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Steady State Diffusion Ficks 2nd Law

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Title: Steady State Diffusion Ficks 2nd Law


1
Steady State DiffusionFicks 2nd Law
27-216 Spring 2004 A. D. Rollett
Slides from Diffusion Modules by Glicksman,
except where marked
2
Fluxes
  • Atoms/ions/molecules jump a lot (rn) but only a
    short NET distance rvn.
  • All this jumping to a flux of material,
  • when a concentration gradient exists

Examinable
S.Seetharaman 03
3
Objectives
  • Steady State what does this mean?
  • Now that we know what diffusion is and the
    physics behind it, how do we use it in
    engineering problems?
  • Our 1st diffusion problem Case study

4
What does steady state mean?
  • The meaning of steady state is very simple
  • The concentration profile does not change
  • The amount of solute in any given volume does not
    change
  • We do not have to worry about changes in
    concentration with time, so t can be omitted
    from the equation
  • Example (from fluid flow!) fish ladders

A. Rollett 04
http//www.nwd.usace.army.mil/ps/colrvbsn.htm
Examinable
5
What do we need to know?
Examinable
S.Seetharaman 03
6
Our 1st diffusion problem A special case study
Steady State
7
Design of Hydrogen Reactor Vessel
  • A plant for hydrogenation of a hydrocarbon
    (current example of research in this area
    formation of methanol by hydrogenation of
    supercritical CO2) is being designed. The
    reaction vessel is to be made of low-alloy steel
    and the wall thickness depends primarily on how
    large a loss rate of hydrogen can be tolerated
    through the wall.
  • The boundary conditions are as follows
  • Reactor temperature 450C
  • Hydrogen pressure in reactor 75 atmospheres
  • Hydrogen pressure outside reactor 1 atmosphere
  • Length of vessel 1 m
  • Inner diameter, 2r1, of vessel 0.1 m.

PG section 13.1
1 m
NB for this problem, J total flow, jflux
Examinable
8
Steady-State Diffusion in Cylinders Constant D
Ficks law reduces to an ODE (Laplaces
Equation) in a single spatial variable, r .
The boundary conditions are
Examinable
9
Steady-State Diffusion in Cylinders Constant D
Steadystate diffusion solution for cylinders,
rinner 1.
Examinable
10
Design of Hydrogen Reactor Vessel, contd.
  • Since we are discussing a cylindrical vessel we
    need a particular solution (to be discussed in a
    later lecture) for steady-state diffusion,
    despite the fact that we are dealing with 1D
    diffusionThe inner and outer radii are
    rinside and routside, respectively, and Cinside
    and Coutside are the concentrations at the inner
    and outer radii.
  • Now this is a solution to the differential
    equation,
  • At steady state, we also know from Ficks 1st Law
    that
  • Also, the mass flow rate, J, at a given radius
    must be equal to the flux multiplied by the area,
    which is the perimeter, 2pr, multiplied by the
    length, l J jarea 2prlj

Examinable
A. Rollett 04
11
Design of Hydrogen Reactor Vessel, contd.
  • Combining the mass flow rate with Ficks 1st Law
    gives this
  • Now lets insert the particular solution for the
    cylinder into this relationship
  • Now we need some additional information because
    we are dealing with gases we have to delve into
    permeability.

Examinable
A. Rollett 04
12
Permeability
  • First, we need to be able to relate gas pressures
    to concentrations based on chemical equilibrium.
    In this case we use Sieverts Law to relate
    solubility (equivalent to concentration), S, to
    (hydrogen) gas pressure, p, where K is the
    (reaction) equilibrium constant S Kvp.
    The corresponding chemical reaction is 1/2
    H2(g) H (in solution).
  • Permeability, P, is defined as the product of
    diffusivity and reaction constant for the above
    reaction P P0 exp-Q/RT
  • Implicit in this definition is some information
    about diffusion, so lets expand this definition.

A. Rollett 04
Examinable
13
Permeability, contd.
  • Permeation of a membrane by a chemical species
    depends on the concentration gradient and the
    diffusivity. Given concentrations defined by gas
    pressures in equilibrium with each surface (e.g.
    gas permeation of a metal foil), we can write
    Ficks 1st Law in this form

From Poirier Geiger note the non-SI units
Examinable
A. Rollett 04
14
Design of Hydrogen Reactor Vessel, contd.
  • Now, finally, we can insert values for
    concentrations related to the gas pressures
    defined in the design problem
  • From Table 13.1 in PG we can estimate the
    permeability that we need for hydrogen in steel
    as P 8.4 10-6 cm3(STP) s-1 atm-1/2.
  • Inserting this we obtain

Examinable
A. Rollett 04
15
Design of Hydrogen Reactor Vessel, contd.
  • For the design, we choose a rate at which we can
    afford to lose hydrogen from the reactor vessel.
    This then determines the outer radius of the
    vessel.

PG section 13.1
Examinable
A. Rollett 04
16
Divergence Operators
A useful shorthand notation in math is divergence
or div, which stands for the sum of the 1st
spatial derivatives of a vector function (e.g.
flux).
Cartesian Coordinates
Cylindrical Coordinates
Spherical Coordinates
contrast with grad, the 1st spatial
derivative of a field,but also written as ?.
17
Ficks First Law vector form
One application of div is in writing Ficks 1st
Law.
Vector form of Ficks first law
Examinable
18
Ficks 2nd Law
  • Restricting conditions such that there is no
    change in concentration with time is too
    restrictive for real life! Many real problems
    are transient.
  • What happens if concentrations can change with
    time? Answer we have to be concerned with
    accumulations and losses of material in a given
    volume of material.
  • Ficks 2nd Law time rate of change of
    concentration diffusion coefficient second
    spatial derivative of concentration gradient

Examinable
19
Ficks Second Law(Linear Diffusion Equation)
or
Examinable
20
Ficks Second Law (Cartesian Coordinates)
Laplacian
The Laplacian is a differential operator, i.e.
something that you do to operate on a quantity
or variable to obtain the second spatial
derivative
21
What does transient mean?
  • The meaning of transient is very simple
  • The concentration profile does change
  • The amount of solute in any given volume changes
    with time
  • We do have to worry about changes in
    concentration with time, so t must be in the
    equation(s)
  • Example (from fluid flow!) think about filling
    a fish ladder for the first time
  • Where does Ficks 2nd Law come from? Answer we
    have to think about net accumulation ratesin
    control volumes

Examinable
http//www.nwd.usace.army.mil/ps/colrvbsn.htm
A. Rollett 04
22
Gradient Vector Field
dC/dy
dC/dx
23
Mass-flow Control Volume
This is where we derive Ficks 2nd Law
Control volume indicating mass flows in the
y-direction occurring about an arbitrary point P
in the Cartesian coordinate system, x,y,z.
Examinable
24
Mass Conservation
Examinable
25
Mass Conservation
or
Examinable
26
Exercises
1. Given the concentration field Csin(?x)
g/cm3, plot the gradient field, and then
determine the flux field using Ficks 1st law,
assuming that the diffusion coefficient, D1
cm2/s. The use of a mathematical software
package or spreadsheet provides an invaluable aid
in solving diffusion problems such as suggested
by these exercises, and many others introduced in
later chapters of this book. In one dimension,
the gradient is defined as
27
Exercises
The flux field may be found using Ficks 1st law.
Gradient Plot
Flux Plot
Note These plots differ by a minus sign!
28
Exercises
2. A twodimensional concentration field is given
by C(x,y)-sin(?x)cos(?y). Calculate the
gradient field, and make plots of it and the
given concentration field.
Concentration field
Gradient field
29
Summary
  • Now that we know what diffusion is and the
    physics behind it, how do we use it in
    engineering problems? Find boundary conditions,
    find diffusion constant data and solve PDE
  • Steady state no change with time
  • Our 1st diffusion problem Case study of gas
    permeation through a wall
  • What about problems in which the concentration
    changes with time? We have to concern ourselves
    with net accumulation rates in a given volume.
    By taking limits (standard calculus) we arrive at
    Ficks 2nd Law.

Examinable
A. Rollett 04
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