Title: Einstein (1905): Energy of e.m.r. is quantised
1Einstein (1905) Energy of e.m.r. is quantised
Ephoton hn hc/l (1) E.m.r. stream of
particles called photons Also Energy has
mass! i.e. E mc2 or m E/c2 (2) Combining
(1) and (2) Mass of e.m.r. photon m
h/lc Overall conclusion Light (e.m.r.) has both
wave and particulate properties Question Does
matter have wave-like properties?
2Does matter have wave-like properties?
3Does matter have wave-like properties? Wave
Properties of Matter De Broglie (1925) Yes,
particularly for small masses
4Does matter have wave-like properties? Wave
Properties of Matter De Broglie (1925) Yes,
particularly for small masses Similar equation
applies as for light m h/l.v or l
h/mv (v velocity of particle)
5Does matter have wave-like properties? Wave
Properties of Matter De Broglie (1925) Yes,
particularly for small masses Similar equation
applies as for light m h/l.v or l
h/mv (v velocity of particle) For
an electron (m 9.1 x 10-28g, v 1.2 x
105m/s) l 6.1 x 10-9m
6Does matter have wave-like properties? Wave
Properties of Matter De Broglie (1925) Yes,
particularly for small masses Similar equation
applies as for light m h/l.v or l
h/mv (v velocity of particle) For
an electron (m 9.1 x 10-28g, v 1.2 x
105m/s) l 6.1 x 10-9m For a cyclist (m 1 x
105g, v 3m/s) l 3.5 x 10-40m
7- Energy of photon
- E hn hc/l
8- Energy of photon
- E hn hc/l
- l 500 nm
9- Energy of photon
- E hn hc/l
- l 500 nm
- E 6.626 x 10-34 x 3.00 x 109/ 500 x 10-9
- 3.97 x 10-18 J s m s-1 m-1
- 3.97 x 10-18 J
10- Energy of photon
- E hn hc/l
- l 500 nm
- E 6.626 x 10-34 x 3.00 x 109/ 500 x 10-9
- 3.97 x 10-18 J s m s-1 m-1
- 3.97 x 10-18 J
- 100 W bulb emits 100 J s-1
- ? 100/ 3.97 x 10-18 2.5 x 1019 photons s-1.
11- Summary so far
- On the atomic scale energy is transferred in
- discrete quantities (quanta)
- Light (e.m.r.) exhibits both wave and
particulate - behaviour
12- Summary so far
- On the atomic scale energy is transferred in
- discrete quantities (quanta)
- Light (e.m.r.) exhibits both wave and
particulate - behaviour
- Matter, if small enough in mass, exhibits wave
- behaviour which is measurable
13Line spectrum of sodium
400 550 700 nm
14Line spectrum of sodium
400 550 700 nm
Line spectrum of hydrogen
400 550 700 nm
15Line spectrum of sodium
400 550 700 nm
Line spectrum of hydrogen
400 550 700 nm
Balmer-Rydberg equation 1/l R1/m2 -
1/n2 m 1, n gt 1
16- Bohr Theory of the Atom (1913)
- Developed a quantum model for the H atom
17- Bohr Theory of the Atom (1913)
- Developed a quantum model for the H atom
- Electron moves around nucleus only in certain
- allowed circular orbits
18- Bohr Theory of the Atom (1913)
- Developed a quantum model for the H atom
- Electron moves around nucleus only in certain
- allowed circular orbits
Allowed electron energy levels n 1 n 2 n
3, etc.
Nucleus
Electron in ground state atom
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20Energy put in
Energy given out
21Energy given out
22Energy given out
As a photon of given ?
23Energy given out
As a photon of given ?
Other allowed e- transitions
Hydrogen emission spectrum
24Energy put in
As a photon of given ?
Other allowed e- transitions
Hydrogen absorption spectrum
25- Bohr theory
- Was based on a particulate view of the
electron - Worked reasonably well for the hydrogen atom
- But failed for all other elements
26- Bohr theory
- Was based on a particulate view of the
electron - Worked reasonably well for the hydrogen atom
- But failed for all other elements
- Wave (Quantum) Mechanical Model of the Atom
- Schroedinger (1925)
- Applied de Broglies idea of a wave-like
electron - to electrons in atoms
27- Bohr theory
- Was based on a particulate view of the
electron - Worked reasonably well for the hydrogen atom
- But failed for all other elements
- Wave (Quantum) Mechanical Model of the Atom
- Schroedinger (1925)
- Applied de Broglies idea of a wave-like
electron - to electrons in atoms
- Visualised electrons as standing waves,
existing - around the nucleus
28Electron as a standing wave n 4
wavelengths Nucleus
Standing wave must have a whole number of
wavelengths to prevent destructive interference
29- Quantization of e- energy levels by standing
- wave assumption
30- Quantization of e- energy levels by standing
- wave assumption
- Derived a mathematical description for e-s as
- 3-d standing waves in atoms
31- Quantization of e- energy levels by standing
- wave assumption
- Derived a mathematical description for e-s as
- 3-d standing waves in atoms
- H? E?
32- Quantization of e- energy levels by standing
- wave assumption
- Derived a mathematical description for e-s as
- 3-d standing waves in atoms
- H? E?
- ?, the wave function, is a function spatial
- position of e-
- H, is a mathematical function which allows the
- calculation of the e- energy (Hamiltonian
- operator) and
- E, is the total energy of the electron
33Fe atoms (blue) on a Cu crystal. Quantum energy
states of Cu electrons trapped inside the
circular Fe corral are imaged by STM as
waveforms (in red).
341
2
4
3
Making a quantum corral image sequence shows how
the scientists built the circular corral of iron
atoms in order to trap surface electron energy
states. (Courtesy of IBM)
35Compare the energies of photons emitted by
two radio stations, operating at 92 MHz (FM) and
1500 kHz (MW)?
36Compare the energies of photons emitted by
two radio stations, operating at 92 MHz (FM) and
1500 kHz (MW)? E hn 92 MHz 92 x 106 Hz gt
E 6.626 x 10-34 x 92 x 106 6.1 x 10-26J
37Compare the energies of photons emitted by
two radio stations, operating at 92 MHz (FM) and
1500 kHz (MW)? E hn 92 MHz 2 x 106 Hz gt
E 6.626 x 10-34 x 2 x 106 1.33 x
10-27J 1500 kHz E 6.626 x 10-34 x 1.5 x 103
9.94 x 10-31J
38The energy from radiation can be used to break
chemical bonds. Energy of at least 495 kJ mol-1
is required to break the oxygen-oxygen bond. What
is the wavelength of this radiation?
39The energy from radiation can be used to break
chemical bonds. Energy of at least 495 kJ mol-1
is required to break the oxygen-oxygen bond. What
is the wavelength of this radiation? E
hc/l 495 x 103 J mol-1 ? 495 x 103 J mol-1/NA
8.22 x 10-19 J per molecule
40- The energy from radiation can be used to break
chemical bonds. Energy of at least 495 kJ mol-1
is required to break the oxygen-oxygen bond. What
is the wavelength of this radiation? - E hc/l
- 495 x 103 J mol-1 ? 495 x 103 J mol-1/NA
- 8.22 x 10-19 J per molecule
- 6.626 x 10-34 x 3 x 108/ 8.22 x 10-19
- 242 x 10-9 m 242 nm.
41 Autumn 1999 2. The best available balances can
weigh amounts as small as 10-5 g. If you were to
count out water molecules at the rate of one per
second, how long would it take to count a pile
of molecules large enough to weigh 10-5 g?
42 Autumn 1999 2. The best available balances can
weigh amounts as small as 10-5 g. If you were to
count out water molecules at the rate of one per
second, how long would it take to count a pile
of molecules large enough to weigh 10-5 g? 1
molecule H2O has mass of 16 2 18 amu 1 mole
H2O has mass of 18 g ? 6.022 x 1023 molecules
43 Autumn 1999 2. The best available balances can
weigh amounts as small as 10-5 g. If you were to
count out water molecules at the rate of one per
second, how long would it take to count a pile
of molecules large enough to weigh 10-5 g? 1
molecule H2O has mass of 16 2 18 amu 1 mole
H2O has mass of 18 g ? 6.022 x 1023
molecules 10-5 g ? 10-5/18 moles 5.6 x 10-7
moles
44 Autumn 1999 2. The best available balances can
weigh amounts as small as 10-5 g. If you were to
count out water molecules at the rate of one per
second, how long would it take to count a pile
of molecules large enough to weigh 10-5 g? 1
molecule H2O has mass of 16 2 18 amu 1 mole
H2O has mass of 18 g ? 6.022 x 1023
molecules 10-5 g ? 10-5/18 moles 5.6 x 10-7
moles ? 5.6 x 10-7 x 6.022 x 1023 molecules
3.35 x 1017 molecules
45 Autumn 1999 2. The best available balances can
weigh amounts as small as 10-5 g. If you were to
count out water molecules at the rate of one per
second, how long would it take to count a pile
of molecules large enough to weigh 10-5 g? 1
molecule H2O has mass of 16 2 18 amu 1 mole
H2O has mass of 18 g ? 6.022 x 1023
molecules 10-5 g ? 10-5/18 moles 5.6 x 10-7
moles ? 5.6 x 10-7 x 6.022 x 1023 molecules
3.35 x 1017 molecules 3.35 x 1017 s
46 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light.
47 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light. E
hn hc/l 6.626 x 10-34 x 3 x 108 /407 x 10-9
J s m s-1 m-1
48 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light. E
hn hc/l 6.626 x 10-34 x 3 x 108 /407 x 10-9
J s m s-1 m-1 4.88 x 10-19 J
49 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light. E
hn hc/l 6.626 x 10-34 x 3 x 108 /407 x 10-9
J s m s-1 m-1 4.88 x 10-19 J 1 millimole
10-3 mole 6.022 x 1020 photons
50 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light. E
hn hc/l 6.626 x 10-34 x 3 x 108 /407 x 10-9
J s m s-1 m-1 4.88 x 10-19 J 1 millimole
10-3 mole 6.022 x 1020 photons energy of 1
millimole of photons ? 6.022 x 1020x 4.88 x 10-19
J
51 Autumn 2000 13. Hemoglobin absorbs light of
wavelength 407 nm. Calculate the energy (in J)
of one millimole of photons of this light. E
hn hc/l 6.626 x 10-34 x 3 x 108 /407 x 10-9
J s m s-1 m-1 4.88 x 10-19 J 1 millimole
10-3 mole 6.022 x 1020 photons energy of 1
millimole of photons ? 6.022 x 1020x 4.88 x 10-19
J 294 J
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53Line spectrum of sodium
400 550 700 nm
Line spectrum of hydrogen
400 550 700 nm
Balmer-Rydberg equation 1/l R1/m2 -
1/n2 m 1, n gt 1
54- Quantization of e- energy levels by standing
- wave assumption
- Derived a mathematical description for e-s as
- 3-d standing waves in atoms
- H? E?
- ?, the wave function, is a function spatial
- position of e-
- H, is a mathematical function which allows the
- calculation of the e- energy (Hamiltonian
- operator) and
- E, is the total energy of the electron
55What is ?2? " Amplitude probability function
" e.g. for a linear standing wave Amplitude
sin x , where x is distance along the wave
56What is ?2? " Amplitude probability function
" e.g. for a linear standing wave Amplitude
sin x , where x is distance along the wave Why
amplitude probability function ? Heisenberg
Uncertainty Principle (1927)
57What is ?2? " Amplitude probability function
" e.g. for a linear standing wave Amplitude
sin x , where x is distance along the wave Why
amplitude probability function ? Heisenberg
Uncertainty Principle (1927) "There is a
fundamental limit to how precisely we can
simultaneously determine both the position (x)
and the momentum (m.v) of a particle"
58What is ?2? " Amplitude probability function
" e.g. for a linear standing wave Amplitude
sin x , where x is distance along the wave Why
amplitude probability function ? Heisenberg
Uncertainty Principle (1927) "There is a
fundamental limit to how precisely we can
simultaneously determine both the position (x)
and the momentum (m.v) of a particle" ?x.m?v gt
h/4? i.e. ?x.m?v gt 5.272(10-35) m2 kg s-1
59Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg).
60Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg). (a) ?x gt 5.272(10-35)/9.11(10-31)(
0.1) 5.79(10-4) m
61Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg). (a) ?x gt 5.272(10-35)/9.11(10-31)(
0.1) 5.79(10-4) m ?x of e- is big c.f. size
of an atom (2(10-10m))!
62Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg). (a) ?x gt 5.272(10-35)/9.11(10-31)(
0.1) 5.79(10-4) m ?x of e- is big c.f. size
of an atom (2(10-10m))! (b) ?x gt
5.272(10-35)/0.4(0.1) 1.31(10-33) m
63Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg). (a) ?x gt 5.272(10-35)/9.11(10-31)(
0.1) 5.79(10-4) m ?x of e- is big c.f. size
of an atom (2(10-10m))! (b) ?x gt
5.272(10-35)/0.4(0.1) 1.31(10-33) m ?x of
ball is v. small c.f. its size (0.3m)
64Example For a ?v of 0.1m/s, calculate ?x for (a)
an electron (m9.11 x 10-31kg) and (b) a football
(m0.4kg). (a) ?x gt 5.272(10-35)/9.11(10-31)(
0.1) 5.79(10-4) m ?x of e- is big c.f. size
of an atom (2(10-10m))! (b) ?x gt
5.272(10-35)/0.4(0.1) 1.31(10-33) m ?x of
ball is v. small c.f. its size (0.3m) Conclusion
H.U.P. only important for v. small particles
such as e-
65Major implication of H.U.P. It is not possible
to find out the exact position velocity of an
e- in an atom
66Major implication of H.U.P. It is not possible
to find out the exact position velocity of an
e- in an atom Can only define the shapes of
electron "clouds" in terms of probability of
finding electron at a given spot
67Major implication of H.U.P. It is not possible
to find out the exact position velocity of an
e- in an atom Can only define the shapes of
electron "clouds" in terms of probability of
finding electron at a given spot Probability or
e- density is given by the term ?2
68Major implication of H.U.P. It is not possible
to find out the exact position velocity of an
e- in an atom Can only define the shapes of
electron "clouds" in terms of probability of
finding electron at a given spot Probability or
e- density is given by the term ?2 Probability
maps for a particular wavefunction are called
electron orbitals
69Major implication of H.U.P. It is not possible
to find out the exact position velocity of an
e- in an atom Can only define the shapes of
electron "clouds" in terms of probability of
finding electron at a given spot Probability or
e- density is given by the term ?2 Probability
maps for a particular wavefunction are called
electron orbitals Orbitals usually drawn as
shape which encloses 90 of the total e- density
for that wavefunction
70- Characterisation of Electron Orbitals
- Many different solutions to the Schroedinger
- Equation for an electron in an atom.
71- Characterisation of Electron Orbitals
- Many different solutions to the Schroedinger
- Equation for an electron in an atom.
- Each solution represented by an orbital
72- Characterisation of Electron Orbitals
- Many different solutions to the Schroedinger
- Equation for an electron in an atom.
- Each solution represented by an orbital
- A series of quantum numbers are used to
- describe the various properties of an orbital
73- Characterisation of Electron Orbitals
- Many different solutions to the Schroedinger
- Equation for an electron in an atom.
- Each solution represented by an orbital
- A series of quantum numbers are used to
- describe the various properties of an orbital
- Principle quantum number (n) has integral values
- (1,2,3, etc.) describes orbital size and energy
74- Characterisation of Electron Orbitals
- Many different solutions to the Schroedinger
- Equation for an electron in an atom.
- Each solution represented by an orbital
- A series of quantum numbers are used to
- describe the various properties of an orbital
- Principle quantum number (n) has integral values
- (1,2,3, etc.) describes orbital size and energy
- Angular momentum quantum number (l) has
- integral values from 0 to n-1 for each value of n
- describes the orbital shape
75Magnetic quantum number (ml) has integral
values between l and -l, including zero
describes the orientation in space of the orbital
relative to the other orbitals in the atom
76Magnetic quantum number (ml) has integral
values between l and -l, including zero
describes the orientation in space of the orbital
relative to the other orbitals in the atom
Spin quantum number (ms) is either 1/2 or -1/2
for a given e- describes the direction of spin
of the e- on its axis
77Magnetic quantum number (ml) has integral
values between l and -l, including zero
describes the orientation in space of the orbital
relative to the other orbitals in the atom
Spin quantum number (ms) is either 1/2 or -1/2
for a given e- describes the direction of spin
of the e- on its axis Pauli Exclusion Principle
"no two electrons in an atom can have the same
set of quantum numbers", or, only two electrons
(of opposite spin) per orbital.
78Some Quantum Nos. Orbitals in the H Atom
Sub-shell No. of n l
Designation ml Orbitals No. of e-
79Some Quantum Nos. Orbitals in the H Atom
Sub-shell No. of n l
Designation ml Orbitals No. of e- 1
0 1s 0 1 2
80Some Quantum Nos. Orbitals in the H Atom
Sub-shell No. of n l
Designation ml Orbitals No. of e- 1
0 1s 0 1 2 2
0 2s 0 1 2 1 2p -1, 0,
1 3 6
81Some Quantum Nos. Orbitals in the H Atom
Sub-shell No. of n l
Designation ml Orbitals No. of e- 1
0 1s 0 1 2 2
0 2s 0 1 2 1 2p -1, 0,
1 3 6 3 0 3s 0 1 2 1
3p -1, 0, 1 3 6 2 3d -2, -1, 0,
1, 2 5 10 4...etc...
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83Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms 1/2
84Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid
85Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid (c) n 2, l 0, ml
-1, ms 1/2 invalid ml -l to l
86Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid (c) n 2, l 0, ml
-1, ms 1/2 invalid ml -l to l (d) n 3,
l 1, ml 0, ms 0 invalid ms -1/2 or
1/2
87Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid (c) n 2, l 0, ml
-1, ms 1/2 invalid ml -l to l (d) n 3,
l 1, ml 0, ms 0 invalid ms -1/2 or
1/2 Write a valid set of quantum numbers for
each of the following sub-shells (a) 2s n
2, l 0, ml 0, ms 1/2
88Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid (c) n 2, l 0, ml
-1, ms 1/2 invalid ml -l to l (d) n 3,
l 1, ml 0, ms 0 invalid ms -1/2 or
1/2 Write a valid set of quantum numbers for
each of the following sub-shells (a) 2s n
2, l 0, ml 0, ms 1/2 (b) 2p n 2, l
1, ml -1, ms 1/2
89Which of the following are valid sets of quantum
numbers? (a) n 1, l 1, ml 0, ms
1/2 invalid l 0 to n-1 (b) n 2, l 1, ml
0, ms 1/2 valid (c) n 2, l 0, ml
-1, ms 1/2 invalid ml -l to l (d) n 3,
l 1, ml 0, ms 0 invalid ms -1/2 or
1/2 Write a valid set of quantum numbers for
each of the following sub-shells (a) 2s n
2, l 0, ml 0, ms 1/2 (b) 2p n 2, l
1, ml -1, ms 1/2 (c) 3d n 3, l 2, ml
-2, ms 1/2
90Principal quantum number specifies energy of e-
91Principal quantum number specifies energy of
e- For hydrogen, Schroedinger showed that E
- hR/n2 where R is the Rydberg constant 3.29 X
1015 Hz
92- Principal quantum number specifies energy of e-
- For hydrogen, Schroedinger showed that
- E - hR/n2
- where R is the Rydberg constant 3.29 X 1015 Hz
- Can calculate from theory the hydrogen spectrum
93- Principal quantum number specifies energy of e-
- For hydrogen, Schroedinger showed that
- E - hR/n2
- where R is the Rydberg constant 3.29 X 1015 Hz
- Can calculate from theory the hydrogen spectrum
- For transition from n 3 to n 2 state
94- Principal quantum number specifies energy of e-
- For hydrogen, Schroedinger showed that
- E - hR/n2
- where R is the Rydberg constant 3.29 X 1015 Hz
- Can calculate from theory the hydrogen spectrum
- For transition from n 3 to n 2 state
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4
95- Principal quantum number specifies energy of e-
- For hydrogen, Schroedinger showed that
- E - hR/n2
- where R is the Rydberg constant 3.29 X 1015 Hz
- Can calculate from theory the hydrogen spectrum
- For transition from n 3 to n 2 state
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4 - h x 4.57 x 1014 Hz hn and n 4.57 x 1014 Hz
96- Principal quantum number specifies energy of e-
- For hydrogen, Schroedinger showed that
- E - hR/n2
- where R is the Rydberg constant 3.29 X 1015 Hz
- Can calculate from theory the hydrogen spectrum
- for transition from n 3 to n 2 state
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4 - h x 4.57 x 1014 Hz hn and n 4.57 x 1014 Hz
- l c/n 3 x 108 ms-1/ 4.57 x 1014 s-1 656 nm
97Line spectrum of hydrogen
400 550 700 nm
98- For hydrogen, E - hR/n2
- If H atom acquires enough energy e- can be
promoted from - one level to the next
-
99- For hydrogen, E - hR/n2
- If H atom acquires enough energy e- can be
promoted from - one level to the next
-
- To promote an e- from n 1 to n 2 level
- DE -hR1/22 - 1/12 - h x 3.29 x 10151/4 -
1 1.63 x 10-18 J
100- For hydrogen, E - hR/n2
- If H atom acquires enough energy e- can be
promoted from - one level to the next
-
- To promote an e- from n 1 to n 2 level
- DE -hR1/22 - 1/12 - h x 3.29 x 10151/4 -
1 1.63 x 10-18 J -
- To promote an e- from n 2 to n 3 level
-
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4 3.03 x 10-19 J
101- For hydrogen, E - hR/n2
- If H atom acquires enough energy e- can be
promoted from - one level to the next
-
- To promote an e- from n 1 to n 2 level
- DE -hR1/22 - 1/12 - h x 3.29 x 10151/4 -
1 1.63 x 10-18 J -
- To promote an e- from n 2 to n 3 level
-
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4 3.03 x 10-19 J -
- To remove e- (ionise) from the atom
-
- DE -hR1/?2 - 1/12 hR 2.18 x 10-18 J
-
102- For hydrogen, E - hR/n2
- If H atom acquires enough energy e- can be
promoted from - one level to the next
-
- To promote an e- from n 1 to n 2 level
- DE -hR1/22 - 1/12 - h x 3.29 x 10151/4 -
1 1.63 x 10-18 J -
- To promote an e- from n 2 to n 3 level
-
- DE -hR1/32 - 1/22 - h x 3.29 x 10151/9 -
1/4 3.03 x 10-19 J -
- To remove e- (ionise) from the atom
-
- DE -hR1/?2 - 1/12 hR 2.18 x 10-18 J
-
- To ionise one mole of hydrogen atoms
-
103Principle quantum number n 1, 2, 3,..
describes orbital size and
energy Angular momentum quantum number l 0 to
n-1 describes orbital shape
Magnetic quantum number ml l, l-1-l
describes orientation in space
of the orbital relative to the other
orbitals in the atom
Spin quantum number ms 1/2 or -1/2
describes the direction of spin of
the e- on its axis Pauli Exclusion Principle
"no two electrons in an atom can have the same
set of quantum numbers", or, only two electrons
(of opposite spin) per orbital.
104Write a valid set of quantum numbers for each of
the following sub-shells (a) 2 s n 2, l
0, ml 0, ms - 1/2 n 2, l 0, ml 0, ms
1/2 2 combinations
105Write a valid set of quantum numbers for each of
the following sub-shells (a) 2 s n 2, l
0, ml 0, ms - 1/2 n 2, l 0, ml 0, ms
1/2 2 combinations (b) 2 p n 2, l 1,
ml -1, ms - 1/2 n 2, l 1, ml -1, 0
or 1, ms 1/2 6 combinations
106Write a valid set of quantum numbers for each of
the following sub-shells (a) 2 s n 2, l
0, ml 0, ms - 1/2 n 2, l 0, ml 0, ms
1/2 2 combinations (b) 2 p n 2, l 1,
ml -1, ms - 1/2 n 2, l 1, ml -1, 0
or 1, ms 1/2 6 combinations (c) 3 d n
3, l 2, ml -2, ms - 1/2 n 3, l 2, ml
-2, -1, 0, 1, or 2, ms 1/2 10 combinations
107How many orbitals in a subshell? l 0,
1s 1 l 1, px, py, pz 3 l 2,
dxy,, dxz,, dyz ,, dx2-y2, dz2 5
108How many orbitals in a subshell? l 0,
1s 1 l 1, px, py, pz 3 l 2,
dxy,, dxz,, dyz ,, dx2-y2, dz2 5 2 l 1
orbitals per subshell
109How many orbitals in a subshell? l 0,
1s 1 l 1, px, py, pz 3 l 2,
dxy,, dxz,, dyz ,, dx2-y2, dz2 5 2 l 1
orbitals per subshell How many orbitals in a
shell? n 1, 1s 1 n 2, 2s, 2px, 2py,
2pz 4 n 3, 3s, 3px, 3py, 3pz, 3dxy,,
3dxz,, 3dyz ,, 3dx2-y2, 3dz2 9
110How many orbitals in a subshell? l 0,
1s 1 l 1, px, py, pz 3 l 2,
dxy,, dxz,, dyz ,, dx2-y2, dz2 5 2 l 1
orbitals per subshell How many orbitals in a
shell? n 1, 1s 1 n 2, 2s, 2px, 2py,
2pz 4 n 3, 3s, 3px, 3py, 3pz, 3dxy,,
3dxz,, 3dyz ,, 3dx2-y2, 3dz2 9 n2 orbitals per
principal quantum level
111- Hydrogen atom-
- all orbitals within a shell have the same energy
- electrostatic interaction between e- and proton
112- Hydrogen atom-
- all orbitals within a shell have the same energy
- electrostatic interaction between e- and proton
- Multi-electron atoms-
- the energy level of an orbital depends not only
on the - shell but also on the subshell
- electrostatic interactions between e- and proton
and other e-
113- Quantum Mechanical Model for Multi-electron Atoms
- electron repulsions
- He He e- E 2372 kJ mol-1
- He has two electron which repel each other
-
114- Quantum Mechanical Model for Multi-electron Atoms
- electron repulsions
- He He e- E 2372 kJ mol-1
- He has two electron which repel each other
- He He2 e- E 5248 kJ mol-1
- He has one electron, no electrostatic repulsion
115- Quantum Mechanical Model for Multi-electron Atoms
- electron repulsions
- He He e- E 2372 kJ mol-1
- He has two electron which repel each other
- He He2 e- E 5248 kJ mol-1
- He has one electron, no electrostatic repulsion
- Less energy required to remove e- from He than
from He - Shielding of outer orbital electrons from ve
nuclear - charge by inner orbital electrons
- gt outer orbital electrons have higher energies
116- Quantum Mechanical Model for Multi-electron Atoms
- Penetration effect of outer orbitals within
inner orbitals - ns gt np gt nd
- For a given n, energy of s lt energy of p lt energy
of d
117- Quantum Mechanical Model for Multi-electron Atoms
- Penetration effect of outer orbitals within
inner orbitals - ns gt np gt nd
- For a given n, energy of s lt energy of p lt energy
of d - Effective nuclear charge (Zeff) experienced by
an electron - is used to quantify these additional effects.
118- Quantum Mechanical Model for Multi-electron Atoms
- Penetration effect of outer orbitals within
inner orbitals - ns gt np gt nd
- For a given n, energy of s lt energy of p lt energy
of d - Effective nuclear charge (Zeff) experienced by
an electron - is used to quantify these additional effects.
- Example Sodium, Na, Z 11
- Na 1s e- Zeff 10.3 shielding
effect is small - Na 3s e- Zeff 1.84 large
shielding effect by inner e-s - penetration effect counteracts
- this to a small extent
119Orbital Energies
3dxy
3dxz
3dyz
3dx2-y2
3dz2
3px
3py
3pz
3s
Energy
2px
2py
2pz
2s
1s
120Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle
121Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle)
122Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle) 3. Try to attain maximum
number of unpaired e- spins in a given
sub-shell (Hund's Rule)
123Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle) 3. Try to attain maximum
number of unpaired e- spins in a given
sub-shell (Hund's Rule)
H (Z 1) 1s1
2s 2p
Energy
1s
124Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle) 3. Try to attain maximum
number of unpaired e- spins in a given
sub-shell (Hund's Rule)
N (Z 7) 1s2, 2s2, 2p3,
2p
2s
Energy
1s
125Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle) 3. Try to attain maximum
number of unpaired e- spins in a given
sub-shell (Hund's Rule)
B (Z 5) 1s2, 2s2, 2p1
2p
2s
Energy
1s
126Electronic Configuration Filling-in of Atomic
Orbitals Rules 1. Pauli Principle 2. Fill
in e-'s from lowest energy orbital upwards
(Aufbau Principle) 3. Try to attain maximum
number of unpaired e- spins in a given
sub-shell (Hund's Rule)
F (Z 9) 1s2, 2s2, 2p5
2p
2s
Energy
1s
127Hydrogen 2s 3s 4s 1s
2p 3p 4p 3d 4d 4f Multi-electron
atoms 1s 2s 3s 4s 5
s 2p 3p 4p 3d 4d
128 1s 2s 2px 2py 2pz
H 1s1 He 1s2 Li 1s2, 2s1 Be 1s2,
2s2 B 1s2, 2s2, 2px1 C 1s2, 2s2, 2px1, 2py1 N
1s2, 2s2, 2px1, 2py1, 2pz1 O 1s2, 2s2,
2px2, 2py1, 2pz1 F 1s2, 2s2, 2px2, 2py2,
2pz1 Ne 1s2, 2s2, 2px2, 2py2, 2pz2
129H 1s1 He 1s2 Li He, 2s1 Be He, 2s2
130H 1s1 He 1s2 Li He, 2s1 Be He,
2s2 B He, 2s2, 2p1 Ne He, 2s2, 2p6 Na
He, 2s2, 2p6, 3s1 ? Ne, 3s1
131H 1s1 He 1s2 Li He, 2s1 Be He,
2s2 B He, 2s2, 2p1 Ne He, 2s2, 2p6 Na
He, 2s2, 2p6, 3s1 ? Ne, 3s1 Mg He, 2s2,
2p6, 3s2 ? Ne, 3s2 Al Ne, 3s2, 3p1 Si
Ne, 3s2, 3p2
132H 1s1 He 1s2 Li He, 2s1 Be He,
2s2 B He, 2s2, 2p1 Ne He, 2s2, 2p6 Na
He, 2s2, 2p6, 3s1 ? Ne, 3s1 Mg He, 2s2,
2p6, 3s2 ? Ne, 3s2 Al Ne, 3s2, 3p1 Si
Ne, 3s2, 3p2 P Ne, 3s2, 3p3 S Ne, 3s2,
3p4 Cl Ne, 3s2, 3p5 Ar Ne, 3s2, 3p6
133- H 1s1 He 1s2
- Li He, 2s1 Be He, 2s2
- B He, 2s2, 2p1 Ne He, 2s2, 2p6
- Na He, 2s2, 2p6, 3s1 ? Ne, 3s1
- Mg He, 2s2, 2p6, 3s2 ? Ne, 3s2
- Al Ne, 3s2, 3p1 Si Ne, 3s2, 3p2
- P Ne, 3s2, 3p3 S Ne, 3s2, 3p4
- Cl Ne, 3s2, 3p5 Ar Ne, 3s2, 3p6
- outermost shell - valence shell
- most loosely held electron and are the most
important - in determining an elements properties
134K Ar, 4s1 Ca Ar, 4s2 Sc Ar, 4s2, 3d1
Ca Ar, 4s2, 3d2
135K Ar, 4s1 Ca Ar, 4s2 Sc Ar, 4s2, 3d1
Ca Ar, 4s2, 3d2 Zn Ar, 4s2, 3d10 Ga
Ar, 4s2, 3d10, 3p1 Kr Ar, 4s2, 3d10, 3p6
136K Ar, 4s1 Ca Ar, 4s2 Sc Ar, 4s2, 3d1
Ca Ar, 4s2, 3d2 Zn Ar, 4s2, 3d10 Ga
Ar, 4s2, 3d10, 3p1 Kr Ar, 4s2, 3d10,
3p6 Anomalous electron configurations d5 and
d10 are lower in energy than expected Cr
Ar, 4s1, 3d5 not Ar, 4s2, 3d4
Cu Ar, 4s1, 3d10 not Ar, 4s2, 3d9
137Electron Configuration of Ions Electrons lost
from the highest energy occupied orbital of the
donor and placed into the lowest unoccupied
orbital of the acceptor (placed according to the
Aufbau principle)
138Electron Configuration of Ions Electrons lost
from the highest energy occupied orbital of the
donor and placed into the lowest unoccupied
orbital of the acceptor (placed according to the
Aufbau principle) Examples Na Ne,
3s1 Na Ne e- Cl Ne, 3s2, 3p5 e-
Cl- Ne, 3s2, 3p6 Mg Ne, 3s2 Mg2
Ne O He, 2s2, 2p4 O2- He, 2s2, 2p6
139- Modern Theories of the Atom - Summary
- Wave-particle duality of light and matter
- Bohr theory
- Quantum (wave) mechanical model
- Orbital shapes and energies
- Quantum numbers
- Electronic configuration in atoms