one of the air molecules
exhaled by Julius Caesar in his dying breath? - How many molecules are exhaled in one breath?
- What is the concentration of such molecules in
the atmosphere? - How many such molecules will I inhale in my next
breath?
58Molecules per Breath
- COW XV (p. 263) gives characteristics of a
standard adult man - Breathing rate, resting 6-8 breath/min 7.5
L/min, so one breath ? 1 L - One liter of any gas contains 0.045 moles at STP,
but we also could compute this given the density
and molecular weight of air
59Concentration in Atmosphere
- The molecules Caesar exhaled are now uniformly
mixed throughout the atmosphere. The
concentration of cdb molecules is
Sometimes called the mixing ratio
- In your next breath, you inhale 1 L (0.045 mol)
of air, with an average of 7 molecules exhaled by
Caesar in his dying breath
60Residence Time of Air Molecules
- Probability of inhaling no cdb molecules in
your next breath - POISSON(0,7,0) 0.0009
- Can we be sure that the air molecules that Caesar
exhaled are still in the atmosphere, and that
they are uniformly mixed? - yes, well come back to this later
61Nitrogen Runoff into Chesapeake
- Recall the discharge of the Susquehanna
- Lancaster County contains ?100,000 cows. Each cow
produces ?120 lb/d wet manure (75 water). Dry
manure is ?5 nitrogen.
62Nitrogen Runoff into Chesapeake
- Half of the N produced runs off into the river
- Measured level ?3 ppm thus, Lancaster cows are
about 1/10th of problem - Other sources other farm animals (pigs,
chickens) other counties human waste vehicle
and power-plant emissions
63Ecology USA (11 Nov 1996)
- The Biomass for Rural Development program
centers on a 2600 acre tract where officials hope
to develop hybrid, faster-growing willows that
will produce between 3747 MW, or enough power to
light 40,000 homes. Officials, who hope the
willows will provide a viable energy source by
2000, project willow-based sales could be as much
as 20 million per year, which could lead to 135
million worth of related energy sales. - How much wood can be produced (t/yr)?
- How much is this wood worth (/yr)?
- How much electrical power (MW)?
- How many homes can this light?
64How Much Wood?
- From Harte, NPP of temperate forests 0.56
kg(C)/m2-yr biomass 37 carbon - Compare to best average yields of 8 t/acre
65How Much Is Wood Worth?
- As heating fuel, wood cannot be more valuable per
J than other solid fuels coal - Coal costs 30/t energy content is 29 GJ/t, v.
15 GJ/t for dry wood
Compare to 20 million/y cited in article
66How Much Electricity?
- 3 J of heat can produce 1 J of electricity
- Retail price of electricity ? 0.1/kWh
Compare to 37-47 MWe, 135 million/y cited in
article
67How Many Homes?
- US residential sales 1.2?1012 kWh/y
- ?100 million households in US
- 1.2?1012/108 12,000 kWh/household?y
- Project can produce 30?106 kWh/y
33 of total
Article enough to light 40,000 homes Lighting
is ?10 of residential demand
68Box Models
- Natural systems are characterized by the
transport of substances (water, nutrients,
toxics), organisms, and energy from one reservoir
to another. - Reservoirs can be physical (air, ocean), chemical
(different chemical forms), or biological (live
biomass, dead organic matter) - Flows can be bulk motion, diffusion, convection,
conduction and radiation, chemical or nuclear
reactions, phase change
69Uses of Box Models
- Predicting concentrations in organs after
inhalation or ingestion of substance setting
standards for exposure/intake of substances - Water pollution, outdoor/indoor air pollution
predicting concentrations in various
environmental reservoirs as a function of time - Population dynamics, predator-prey and food-chain
models, fisheries, wildlife management - Climate models (energy, air, water)
70Box Models
- We represent the reservoirs with a box we
usually assume the box is well-mixed, and we
usually are not concerned with internal details
Stock, S
Inflow, Fin
Outflow, Fout
- Basic rule inflow outflow change in stock
- Flows (Fin, Fout) constant over small time ?t, so
71Equilibrium
- If Fin Fout, then dS/dt 0 and the stock is
constant with time a state of equilibrium. - Most natural systems are in quasi-equilibrium
- Equilibrium means a particular quantity (stock)
is not changing significantly over some time - doesnt mean nothing is happening, every-thing is
constant, or constancy is permanent - equilibrium can be dynamic or static
- equilibrium can be stable or unstable
72Equilibrium
Stable
Unstable
Neutral
Locally Stable
73Residence Time
- If a quantity is near equilibrium, the
characteristic response time of the system is
- Residence time is often the single most important
characteristic of a natural system - if ? large, system is resistant to change but,
once perturbed, slow to return - if ? small, system is quick to respond to
perturbations, but quick to return
74Hydrological Systemstocks and flows 1012 m3
103 km3 (COW, VI.2-3)
75Hydrological System
76Carbon(COW, XII.1)
77Chesapeake Bay
- Stock of water 68 km3
- Flow in from Susquehanna 33 km3/y Susquehanna
is about 50 of total flow in
- Ignores precipitation, evaporation, groundwater,
tidal flows - Not good example because not well-mixed
78Mono Lake
79Mono Lake
- High-altitude basin lake (no outflow, saline)
brine shrimp and islands provide important
habitat for migratory birds - Before 1940, quasi-equilibrium (Fin ? Fout)
- Elevation 6417 ft
- Area 55,000 acres (55 kac)
- Volume 4300 kac-ft
- Fin streams (150 kac-ft/y) groundwater in
(40 kac-ft/y) precipitation (8 in/y) - Fout evaporation groundwater (25 kac-ft/y)
What is the average depth?
80Evaporation 202 kac-ft/y
Precipitation 37 kac-ft/y
Stream Runoff 150 kac-ft/y Rush, Lee Vining, Mill
creeks
Mono Lake V 4,300 kac-ft A 55 kac
Groundwater out 25 kac-ft/y
Groundwater in 40 kac-ft/y plus non-stream runoff
81Estimating Runoff
- In this example, stream flows were measured.
For a watershed (drainage basin) - Precip Evap Runoff Groundwater
- Average precipitation 21 in/y 1.74 ft/y
- Average evaporation 40 8.4 in/y
- Average groundwater recharge 35 7.3 in/y
- Average runoff 25 5.2 in 0.43 ft/y
- Watershed area 432 55 377 kac
- Runoff (377 kac)(0.43 ft/y) 160 kac-ft/y
82Mono Lake Watershed
83Residence Times
- Residence time of water in Lake Mono
- (and substances that co-distill with water, like
DDT, PCBs)
- Residence time of other dissolved substances
84Concentrations
- Suppose a toxic substance that co-distills with
water flows into Mono Lake at a constant rate of
1000 kg/y. What is the concentration? - After a long time, fin fout f 1000 kg/y
85Concentrations
- Most substances dont codistill with water in
this case, ? 170 y and c 32 ppb. - We could also get this answer by assuming that
the toxic flow out is contained in the
groundwater flow out
86Concentration
- If we measure a concentration of 5 ppm in the
lake water, then at what rate is the substance
flowing into the lake?
87Natural Sources of N2O
- Nitrous oxide is a greenhouse gas. The
preindustrial concentration in the atmosphere was
275 ppbv (v. 317 ppbv today) - N2O is inert and nonreactive in the troposphere
it diffuses to the stratosphere, where it is
destroyed photochemically - The residence time in the atmosphere is about 120
years - What is the natural (preindustrial) flow of N2O
into the atmosphere?
88Natural Sources of N2O
Photochemical destruction
Fout
c 275 ppbv ? 120 y
Natural Flow
Best estimates 9.6 and 10.8 TgN/y (with
uncertainties of ?5)
Fin
89Great Lakes Watershed
90Great Lakes A 5-Box Model
91What If Flows Are Not Constant?
- If flows are not constant, then we must solve the
differential equation
- Simplest case is when the difference between Fin
and Fout is constant
92Exponential Growth
- Next simplest is when flow in (or out) is
directly proportional to the stock
- Put 100 in an account with r 0.1/y after 10
years you have (100)e(0.1/y)(10y) 270
93Doubling Time
- The time it takes for the stock to double when
growing at a constant rate r is given by
- If a stock (e.g., US population) is growing 1/y
(r 0.01/y), then it will double in 69 y - At 3.5 (e.g., population of Saudi Arabia), it
will double in 20 y at 7/y, T2x ? 10 y - If St lt S0, r is negative and T½ is the halflife
94Continuous v. Annual Rates
- Growth rate r is called the continuous growth
rate. Most publications give annual yield i
total percentage growth in one year. - The relationship between r and i can be found by
writing the equation for the stock after 1 y
95If r lt 0.1, then i ? rBut i gt r always.S(t)
is given bySt S0(1 i)twhich is identical
to St S0 ertwhere r ln(1i)
96Average Growth Rate
- If you know the stock at times t1 and t2, the
average growth rate is given by - US Pop S2000 281.4, S1990 248.7 million
? 1.2/y
? 1.2/y
97Population Growth
- Populations have flows in (births) and out
(deaths), which are proportional to population - If b d, then r 0 and population is constant
(ZPG) - If b gt d, we have exponential growth at rate r
b d - If b lt d, we have exponential decay at rate r
- Somalia b 50/y per 1000, d 20/y per 1000
- r 0.05 0.02 0.03/y 3/y, T2x 23 y
98Combining Rates
- If P is growing at rate rP, per-capita income is
growing at rate rA, and emissions per dollar of
economic activity at growing at rT, then impact
is growing at rate r (rP rA rT)
99Carbon Emissions
100Carbon Emissions
- Often it is useful to break the IPAT identity
down into more components - For example, emissions intensity (tC/) is the
product of energy intensity (GJ/) and carbon
intensity (tC/GJ)
101Carbon Emissions
102Allocating Blame
- US energy use rose from 89 to 104 EJ/y from 1990
to 2000 (r 0.0158/y). How much of this is due
to population growth (r 0.0121/y)? Growth in
per-capita consumption (r 0.0034/y)?
due to pop growth due to growth in
per-capita consumption
103Exponential Growth of Flows
- We use growth rates for stocks (population) and
flows (/y, energy/y, tons/y) - When flows increase at a constant rate, we can
integrate to find total amount consumed
between time 0 and T
104Exponential Growth
- If consumption rate is growing exponentially,
total consumption in next doubling time equals
all previous consumption
105In this chart, consumption is growing at 7/y
(doubling time 10 y) Consumption in the next
ten years (blue bars) equals total consumption
over all previous years
106Exponential Depletion
- How long to consume a total amount of oil S?
- Suppose we have a 100-y supply of oil at current
rate of consumption (S/F0 100 y), but
consumption is growing 5/y (r 0.05/y)
107Annual Consumption
108Technical Note
- Note that this expression breaks down when r
0, but thats ok because
109Exponential Decay
- If the rate of consumption is decreasing at a
constant rate, then total consumption for all
time is finite - If r 0.05/y, S8 20 F0
Suppose we reduced the annual consumption of a
resource (e.g., mercury) by 1/y forever. Total
consumption over the rest of human history would
be 100 times current annual consumption.
110ANWR v. CAFE
- USGS estimates that, if opened to drilling, ANWR
could produce ?10 billion barrels of oil over a
20-year period, beginning 2010 - 95 confidence interval 6 to 16 Gbbl
- How does the amount of gasoline that could be
produced from ANWR oil compare with - the amount of gasoline that could be saved by
increasing the average fuel economy of passenger
vehicles by 5 mpg?
111Gallons of Gasoline from ANWR
- 1 barrel (bbl) 42 gallons
- On average, ?20 gallons of gasoline are produced
per barrel of oil - the other 22 gallons are used to produce fuel
oil, lubricants, solvents, asphalt, etc.
112Gasoline Consumption 1
- In 2000 passenger vehicles drove 2,540 Gmi and
consumed 126 Ggal of gasoline - Average fuel economy 2540/126 20.1 mpg
- roughly constant since 1990
- each vehicle type is more efficient, but greater
fraction of SUVs, minivans, trucks - If fuel economy was 25.1 mpg, gasoline
consumption would be
113Gasoline Consumption 1
- Savings 126 101 25 Ggal/y
- Over 20 y (25 Ggal/y)(20 y) 500 Ggal
- Compare to ANWR 200 Ggal
- This assumes that VMT are constant, but VMT has
increased steadily - total vehicle miles in 1990 1,990 billion.
- what was average rate of growth?
114Average Rate of Growth
T2X 69/2.5 28 y
- Better method regression with y ln(VMT), x
t slope best-fit growth rate
115Passenger VMT/y, 1966-2000
Passenger Vehicle Miles (Gmi/y)
116Passenger VMT/y, 1966-2000
Passenger Vehicle Miles (Gmi/y)
117Estimated VMT, 2010-2030
F(t) F2000e0.025(t-2000)
Passenger Vehicle Miles (Gmi/y)
Total VMT 2010-2030
118Estimated VMT, 2010-2030
119Gasoline Consumption 2
- Assuming average of 20 mpg
- Assuming average of 25 mpg
- Savings
- 4,250 3,400 850 Ggal
Compare to 500 Ggal, 200 Ggal from ANWR
120DOE Projections
121Logistic Growth
- Exponential growth cannot continue for more than
10 (103) or 20 (106) doubling times - As population grows, growth rate decreases
simplest representation is a logistic function
S8 carrying capacity
exponential growth
no growth
122Logistic Growth Total Stock
S(t) S0ert
S0 1 S8 100 r 0.1/y
123Logistic Growth Annual Increment
S0 1 S8 100 r 0.1/y
124Logistic Growth Rate
S0 1 S8 100 r 0.1/y
125Other Uses for Logistic Equations
- Logistic equations have been used to model
- growth of populations (e.g., C in forest)
- relationships with dependent variable that is a
proportion or a dichotomous variable - spread of epidemics
- diffusion of innovations, market penetration,
transition between industries, processes, fuels
(e.g., percentage of final energy that is coal,
oil, gas, or electricity) - consumption of finite resources (fossil fuels)
126Logistic Fit to SARS Cases
127Oil Consumption
- There is a finite amount of oil that can be
economically recovered S8 - When cumulative consumption, S(t), is small
compared to S8, demand increases exponentially at
rate r - Cheapest, easiest deposits are exploited first
as cumulative consumption increases, price
increases (extraction more expensive, scarcity
rents) and growth rate decreases - When cumulative consumption ? ½S8, demand peaks
and declines thereafter
128US Oil Production
129PA Coal Production
130Three Facts and Some Speculation
- Current rate of oil consumption 163 EJ/y
- Average growth rate, 1990-2000 1.4/y
- Cumulative world consumption ? 6,000 EJ
- Estimates of total recoverable oil resources
range from about 8,000 to 20,000 EJ remaining
resource 2,000 to 14,000 EJ - Lifetime assuming constant consumption
- (S8S0)/F0 12 to 86 y
- Lifetime assuming constant growth
- If r 0.014, T ln(1rS/F)/r 11 to 57 y
131Cumulative Production
Best fit to 1980-2000 Cumulative Production
132Annual Production
Best fit to 1980-2000 Cumulative Production
133Year of Peak Production
134Best-fit Logistic Curves simple method
Assume S8, compute ft St/S8, yt lnft/(1-ft)
135Best-fit Logistic Curves
136Best-fit Logistic Curves Rate Method
Can be rewritten as
The left-hand side, (dS/dt)/S, is the growth rate
of cumulative consumption. This is a linear
function of cumulative consumption, with an
intercept of r and a slope of r/S8. Growth is
zero when S S8 r/(r/S8)
137Best Fit to Rate Curve 1929-2001
1970
95 CI (8,400, 11,000)
1983
95 CI (10,400, 13,000)
138Best-fit to Rate Curves
139Concentrations non-constant flows
- c concentration of contaminant (mg/L, ?g/m3)
140Contamination and Clean-up
141Simple Model v. Reality
- Caution reality is often more complicated!
- Stocks often are not well-mixed
- Stocks and flows may contain both dissolved and
suspended contaminants - Contaminants may precipitate at high
concentrations and go back into solution at low
concentrations - Realistic models often subdivide physical
reservoirs into several physical, chemical, or
biological sub-compartments
142Box Model of Human Body
143Inhalation of 1-?m UO2 Aerosol
Fraction
Lung
Blood
Bone
Kidney
Time (hours)
144Numerical Solutions
- If flows vary with time or if there are many
different stocks, analytical solutions for S(t)
for each box may be difficult or impossible - Equations are solved numerically using
- custom program
- special systems modeling software (Stella)
- general-purpose equation-solving software
(Mathematica, Maple, MathCad) - spreadsheet (Excel Crystal Ball)
145Mono Lake
- In 1941 Los Angeles began to divert water from
the streams feeding Mono Lake - Lake level drops, producing non-linear decrease
in lake area, evaporation rate - Lake volume decreases, salinity increases,
evaporation rate decreases - Runoff (precipitation) and diversions vary from
year to year - Numerical solution required! Mono Lake.xls
146Mono Lake BOTE Calculation
- Always good to check detailed models with a quick
back-of-the-envelope calculation - What would happen if diversions continued at
1962-85 average rate (?90 kac-ft/y)? - In equilibrium, evaporation flow would decrease
from 202 to 112 kac-ft/y - Evaporation flow is proportional to lake area, so
area reduced by factor of (112/202) 0.55, from
55.2 to 30.6 kac - Compare to spreadsheet answer 30.6 kac
147Cost-Benefit Analysis
- Many environmental policy issues involve weighing
costs and benefits of environmental protection
measures or practices/projects that affect
environmental quality - Do the benefits of the policy or project outweigh
the costs? - What is the optimal solution? What level of
pollution control or what size project is best?
148Measuring Costs
- Costs of environmental protection generally are
relatively easy to measure - forgone industrial production or use of economic
resources - installing and operating pollution control
devices, transition to more efficient and
expensive technologies - paying pollution taxes or purchasing permits
- verifying compliance
- lost markets
149Measuring Benefits
- Benefits are often are avoided costs more
difficult to measure difficult to monetize - Deaths or illnesses avoided days of work
quality-adjusted life-years saved (QALY) - Dollar value of resources, ecosystem goods and
services preserved or recovered - Economic damages avoided (e.g., crops, timber,
settlements, etc.) - Recreational, aesthetic, and existence values of
natural systems
150Non-Market Valuation
- Value of wages lost due to death, illness cost
of medical treatment for illness - Travel costs, access fees for recreational value
- Willingness to pay (WTP) to preserve
environmental goods and services contingent
valuation (CV) - Willingness to accept compensation (WTA) for
illness, loss/damage to goods, services - Differences, changes in property values
- Cost of compliance with existing laws (pollution
control, taxes, permits) - Cost of providing lost environmental goods and
services with market goods and services
151Discounting
- Usual procedure is to discount costs and benefits
at the same rate and compare the present values - Benefits in the distant future have little
weight - 1 billion today 20 billion in 2100 if r
0.03/y - 150 billion in 2100 if r 0.05/y
- 22,000 billion in 2100 if r 0.10/y
- 3,300,000 billion in 2100 if r 0.15/y
152Incandescent v. Compact Fluorescent
- A 1200-lumen incandescent bulb uses 100 W,
costs 1, and lasts 1000 h - A 1200-lumen compact fluorescent uses 20 W,
costs 10, and lasts 10,000 h - Net benefit of CF bulb depends on discount rate,
annual usage, cost of electricity, and - cost of changing bulbs, space heating and
cooling, aesthetics, externality costs of
electricity generation and bulb manufacture and
disposal
153Other Examples
- Paper v. plastic grocery bags?
- Paper v. polystyrene coffee cups?
- Cloth v. disposable diapers?
- Glass v. plastic beverage containers?
- Heat pump v. gas furnace?
154Economic Efficiency
- Costs are minimized (benefits maximized) when
- marginal cost marginal benefit
- costs of reducing the next unit of pollution
benefits of the reduction
155Theory Can Be Hard to Put into Practice
156Cost-effectiveness Analysis
- Because benefits are difficult to measure and
compare with costs, some are skeptical that CBA
can be used to define policy goals - The goal (e.g., the allowed level of pollution)
is set externally through the policy problem - The cost part of CBA analysis can be used to
define the most cost-effective strategy to
achieve the goal - Like CBA, subject to problems facing discounting
and uncertainties about technology, resources,
etc.
157Risk Analysis
- Costs and benefits often are not deterministic
multiple outcomes are possible - For a risk-neutral decisionmaker
- Ci is the cost of the ith possible outcome
- pi may be well-known (smoking), poorly known
(reactor accidents), or completely unknown - If risk-averse, event with Cipi (106)(106) 1
is riskier than event with Cipi (1)(1) 1
158Other Considerations
- Do same people pay as receive benefits?
- Are costs and benefits dispersed or concentrated
(in space or in time)? - How reversible is the damage? On what time scale?
- Is response linear or nonlinear, with or without
a threshold? - What is the quality of the evidence? How much
uncertainty? How likely is it that uncertainties
will be resolved or reduced?