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Expert Judgment Techniques and Distribution Sensitivity Analyses in RMPS Methodology

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Title: Expert Judgment Techniques and Distribution Sensitivity Analyses in RMPS Methodology


1
Expert Judgment Techniques and Distribution
Sensitivity Analyses in RMPS Methodology
Ricardo Bolado Lavín Nuclear Safety Unit,
Institute for Energy, European Commission
DG-JRC http// www.energyrisks.jrc.nl http//www
.jrc.nl
2
RMPS methodology
3
Identification of relevant parameters
  • Use of the Analytical Hierarchy Process (AHP). It
    allows to create a hierarchy of parameters in the
    case studied (rank parameters according to their
    importance)
  • Building a hierarchy to decompose the problem
  • Definition of the top goal (top level in the
    hierarchy)
  • Create lower levels searching for factors that
    affect the upper level and are affected by others
    in the lower level
  • Locate basic parameters in the lowest part of the
    hierarchy
  • Use of pair wise comparisons
  • For each element in each level build a pair wise
    comparison matrix to assess importance of
    elements in the level just below it.
  • Normalized eigenvalues of the pair wise matrix
    comparison provide the ranking
  • Index available to detect inconsistent
    assessments.

4
Identification of relevant parameters (2)
5
Quantification of uncertainties
  • The method to be applied depends on the quantity
    of data available
  • Many data available
  • Classical estimation methods Chi-square,
    Kolmogorov
  • Not many data available
  • Bayesian estimation methods
  • Scarce or almost no data
  • Expert judgment methods

6
Distribution sensitivity analysis
  • What happens with our output variable (e.g.
    probability of success) if the distributions of
    our inputs are changed?
  • There are several reasons for the experts to
    provide more than one input vector distribution
  • Experts may show reluctance to provide accurate
    answers/distributions (under confident experts).
  • Experts may acknowledge that the actual
    distribution could be slightly different from the
    one provided by them.
  • In some cases the experts consider that the
    distribution should be divided into different
    distributions (conditional distributions).
  • Sometimes experts just disagree and provide
    different distributions
  • A check of the influence of those different
    distributions may be worthy.

7
The trivial solution
  • Let us assume that we want to estimate the
    influence of changing the distribution of one
    input parameter
  • Take a sample of size n under the original
    distribution
  • Propagate the uncertainty through the model
  • Estimate the reliability under the original
    distribution
  • Take a sample of size n under the alternative
    distribution
  • Propagate the uncertainty through the model
  • Estimate the reliability under the alternative
    distribution
  • Compare both reliabilities.

8
The trivial solution (2)
  • Let us assume that we want to estimate the
    influence of changing the distribution of k input
    parameters
  • Repeat the process described in the first three
    points of last slide.
  • Repeat the process described in steps 4 to 7 in
    last slide k times.
  • Total number of computer code runs n kn
  • Let us assume that we want to estimate the
    influence of changing simultaneously the
    distribution of 2 or more input parameters
  • The problem becomes a combinatorial problem
    (forget the trivial method).

9
Available acceptable solutions
  • Two methods proposed by Beckman and McKay (1987)
  • The re-weighting method (based on the idea of
    importance sampling)
  • Provides unbiased estimators for the mean of the
    output variable
  • The rejection method (based on the idea of
    acceptance-rejection sampling)
  • Estimates in an unbiased way the distribution
    function of the output variable (adequate for our
    objectives)

10
The problem
  • Let us consider a k components vector of input
    parameters X.
  • Let us assume that two different distribution
    functions f1(x) and f2(x) may be assigned to that
    input parameter vector.
  • Let us also assume that the first one is the
    reference one and the second one is the one we
    are addressing for sensitivity.
  • For simplicity, let us consider only one output
    variable Y.
  • Let us call F1(y) and F2(y) to the distribution
    functions of Y when X follows the distributions
    f1(x) and f2(x) respectively.
  • The challenge
  • To use only one sample to estimate simultaneously
    properties of F1(y) and F2(y) in order to compare
    them.

11
The rejection method
  • There are two conditions for the application of
    this method
  • First, as in the previous method, the support of
    f2(x), R2, must be contained in the support of
    f1(x), R1 and
  • Second, the quotient f2(x)/f1(x) must be bounded.
    Let us assume that the bound is M.

12
The rejection method (2) - Implementation
  • Step 1? To get a sample of size n of the input
    random vector under the reference distribution
    X1, X2, , Xn. Their actual values will be x1,
    x2, , xn.
  • Step 2 ? To run the code for those n sets of
    inputs in order to get the corresponding sample
    of the output variable Y1, Y2,, Yn. Their
    actual values will be y1, y2,, yn.
  • Step 3? For each sample xi, take a sample of the
    uniform distribution Vi between 0 and Mf1(xi).
  • Step 4? To retain in the sample the corresponding
    output value Yiyi if the realisation vi of Vi is
    less or equal to f2(xi), otherwise reject that
    value from the sample.
  • Step 5? To consider the values of Y remaining in
    the sample as a random sample of Y under f2(x).
    That sample of size kn will be used to build up
    an empirical distribution function that estimates
    the actual distribution function of Y under
    f2(x). Each step in that empirical distribution
    function will have a height 1/k.

13
The rejection method (3) - Example
14
The rejection method (4) - Example
15
Problem Inefficiency
  • The efficiency of this method is 1/M (probability
    of a random realization of X obtained under f1(x)
    being retained as a random realization under
    f2(x)).
  • Intuitive justification the quotient between the
    hypervolume under Mf1(x) and the hypervolume
    under f2(x) is M, so that, in the average,
    according to the acceptance criterion, only a
    fraction 1/M of the observations obtained under
    f1(x) will remain as a sample under f2(x)

16
Proposed solution
17
Proposed solution (Extended rejection method)
  • Applying the rejection method an infinite number
    of times and averaging converges to a solution
    (red stepwise line in previous slide) that uses
    all the information in an optimum way
  • The distribution obtained is a discrete random
    variable with probability
  • for each sample value Y(xi)
  • The estimator for the mean
  • under the new distribution is

18
Application of the method
  • RP2_B case
  • Success criterion Pressure comes below 40 bar
    before the end of the scenario
  • Possible variations in input distributions
  • Mean varies up to 25 of the standard deviation
  • Standard deviation varies up to 10

19
Application of the method
20
Application of the method
21
Conclusions
  • There are methods available for phenomena and
    parameter identification and screening
  • There are methods available for uncertainty
    quantification
  • There are methods available for assessing
    (performance) reliability
  • There are methods for computing distribution
    sensitivity
  • Are there systems available to apply these
    methods on them?
  • Fortunately it seems so!!!
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