Local Extrema & Mean Value Theorem - PowerPoint PPT Presentation

1 / 18
About This Presentation
Title:

Local Extrema & Mean Value Theorem

Description:

Local Extrema & Mean Value Theorem Local Extrema Rolle s theorem: What goes up must come down Mean value theorem: Average velocity must be attained – PowerPoint PPT presentation

Number of Views:61
Avg rating:3.0/5.0
Slides: 19
Provided by: mathemati2
Category:
Tags: c | extrema | local | mean | theorem | value

less

Transcript and Presenter's Notes

Title: Local Extrema & Mean Value Theorem


1
Local Extrema Mean Value Theorem
  • Local Extrema
  • Rolles theorem What goes up must come down
  • Mean value theorem Average velocity must be
    attained
  • Some applications Inequalities, Roots of
    Polynomials

2
Local Extrema
3
Example
  • Let f(x) (x-1)2(x2), -2 ? x ? 3
  • Use the graph of f(x) to find all local extrema
  • Find the global extrema

4
Example
  • Consider f(x) x2-4 for 2.5 ? x lt 3
  • Find all local and global extrema

5
Fermats Theorem
  • Theorem If f has a local extremum at an
    interior point c and f? (c) exists, then f? (c)
    0.
  • Proof Case 1 Local maximum at interior point c
  • Then derivative must go from ?0 to ?0 around c
  • Proof Case 2 Local minimum at interior point c
  • Then derivative must go from ?0 to ?0 around c

6
Cautionary notes
  • f? (c) 0 need not imply local extrema
  • Function need not be differentiable at a local
    extremum (e.g., earlier example x2-4)
  • Local extrema may occur at endpoints

7
Summary Guidelines for finding local extrema
  • Dont assume f? (c) 0 gives you a local extrema
    (such points are just candidates)
  • Check points where derivative not defined
  • Check endpoints of the domain
  • These are the three candidates for local extrema
  • Critical points points where f? (c)0 or where
    derivative not defined

8
What goes up must come down
  • Rolles Theorem Suppose that f is
    differentiable on (a,b) and continuous on a,b.
    If f(a) f(b) 0 then there must be a point c
    in (a,b) where f ?(c) 0.

9
Proof of Rolles theorem
  • If f 0 everywhere its easy
  • Assume that f gt 0 somewhere (case flt 0 somewhere
    similar)
  • Know that f must attain a maximum value at some
    point which must be a critical point as it cant
    be an endpoint (because of assumption that f gt 0
    somewhere).
  • The derivative vanishes at this critical point
    where maximum is attained.

10
Need all hypotheses
  • Suppose f(x) exp(-x).
  • f(-2) f(2)
  • Show that there is no number c in (-2,2) so that
    f ?(c)0
  • Why doesnt this contradict Rolles theorem

11
Examples
  • f(x) sin x on 0, 2?
  • exp(-x2) on -1,1
  • Any even continuous function on -a,a that is
    differentiable on (-a,a)

12
Average Velocity Must be Attained
  • Mean Value Theorem Let f be differentiable on
    (a,b) and continuous on a,b. Then there must
    be a point c in (a,b) where

13
Idea in Mean Value Proof
  • Says must be a point where slope of tangent line
    equals slope of secant lines joining endpoints of
    graph.
  • A point on graph furthest from secant line works

14
Consequences
  • f is increasing on a,b if f ?(x) gt 0 for all x
    in (a,b)
  • f is decreasing if f ?(x) lt 0 for all x in (a,b)
  • f is constant if f ?(x)0 for all x in (a,b)
  • If f ?(x) g ?(x) in (a,b) then f and g differ
    by a constant k in a,b

15
Example
16
More Consequences of MVT
17
Examples
  • Show that f(x) x32 satisfies the hypotheses of
    the Mean Value Theorem in 0,2 and find all
    values c in this interval whose existence is
    guaranteed by the theorem.
  • Suppose that f(x) x2 x 2, x in -1,2. Use
    the mean value theorem to show that there exists
    a point c in -1,2 with a horizontal tangent.
    Find c.

18
Existence/non-existence of roots
  • x3 4x - 1 0 must have fewer than two
    solutions
  • The equation 6x5 - 4x 1 0 has at least one
    solution in the interval (0,1)
Write a Comment
User Comments (0)
About PowerShow.com