Quadratic Problems - PowerPoint PPT Presentation

1 / 15
About This Presentation
Title:

Quadratic Problems

Description:

This type of problem appears on a Babylonian tablet ~1700BC. Write this down. ... (MACTUTOR Biography) Try this in your group. Did you get 9 and 1 for y and z ? ... – PowerPoint PPT presentation

Number of Views:52
Avg rating:3.0/5.0
Slides: 16
Provided by: jiml2
Category:

less

Transcript and Presenter's Notes

Title: Quadratic Problems


1
Quadratic Problems
  • Babylonians
  • And
  • Diophantus

2
This type of problem appears on a Babylonian
tablet 1700BC
Write this down.
3
Like we were doing in false position, lets make
a guess
  • 5 x 5 25 sq. units, but we wanted
  • xy 16
  • How far off are we?
  • 25 - 16 9 units of area.
  • Error 9 sq. units

4
(No Transcript)
5
Our solutions for the sides of the rectangle are
the lengths 8 and 2.
Lets try another
6
Try this one on our own
In English, I am looking for two numbers whose
product is 45 and whose sum is 18.
7
What did you get?
The two numbers whose product is 45 and whose
sum is 18 are 3 and 15.
8
Diophantus (200 - 284)
  • There are, however, many other types of
    problems considered by Diophantus. (MACTUTOR
    Biography)

Try this in your group.
9
Did you get 9 and 1 for y and z ?

Diophantus idea is to plan ahead a bit.
He introduces x to be the difference that we
would soon be adding and subtracting from 5 if
we were to do it the Babylonians way. So he
replaces y by (5 x) and z by (5 - x) yz 9
becomes (5 x)(5 - x) 9
10
yz 9 becomes (5 x)(5 - x) 9
25 - x2 9
x2 16
So, X 4
So we get y 9 and z 1 just as Diophantus
tells us to do.
11
Whats been the point of the two talks on False
Position?
  • To see and understand how early mathematicians
    solved equations
  • To experience a style of doing algebra that is
    different from the way we have been taught and
  • To wonder at how much early scribes and others
    really understood.

12
Thanks for your attention and work !
13
How does this system relate to our quadratic
formula?
  • Lets consider

Then our first guess is 1/2 b.
Our error will be (1/2 b)2 - c. Take the
square root of that
14
So that square root is the amount that we must
add and subtract from 1/2b. This is what we get
for solutions
and
leads to
-gt
Our equation
15
OK, now were done!
Write a Comment
User Comments (0)
About PowerShow.com