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9'7 Vectors

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I'm only giving you exactly what is on the test. ... Next use the distance formula to find the magnitude. |PQ| = (-6 0)2 (3 0)2 = 62 32 ... – PowerPoint PPT presentation

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Title: 9'7 Vectors


1
9.7 Vectors
  • Geometry
  • Mrs. Spitz
  • Spring 2005

2
Objectives
  • This lesson is worth 1/3 of your test grade on
    Thursday.
  • Find the magnitude and the direction of the
    vector
  • Add vectors
  • Assignment pp. 576-577 13-20, 35-40 all. Due
    Thursday
  • Also complete Ch. 9 Review pp. 582-584 1-24
    all Due Thursday.
  • Reminder Ch. 9 Test Thursday. IF you are
    leaving early, please take the exam tomorrow
    during seminar.

3
Pay attention
  • Im only giving you exactly what is on the test.
    There are 4 questions that have to do with
    graphing the vector, putting it into component
    form, and then finding the magnitude. The next
    three examples are good practice and/or notes to
    have on the test Thursday.

4
Finding the magnitude of a vector
  • You begin with an initial point to a terminal
    point given in terms of points, usually P and Q.
    You graph it as you would a ray. Initial point
    is P(0, 0). Terminal point is Q(-6, 3).

Q(-6, 3)
P(0, 0)
5
Write the component form
  • Here you write the following
  • Component Form x2 x1, y2 y1
  • lt-6 0, 3 0gt
  • lt-6, 3gt is the component form.
  • Next use the distance formula to find the
    magnitude.
  • PQ v(-6 0)2 (3 0)2
  • v62 32
  • v36 9
  • v45
  • 6.7

Q(-6, 3)
P(0, 0)
6
Graph Initial/Terminal points
  • Initial point is P(0, 2). Terminal point is Q(5,
    4).
  • Reminder that Q is the second point. P is the
    initial point. Graph the ray starting at P and
    going through Q as to the right. Then you can
    start looking for component form and magnitude.

7
Write the component form
  • Here you write the following
  • Component Form x2 x1, y2 y1
  • lt5 0, 4 2gt
  • lt5, 2gt is the component form.
  • Next use the distance formula to find the
    magnitude.
  • PQ v(5 0)2 (4 2)2
  • v52 22
  • v25 4
  • v29
  • 5.4

8
Graph Initial/Terminal points
  • Initial point is P(3, 4). Terminal point is
    Q(-2, -1).
  • Reminder that Q is the second point. P is the
    initial point. Graph the ray starting at P and
    going through Q as to the right. Then you can
    start looking for component form and magnitude.

9
Write the component form
  • Here you write the following
  • Component Form x2 x1, y2 y1
  • lt-2 3, -1 4gt
  • lt-5, -5gt is the component form.
  • Next use the distance formula to find the
    magnitude.
  • PQ v-2 3)2 (-1 4)2
  • v(-5)2 (-5)2
  • v25 25
  • v50
  • 7.1

10
Adding Vectors
  • Two vectors can be added to form a new vector.
    To add u and v geometrically, place the initial
    point of v on the terminal point of u, (or place
    the initial point of u on the terminal point of
    v). The sum is the vector that joins the initial
    point of the first vector and the terminal point
    of the second vector. It is called the
    parallelogram rule because the sum vector is the
    diagonal of a parallelogram. You can also add
    vectors algebraically.

11
What does this mean?
  • Adding vectors
  • Sum of two vectors
  • The sum of u lta1,b1gt and v lta2, b2gt is
  • u v lta1 a2, b1 b2gt
  • In other words add your xs to get the
    coordinate of the first, and add your ys to get
    the coordinate of the second.

12
Example
  • Let u lt3, 5gt and v lt-6, 1gt
  • To find the sum vector u v, add the xs and add
    the ys of u and v.
  • u v lt3 (-6), 5 (-1)gt
  • lt-3, 4gt
  • There are 6 of these on the test Thursday!!!

13
Reminders
  • Test Thursday before you leave
  • Binder Check Thursday
  • HW 9.7 is due Thursday
  • HW Chapter 9 Review is due Thursday.
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