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Water - Cement Ratio

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0.500 X 600 = 300 pounds of water 300 pounds / 8.33 = 36.0 gallons Water/Cementitious Problem Cement ... Abrasion Resistance of an Aggregate Durability Hydration Ph ... – PowerPoint PPT presentation

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Title: Water - Cement Ratio


1
Water - Cement Ratio
2
Water/Cement Ratio
  • The number of pounds of water per pound of
    cement.
  • A low ratio means higher strengths, a high ratio
    means lower strengths.
  • For NCDOT, the ratio depends on the class of
    concrete, whether an air agent is used or not,
    and the shape of the stone - rounded or angular.

3
W/C Ratio Cont.
  • Example
  • W/C 0.500, and Water 250 pounds
  • How much cement is needed?
  • 250 / 0.500 500 pounds of
    cement

4
W/C Ratio Cont.
  • Example
  • W/C 0.500, and Cement 600 pounds
  • How much water is needed?
  • 0.500 X 600 300 pounds of water
  • 300 pounds / 8.33 36.0 gallons

5
Water/Cementitious Problem
  • Cement Used in Mix 436 pounds
  • Fly Ash in Mix 131 pounds
  • Maximum Water 36.0 gallons
  • Total Water 33.5 gallons
  • Metered Water 27.5 gallons
  • Free Water in aggregates 50 pounds
  • Determine the design w/c ratio and the batched
    w/c ratio

6
SOLUTION Design W/C
  • Add Cement And Fly Ash
  • 436 131 567 pounds
  • Convert Design Water Into Pounds
  • 33.5 X 8.33 279 pounds
  • Plug Into Formula W/C Ratio
  • 279 / 567 0.492
  • (carry answer to three places after decimal)

7
Batched W/C Ratio
  • Add Cement And Fly Ash
  • 436 131 567 pounds
  • Convert Metered Water Into Pounds
  • 27.5 X 8.33 229 pounds
  • Add free water 229 50 279 Lbs
  • 279 / 567 0.492

8
W/C Ratio with Ice
  • Determine the W/C ratio if 68 pounds of ice is
    used to lower the temperature of the concrete.
  • The W/C ratio remains the same because the
    quantity of total water does not change.

9
QUESTIONS
10
Solids And Voids
  • In determining mix designs, you must use an
    aggregate dry rodded unit weight.
  • This weight is determined at the lab.
  • In the procedure for determining this weight,
    only the coarse aggregate is used.
  • Therefore, there is a of solids and a of
    voids in the container.

11
Formula Solids Voids
  • Solids
  • Dry Rodded Unit Weight
  • (Spec. Gravity) X (62.4)
  • The Answer Is Then Multiplied Times 100
  • To get Voids
  • Subtract Solids from 100

12
Example
  • Dry Rodded Unit Weight 96.6 pcf
  • Specific Gravity Of Agg. 2.80
  • Solids 96.6 0.553
    (2.80 X 62.4)
  • 0.533 X 100 55
  • Voids 100 - 55 45

13
Terms I Should Know.
  • Abrasion Resistance of an Aggregate
  • Durability
  • Hydration
  • Ph
  • Saturated Surface Dry
  • Set Retarder
  • Unit Weight
  • Water / Cement Ratio
  • THAT IS ENOUGH FOR A MONDAY!!

14
Pass Out Day 1 Mix Design Problems
15
PROBLEM SOLUTION
  • 1.Water 209 15 224 gals
  • 224 X 8.33 1866 pounds
  • Add all material
  • 40607733 13,586 1866 27,245
  • Divide by unit weight
  • 27,245 7.1 cu. yd.
  • (142.10 X 27)

16
PROBLEM SOLUTION
  • 2. Water / Cement Ratio
  • 1866 / 4060 0.460
  • 3. (A) Solid
  • 88.6 0.508 X 100 51
  • (2.79 X 62.4)
  • (B) Void 100 51 49

17
PROBLEM SOLUTION
  • 4. Wet Sand
  • 5.9 - 0.5 5.4 5.4 / 100 0.054
  • 0.054 X 1102 59.5 pounds
  • 1102 60 1162 pounds (batch weight)
  • Dry Sand
  • 0.5 / 100 0.005
  • 0.005 X 1102 5.5 pounds
  • 1102 - 6.0 1096 pounds

18
PROBLEM SOLUTION
  • 5. SSD sand weight ?
  • 1720 / 1.062 1620 pounds SSD sand

19
PROBLEM SOLUTION
  • Gallons of Water from Wet Sand
  • 1720 1620 100 pounds / 8.33 12.0 gallons

20
HOMEWORK PROBLEM
21
QUESTIONS
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